单选题Which of the following choices could be equal to set Z ifX = {2, 5, 6, 7, 9} and Y = {2, 5, 7}X ∪ Y ∪ Z = {1, 2, 3, 4, 5, 6, 7, 8, 9}X ∩ Z = {2, 6}Y ∩ Z = {2}AZ= {1, 4, 8}BZ= {1, 3, 8}CZ= {1, 3, 4, 8}DZ= {1, 2, 3, 4, 6, 8}EZ= {1, 2, 3, 5, 6, 8}
单选题
Which of the following choices could be equal to set Z ifX = {2, 5, 6, 7, 9} and Y = {2, 5, 7}X ∪ Y ∪ Z = {1, 2, 3, 4, 5, 6, 7, 8, 9}X ∩ Z = {2, 6}Y ∩ Z = {2}
A
Z= {1, 4, 8}
B
Z= {1, 3, 8}
C
Z= {1, 3, 4, 8}
D
Z= {1, 2, 3, 4, 6, 8}
E
Z= {1, 2, 3, 5, 6, 8}
参考解析
解析：
We know that: X = {2, 5, 6, 7, 9} and Y = {2, 5, 7}, X ∪ Y ∪ Z = {1, 2, 3, 4, 5, 6, 7, 8, 9}. This tells us that Z must contain {1, 3, 4, 8} because these elements are in the union of X, Y, and Z but not in set X and not in set Y.
We also know that: X ∩ Z = {2, 6}, Y ∩ Z = {2}. This tells us that Z must also contain {2, 6}. Only choice D contains all these elements. Z = {1, 2, 3, 4, 6, 8}
We know that: X = {2, 5, 6, 7, 9} and Y = {2, 5, 7}, X ∪ Y ∪ Z = {1, 2, 3, 4, 5, 6, 7, 8, 9}. This tells us that Z must contain {1, 3, 4, 8} because these elements are in the union of X, Y, and Z but not in set X and not in set Y.
We also know that: X ∩ Z = {2, 6}, Y ∩ Z = {2}. This tells us that Z must also contain {2, 6}. Only choice D contains all these elements. Z = {1, 2, 3, 4, 6, 8}
相关考题：
化简下列各式：（1）5x4+3x2y-10-3x2+x-1;（2）p²+3pq+6-8p²+pq ;（3）（7y-3z）-（8y-5z）;（4）-(a5-6b)-(-7+3b)（5）2（2a²+9b）+3（-5a²-4b）；（6）-3（2x²-xy）+4（x²+xy-6）.
阅读以下说明和X86汇编语言代码，将应填入(n)处的字句写在答题纸的对应栏内。[说明]设有数组X和Y。X数组中有X1，X2、…、X10十个数，Y中有Y1、Y2、…、 Y10十个数。编制程序计算：Z1=X1+Y1 Z2=X2+Y2 Z3=X3-Y3 Z4=X4-Y4Z5=X5-Y5 Z6=X6+Y6 Z7=X7-Y7 Z8=X8-Y8Z9=X9+Y9 Z10=X10+Y10设置一个10位的标志尺：LOGIC_RULE，若它的每一位决定了当前按顺序该做加法(该位为0)或减法(该位为1)操作，则由上列等式可知LOGIC RULE中的低10位应是(1)。[汇编程序代码]datarea segment ;define data segmentx dw x1,x2,x3,x4,x5,x6,x7,x8,x9,x10y dw y1,y2,y3,y4,y5,y6,y7,y8,y8,y10z dw z1,z2,z3,z4,z5,z6,z7,z8,z9,z10logic_ruledw (2) ;LOGIC_RULE initializedatarea endsprogram segment ;define code segmentmain proc farassume cs：program, ds:datareastart： ;starting execution address(3) ;save old data segmentsub ax, ax ;put zero in AXpush ax ;save it on stack;set DS register to current data segmentmov ax,datareamov ds,ax;MAIN PART OF PROGRAM GOES HEREmov bx,0mov ex,10mov dx,logic_rulenext:mov ax,x[bx]shr dx,1jc subtract(4)jmp short resultsubtract:sub ax, y [bx]result:(5) ;result=＞Znadd bx,2loop nextret ;return to DOSmain endp;end of main part of programprogram ends;end of code segmentend start ;end of assembly附：指令及寄存器说明。MOV 传送字或字节PUSH 把字压入堆栈SHR 逻辑右移JC 有进位时转移JMP 无条件转移指令SUB 减法ADD 加法LOOP CX不为零时循环JNE/JNZ 不等于时转移CMP 比较段寄存器2个：CS： 代码段寄存器DS： 数据段寄存器数据寄存器4个：AX： 累加器BX： 基址寄存器CX： 计数寄存器DX： 数据寄存器(1)00 1101 1100(2)00dch， 或00DCH，或220，或等价的二进制形式(3)push ds(4)add ax,y[bx](5)mov z[bx]，ax
