判断题String s = (Double.valueOf("3.1415926")).toString()。A对B错

判断题
String s = (Double.valueOf("3.1415926")).toString()。
A

B


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String s = (Double.valueOf("3.1415926")).toString()。

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1. interface TestA { String toString(); }  2. public class Test {  3. public static void main(String[] args) {  4. System.out.println(new TestA() {  5. public String toString() { return “test”; }  6. }  7. }  8. }  What is the result?() A、 testB、 nullC、 An exception is thrown at runtime.D、 Compilation fails because of an error in line 1.E、 Compilation fails because of an error in line 4.F、 Compilation fails because of an error in line 5.

单选题public String makinStrings() {  String s = “Fred”;  s = s + “47”;  s = s.substring(2, 5);  s = s.toUpperCase();  return s.toString();  }  How many String objects will be created when this method is invoked?()A 1B 2C 3D 4E 5F 6

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单选题class A {   public String toString () {   return “4”;   }   }   class B extends A {   8. public String toString () {   return super.toString() + “3”;   }   }   public class Test {   public static void main(Stringargs) {   System.out.printIn(new B());   }   }   What is the result?()A Compilation succeeds and 4 is printed.B Compilation succeeds and 43 is printed.C An error on line 9 causes compilation to fail.D An error on line 14 causes compilation to fail.E Compilation succeeds but an exception is thrown at line 9.

单选题public class foo {  public static void main (String[]args) {  String s;  system.out.printIn (“s=” + s);  }  }   What is the result?()A The code compiles and “s=” is printed.B The code compiles and “s=null” is printed.C The code does not compile because string s is not initialized.D The code does not compile because string s cannot be referenced.E The code compiles, but a NullPointerException is thrown when toString is called.

单选题public class foo {   public static void main (Stringargs) {  String s;   system.out.printIn (“s=” + s);   }   }   What is the result?()A The code compiles and “s=” is printed.B The code compiles and “s=null” is printed.C The code does not compile because string s is not initialized.D The code does not compile because string s cannot be referenced.E The code compiles, but a NullPointerException is thrown when toString is called.