s=‘I want to change’,s[-4:]的值是()A、toB、wantC、egnaD、ange

s=‘I want to change’,s[-4:]的值是()

  • A、to
  • B、want
  • C、egna
  • D、ange

相关考题:

—____________________?—I want to be a scientist and it ‟s also my childhood dream. A. What ‟s your jobB. What ‟re you doingC. Are you a scientistD. What ‟s your dream for the future

已知程序段:s=0For i=1 To 10 Step 2s=s+1i=i*2Next i当循环结束后,变量i、s的值各为A.10,4B.11,3C.22,3D.16,4

听力原文:M: Hello, can I do anything for you?W: Yes, I need to change foreign moneys. Could you help me change some Canadian dollars in traveler's cheques issued by Royal Bank of Canada?Q: What kind of foreign currencies does the speaker want to exchange?(17)A.Canadian dollars.B.British Pounds.C.U.S. dollars.D.H.K. dollars.

—Here’s my car.Do you want a ride?—() A.That’s possibleB.Not at allC.That’s very kind of you.ThanksD.I think so

执行下面的程序段后,i的值为______,s的值为 ______。s=2For i=2 To 9 Step 0.8s=s +1Next i

" It' s cold in this room.” “_______ the heating?"A、Do you want to turnB、Turn onC、Shall I turn onD、Will I turn on

已知程序段: S=0 FOR I = 1 T() 10 STEP 2 S=S+1 I=I.2 NEXT I当循环结束后,变量I和s的值分别为( )。A.10和2B.11和5C.16和4D.22和3

已知程序段: s=0 For i=1 to 10 step2 s=s+l i=i*2 Next i当循环结束后,变量i、s值分别为( )。A.22、3B.11、4C.10、5D.16、6

已知程序段:s=0For i=1 To 10 Step 2s=s+1i=i*2Next i当循环结束后,变量i的值为______,变量s的值为______。A.10,4B.11,3C.22,3D.16,4

执行如下程序,最后S的显示值为 SET TALK OFF S=0 i=5 X=11 DO WHILE S<=x S=S +i I = I +l ENDDO ?s SET TALK ONA.5B.11C.18D.26

已知程序段: s=0 For i=1 To 10 Step 2 s=s+1 i=i*2 Next i 当循环结束后,变量i的值为______,变量s的值为______。A.10,4B.11,3C.22,3D.16,4

以下程序中,函数 sumColumM的功能是:求出M行N列二维数组每列元素中的最小值,并计算它们的和值。和值通过形参传回主函数输出。请填空。define M 2define N 4void SumColumMin(int a[M][N],int *sum){ int i,j,k,s=0;for(i=0;i〈N;i++){ k=0;for(j=1;j<M;j++)if(a[k][i]>a[j][i])k=j;s+=【 】;}【 】 =s;}main( ){ int x[M][N]={3,2,5,1,4,1,8,3},s;SumColumMin(【 】);printf("%d\n",s);}

请完成下列Java程序:计算下列级数之和,直到该项之绝对值小于0.001为止。S=1/1! -1/2! +1/3! -1/4! +注意:请勿改动main()主方法和其他已有的语句内容,仅在横线处填入适当的语句。程序运行结果如下:i=1 s=1.0i=2 s=0.5i=3 s=0.6666666666666666i=4 s=0.625i=5 s=0.6333333333333333i=6 s=0.6319444444444444public class exl3_2{public static void main(Stfing[] args){double s=0.0,sign=-1.0,t,f=1.0;for(int i=1;;i++){f=f*i;__________;t=sign/f;if(__________)break;s=s+t;System.out.prinfln("i="+i+"s="+s);}}}

已知程序段: s=0 For i=1 To 10 Step 2 s=s+1 j=j*2 Next i 当循环结束后,变量i的值为( ),变量s的值为( )。A.10,4B.11,3C.22,3D.16,4

执行下面的程序段后,变量S的值为【 】。S=5For i=2.6 To 4.9 Step 0.5S=S +iNext i

已知程序段: s = 0 For i = 1 To 10 Step 2 s = s + 1 i = i * 2 Next i 当循环结束后,变量i和s的值分别为______A.10 4B.11 3C.22 3D.16 4

已知程序段: S=0 For i=1 To 10 Step 2 s=s+1 i=i*2 Nexti 当循环结束后,变量i的值为______,变量s的值为______。A.10,4B.11,3C.22,3D.16,4

程序段如下; s=0 For I=5 to -1 step -2 S=s+I Next I Print I 语句S=S+I执行的次数和最后I的值分别为( )。A.3,-1B.4,-1C.4,-3D.0, 5

以下程序段运行后s的值是( )。 int a[3][3]={1,2,3,4,5,1,2,3,4};int i,j,s=1;for(i=0;i3;i++)for(j=i+1;j3;j++)s+=a[i][j];4A:6B:120C:7D:240

若变量已正确定义,以下不能正确计算1+2+3+4+5的程序段是()。A、i=1;s=1;do{s=s+i;i++;}while(i5);B、i=0;s=0;do{i++;s=s+i;}while(i5);C、i=1;s=0;do{s=s+i;i++;}while(i6);D、i=1;s=0;do{s=s+i;i++;}while(i=5);

以下程序段执行后,整型变量s的值为()。  s=4  For i=1 To 4 s=s-1 Next iA、0B、-1C、4D、5

下面是一段关于计算变量s的算法: ①变量s的初值是0  ②变量i从1起循环到n,此时变量s的值由下面的式子表达式计算 ③s=s+(-1)*i ④输出变量s的值 这个计算s值的算法中,s的代数式表示是()。A、1-2+3-4+…+(-1)n*(n-1)B、1-2+3-4+…+(-1)n-1*nC、1+2+3+4+...+(n-1)+nD、-1-2-3-4-...-n

以下程序段执行后,整型变量s的值为()。  s=1  For i=1 To 4 s=s*i Next iA、1B、4C、24D、36

单选题以下程序段的输出结果是() int a[4][4]={{1},{2,3},{4,5,6},{7,8,9,10}},s=0,i;for(i=0;i4;i++) s+=a[i][i]+a[i][3-i]; printf("%d/n",s); 1+3+5+6+7+10A20B32C12D随机值

单选题The central idea of this passage is _____.Aman’s mental abilities change from season to seasonBman’s intelligence varies from place to placeCman should take long vacation in summerDif you want to do creative thinking, go to a cool place

单选题以下程序段执行后,整型变量s的值为()。  s=1  For i=1 To 4 s=s*i Next iA1B4C24D36

单选题以下程序段执行后,整型变量s的值为()。  s=4  For i=1 To 4 s=s-1 Next iA0B-1C4D5