单选题34. HashMap props = new HashMap();  35. props.put(”key45”, “some value”);  36. props.put(”key12”, “some other value”);  37. props.put(”key39”, “yet another value”);  38. Set s = props.keySet();  39. // insert code here  What, inserted at line 39, will sort the keys in the props HashMap?()A Arrays.sort(s);B s = new TreeSet(s);C Collections.sort(s);D s = new SortedSet(s);

单选题
34. HashMap props = new HashMap();  35. props.put(”key45”, “some value”);  36. props.put(”key12”, “some other value”);  37. props.put(”key39”, “yet another value”);  38. Set s = props.keySet();  39. // insert code here  What, inserted at line 39, will sort the keys in the props HashMap?()
A

 Arrays.sort(s);

B

 s = new TreeSet(s);

C

 Collections.sort(s);

D

 s = new SortedSet(s);


参考解析

解析: 暂无解析

相关考题:

34.HashMapprops=newHashMap();35.props.put(”key45”,somevalue”);36.props.put(”key12”,someothervalue”);37.props.put(”key39”,yetanothervalue”);38.Sets=props.keySet();39.//insertcodehereWhat,insertedatline39,willsortthekeysinthepropsHashMap?()A.Arrays.sort(s);B.s=newTreeSet(s);C.Collections.sort(s);D.s=newSortedSet(s);

下列程序的运行结果是【 】。 include class SomeClass { public: SomeClass(int va 下列程序的运行结果是【 】。include <iostream. h>class SomeClass{public:SomeClass(int value) { some_value=value;};void show_data(void) { cout<<data<<"<<~some_value<<endl; };static void set_data(int value) {data=value; }private:static int data;int some_value};int SomeClass::datavoid main(void){SomeClass my_class(1001),your_class(2002);your_class. set_data(4004);my_elass. show_data()}

33. try {  34. // some code here  35. } catch (NullPointerException e1) {  36. System.out.print(”a”);  37. } catch (RuntimeException e2) {  38. System.out.print(”b”);  39. } finally {  40. System.out.print(”c”);  41. }  What is the result if a NullPointerException occurs on line 34?() A、 cB、 aC、 abD、 acE、 bcF、 abc

31. // some code here  32. try {  33. // some code here  34. } catch (SomeException se) {  35. // some code here  36. } finally {  37. // some code here  38. }  Under which three circumstances will the code on line 37 be executed?()A、 The instance gets garbage collected.B、 The code on line 33 throws an exception.C、 The code on line 35 throws an exception.D、 The code on line 31 throws an exception.E、 The code on line 33 executes successfully.

33. Date d = new Date(0);  34. String ds = “December 15, 2004”;  35. // insert code here  36. try {  37. d = df.parse(ds);  38. }  39. catch(ParseException e) {  40. System.out.println(”Unable to parse “+ ds);  41. }  42. // insert code here too  Which will create the appropriate DateFormat object and add a day to the Date object?() A、 35. DateFormat df= DateFormat.getDateFormat(); 42. d.setTime( (60 * 60 * 24) +d.getTime());B、 35. DateFormat df= DateFormat.getDateJnstance(); 42. d.setTime( (1000 * 60 * 60 * 24) + d.getTime());C、 35. DateFormat df= DateFormat.getDateFormat(); 42. d.setLocalTime( (1000*60*60*24) + d.getLocalTime());D、 35. DateFormat df= DateFormat.getDateJnstance(); 42. d.setLocalTime( (60 * 60 * 24) + d.getLocalTime());

34. HashMap props = new HashMap();  35. props.put(”key45”, “some value”);  36. props.put(”key12”, “some other value”);  37. props.put(”key39”, “yet another value”);  38. Set s = props.keySet();  39. // insert code here  What, inserted at line 39, will sort the keys in the props HashMap?() A、 Arrays.sort(s);B、 s = new TreeSet(s);C、 Collections.sort(s);D、 s = new SortedSet(s);

11. public interface Status {  12. /* insert code here */ int MY_VALUE = 10;  13. }  Which three are valid on line 12?()A、 finalB、 staticC、 nativeD、 publicE、 privateF、 abstractG、 protected

11. public void someMethod(Object value) {  12. // check for null value ....  20. System.out.println(value.getClass());  21. }  What, inserted at line 12, is the appropriate way to handle a null value?() A、 assert value == null;B、 assert value !null, “value is null”;C、 if (value == null) { throw new AssertionException(”value is null”);D、 if (value == null) { throw new IllegalArgumentException(”value is null”);