以下程序运行后，单击按钮输出结果是 Private Sub Commandl_Click( ) Dim x As Integer，y As Integer，z As Integer X=4：y=2： Z=3 Call Gopd(x，x，z) Print x；X；Z Call Gopd(x，y，y) Print x；y；y End Sub Private Sub Gopd(x As Integer，y As Integer，z As Integer) X=3 * Z + 1 y=2 * z z=x + y End SubA．6 6 12 7 11 11B．8 5 10 5 11 11C．9 6 12 9 10 15D．8 10 10 5 9 10
单击按钮时，以下列程序运行后的输出结果是 Private Sub proc1(x As Integer，y As Integer，z As Integer) x=3*z y=2*z z=X+y End Sub Private Sub Command1_Click( ) Dim x As Integer，y As Integer，z As Integer x=1：y=2：z=3 Call proc1(x，x，2) Print x；x；z Call proc1(x，y，y) Print x；y；y End SubA．6 6 12 6 6 10B．9 5 10 5 10 10C．9 6 12 9 10 15D．9 5 10 5 4 10
单击按钮时，以下程序运行后的输出结果是 Private Sub Commandl_Click( ) Dim X As Integer，y As Integer，z As Integer x=1：y=2： Z=3 Call God(x，x，z) Print x；x；z Call God(x，y，y) Print X；y；y End Sub Private Sub God(x As Integer，y As Integer，z As Integer) x=3 * Z + 1 y=2 * Z z=x + y End SubA．6 6 12 7 11 11B．8 5 10 5 11 11C．9 6 12 9 10 15D．8 10 10 5 9 10
已知曲面方程为x-yZ+z2-2x+8y+6z=10，则过点(5，-2.1)的切平面方程为( )。A、2x+3y+2z=0B、2x+y+2z=lOC、x-2y+6z=15 D、x-2y+6z=0
过点(4，-1，3)且平行于直线L：(x-3)/2=y=(z-1)/5的直线方程为( ).A.(x-4)/2=(y+1)/0=(z-3)/5B.(x-4)/2=(y+1)/1=(z-3)/5C.(x+4)/2=(y-1)/0=(z+3)/5D.(x+4)/2=(y-1)/1=(z+3)/5
阅读下面程序，下列选项中，能够完成语句覆盖的测试用例是（） if（（x4）||（z7）） { k=x*y-1； j=sqrt（k）； } if（（x==8）（y5）） { j=x%y+2； } j=j%3；A、x=2，y=6，z=5B、x=6，y=6，z=5C、x=8，y=6，z=4D、x=8，y=5，z=5
单选题曲面x2＋2y2＋3z2＝21在点（1，－2，2）的法线方程为（ ）。A（x－1）/1＝（y＋2）/4＝（z－2）/6B（x－1）/1＝（y＋2）/（－4）＝（z－2）/6C（x－1）/6＝（y＋2）/（－4）＝（z－2）/1D（x－1）/1＝（y＋2）/6＝（z－2）/（－4）
单选题Which of the following choices could be equal to set Z ifX = {2, 5, 6, 7, 9} and Y = {2, 5, 7}X ∪ Y ∪ Z = {1, 2, 3, 4, 5, 6, 7, 8, 9}X ∩ Z = {2, 6}Y ∩ Z = {2}AZ= {1, 4, 8}BZ= {1, 3, 8}CZ= {1, 3, 4, 8}DZ= {1, 2, 3, 4, 6, 8}EZ= {1, 2, 3, 5, 6, 8}
单选题设平面∏位于平面x－2y＋z－2＝0和平面x－2y＋z－6＝0之间，且将二平面间的距离分成1：3，则∏之方程为（ ）。Ax－2y＋z－5＝0或x－2y＋z－3＝0Bx＋2y＋z＋8＝0Cx＋2y－4z＝0Dx－2y＋z－8＝0
单选题过点（－1，2，3）垂直于直线x/4＝y/5＝z/6且平行于平面7x＋8y＋9z＋10＝0的直线是（ ）。A（x＋1）/1＝（y－2）/（－2）＝（z－3）/1B（x＋1）/1＝（y－2）/2＝（z－3）/2C（x＋1）/（－1）＝（y－2）/（－2）＝（z－3）/1D（x－1）/1＝（y－2）/（－2）＝（z－3）/1
单选题设平面α平行于两直线x/2＝y/（－2）＝z及2x＝y＝z，且与曲面z＝x2＋y2＋1相切，则α的方程为（ ）。A4x＋2y－z＝0B4x－2y＋z＋3＝0C16x＋8y－16z＋11＝0D16x－8y＋8z－1＝0
单选题过点（4，-1，3）且平行于直线L：（x-3）/2=y=（z-1）/5的直线方程为（）.A（x-4）/2=（y+1）/0=（z-3）/5B（x-4）/2=（y+1）/1=（z-3）/5C（x+4）/2=（y-1）/0=（z+3）/5D（x+4）/2=（y-1）/1=（z+3）/5
单选题经过点（6，-3，2）且与平面4x-y+2z=8平行的平面方程是（）。A6x-3y+2z=31B4x-y+2z=31C6x-3y+2z=10D4x-y+2z=10