设f(x)=x3+4x2+11x+7,则f(x+1)= ()A.x3+7x2+22x+23 B.x3—7x2+22x+23C.x3+7x2—22x+23D.x3—7x2—22x+23
设f(x)=x3+4x2+11x+7,则f(x+1)= ()
A.x3+7x2+22x+23
B.x3—7x2+22x+23
C.x3+7x2—22x+23
D.x3—7x2—22x+23
B.x3—7x2+22x+23
C.x3+7x2—22x+23
D.x3—7x2—22x+23
参考解析
解析:
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