现有:  1. import java.util.*;      2.  3. Class FindStuff  {  4.public static void main (String[]args)    {      5,    //insert code here      6.    c.put ("X", 123);      7.    }      8.  } 分别插入到第5行,哪三行允许代码编译?()    A、 Map c= new SortedMap();B、 HashMap c= new HashMap();C、 HashMap c= new Hashtalole();D、 SortedMap c= new TreeMap();E、 ArrayList c= new ArrayList();F、  MaD c = new LinkedHashMap();

10. public class ClassA {  11. public void methodA() {  12. ClassB classB = new ClassB();  13. classB.getValue();  14. }  15. }  And:  20. class ClassB {  21. public ClassC classC;  22.  23. public String getValue() {  24. return classC.getValue();  25. }  26. }  And:  30. class ClassC {  31. public String value;  32.  33. public String getValue() {  34. value = “ClassB”;  35. return value;  36. }  37. }  Given:  ClassA a = new ClassA();  a.methodA();  What is the result?()A、 Compilation fails.B、 ClassC is displayed.C、 The code runs with no output.D、 An exception is thrown at runtime.

1. import java.util.*;  2.  3. Class FindStuff {  4. public static void  main(String [] args) {  5. // insert code here  6. c.put("x", 123);  7. }  8. } 分别插入到第5行,哪三行允许代码编译?() A、Map c = new SortedMap();B、HashMap c = new HashMap();C、HashMap c = new Hashtable();D、SortedMap c = new TreeMap();

By default, what does a Juniper Networks router set the BGP origin code to when originating theroute?()A、IGP (Value 0)B、EGP (Value 1)C、Incomplete (Value 2)D、It depends on the route's source.

Given a method that must ensure that its parameter is not null: 11. public void someMethod(Object value) { 12. // check for null value ... 20. System.out.println(value.getClass()); 21. } What inserted at line 12, is the appropriate way to handle a null value?()A、assert value == null;B、assert value != null, "value is null";C、if (value == null) { throw new AssertionException("value is null"); }D、if (value == null) { throw new IllegalArgumentException("value is null"); }

You executed the following code:   BEGIN   DBMS_SCHEDULER.SET_ATTRIBUTE  (  NAME = ’JOB_A’,   ATTRIBUTE = ’JOB_PRIORITY’,   VALUE = 7);   END;  /   After analyzing the above code, what conclusion will you draw?()  A、 The code will be executed successfully.B、 The code will not be executed successfully because the value of the VALUE parameter must be 1, 2, or 3.C、 The code will not be executed successfully because the value of the VALUE parameter must range between 1 and 5.D、 The code will not be executed successfully because no SET_ATTRIBUTE procedure exists in the DBMS_SCHDULER package.

Given 11.public interface Status { 12./* insert code here */ int MY_VALUE = 10; 13.} Which three are valid on line 12?()A、finalB、staticC、nativeD、publicE、private

单选题Given a method that must ensure that its parameter is not null: 11. public void someMethod(Object value) { 12. // check for null value ... 20. System.out.println(value.getClass()); 21. } What inserted at line 12, is the appropriate way to handle a null value?()Aassert value == null;Bassert value != null, value is null;Cif (value == null) { throw new AssertionException(value is null); }Dif (value == null) { throw new IllegalArgumentException(value is null); }

单选题Assume a JavaBean com.example.GradedTestBean exists and has two attributes. The attribute name is oftype java.lang.String and the attribute score is of type java.lang.Integer. An array of com.example. GradedTestBean objects is exposed to the page in a request- scoped attribute called results. Additionally,an empty java.util.HashMap called resultMap is placed in the page scope. A JSP page needs to add the firstentry in results to resultMap, storing the name attribute of the bean as the key and the score attribute of thebean as the value. Which code snippet of JSTL code satisfies this requirement?()A${resultMap[results[0].name] = results[0].score}Bc:set var=${resultMap} key=${results[0].name} value=${results[0].score} /Cc:set var=resultMap property=${results[0].name} ${results[0].value}/c:setDc:set var=resultMap property=${results[0].name} value=${results[0].score} /Ec:set target=${resultMap} property=${results[0].name} value=${results[0].score} /

单选题Given: 11.double input = 314159.26; 12.NumberFormat nf = NumberFormat.getInstance(Locale.ITALIAN); 13.String b; 14.//insert code here Which code, inserted at line 14, sets the value of b to 314.159,26?()Ab = nf.parse( input );Bb = nf.format( input );Cb = nf.equals( input );Db = nf.parseObject( input );

多选题Given 11.public interface Status { 12./* insert code here */ int MY_VALUE = 10; 13.} Which three are valid on line 12?()AfinalBstaticCnativeDpublicEprivate

单选题By default, what does a Juniper Networks router set the BGP origin code to when originating theroute?()AIGP (Value 0)BEGP (Value 1)CIncomplete (Value 2)DIt depends on the route's source.

