单选题设f1(x),f2(x)是二阶线性齐次方程y″+p(x)y′+q(x)y=0的两个特解,则c1f1(x)+c2f2(x)(c1,c2是任意常数)是该方程的通解的充要条件为(  )。Af1(x)f2′(x)-f2(x)f1′(x)=0Bf1(x)f2′(x)+f1′(x)f2(x)=0Cf1(x)f2′(x)-f1′(x)f2(x)≠0Df1′(x)f2(x)+f2(x)f1(x)≠0

单选题
设f1(x),f2(x)是二阶线性齐次方程y″+p(x)y′+q(x)y=0的两个特解,则c1f1(x)+c2f2(x)(c1,c2是任意常数)是该方程的通解的充要条件为(  )。
A

f1(x)f2′(x)-f2(x)f1′(x)=0

B

f1(x)f2′(x)+f1′(x)f2(x)=0

C

f1(x)f2′(x)-f1′(x)f2(x)≠0

D

f1′(x)f2(x)+f2(x)f1(x)≠0


参考解析

解析:
要使c1f1(x)+c2f2(x)是方程y″+p(x)y′+q(x)y=0的通解,则须满足f1(x),f2(x)线性无关,即ψ(x)=f1(x)/f2(x)≠k(k为常数)。则ψ′(x)=[f1′(x)f2(x)-f1(x)f2′(x)]/f22(x)≠0,即f1′(x)f2(x)-f1(x)f2′(x)≠0。

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