单选题10. public class ClassA {  11. public void methodA() {  12. ClassB classB = new ClassB();  13. classB.getValue();  14. }  15. }  And:  20. class ClassB {  21. public ClassC classC;  22.  23. public String getValue() {  24. return classC.getValue();  25. }  26. }  And:  30. class ClassC {  31. public String value;  32.  33. public String getValue() {  34. value = “ClassB”;  35. return value;  36. }  37. }  Given:  ClassA a = new ClassA();  a.methodA();  What is the result?()A Compilation fails.B ClassC is displayed.C The code runs with no output.D An exception is thrown at runtime.

多选题31. // some code here  32. try {  33. // some code here  34. } catch (SomeException se) {  35. // some code here  36. } finally {  37. // some code here  38. }  Under which three circumstances will the code on line 37 be executed?()AThe instance gets garbage collected.BThe code on line 33 throws an exception.CThe code on line 35 throws an exception.DThe code on line 31 throws an exception.EThe code on line 33 executes successfully.

单选题You executed the following code:   BEGIN   DBMS_SCHEDULER.SET_ATTRIBUTE  (  NAME = ’JOB_A’,   ATTRIBUTE = ’JOB_PRIORITY’,   VALUE = 7);   END;  /   After analyzing the above code, what conclusion will you draw?()A The code will be executed successfully.B The code will not be executed successfully because the value of the VALUE parameter must be 1, 2, or 3.C The code will not be executed successfully because the value of the VALUE parameter must range between 1 and 5.D The code will not be executed successfully because no SET_ATTRIBUTE procedure exists in the DBMS_SCHDULER package.

单选题11. public void someMethod(Object value) {  12. // check for null value ....  20. System.out.println(value.getClass());  21. }  What, inserted at line 12, is the appropriate way to handle a null value?()A assert value == null;B assert value !null, “value is null”;C if (value == null) { throw new AssertionException(”value is null”);D if (value == null) { throw new IllegalArgumentException(”value is null”);

多选题11. public interface Status {  12. /* insert code here */ int MY_VALUE = 10;  13. }  Which three are valid on line 12?()AfinalBstaticCnativeDpublicEprivateFabstractGprotected

单选题33. Date d = new Date(0);  34. String ds = “December 15, 2004”;  35. // insert code here  36. try {  37. d = df.parse(ds);  38. }  39. catch(ParseException e) {  40. System.out.println(”Unable to parse “+ ds);  41. }  42. // insert code here too  Which will create the appropriate DateFormat object and add a day to the Date object?()A 35. DateFormat df= DateFormat.getDateFormat(); 42. d.setTime( (60 * 60 * 24) +d.getTime());B 35. DateFormat df= DateFormat.getDateJnstance(); 42. d.setTime( (1000 * 60 * 60 * 24) + d.getTime());C 35. DateFormat df= DateFormat.getDateFormat(); 42. d.setLocalTime( (1000*60*60*24) + d.getLocalTime());D 35. DateFormat df= DateFormat.getDateJnstance(); 42. d.setLocalTime( (60 * 60 * 24) + d.getLocalTime());

单选题34. HashMap props = new HashMap();  35. props.put(”key45”, “some value”);  36. props.put(”key12”, “some other value”);  37. props.put(”key39”, “yet another value”);  38. Set s = props.keySet();  39. // insert code here  What, inserted at line 39, will sort the keys in the props HashMap?()A Arrays.sort(s);B s = new TreeSet(s);C Collections.sort(s);D s = new SortedSet(s);

单选题33. try {  34. // some code here  35. } catch (NullPointerException e1) {  36. System.out.print(”a”);  37. } catch (RuntimeException e2) {  38. System.out.print(”b”);  39. } finally {  40. System.out.print(”c”);  41. }  What is the result if a NullPointerException occurs on line 34?()A cB aC abD acE bcF abc