某LTI系统的微分方程为y′(t)+2y(t)=f(t),在f(t)作用下其零状态响应为1+e-t,则当输入为2f(t)+f′(t)时,其零状态响应为:()A、2+e-tB、2-e-tC、2+3e-tD、1
某LTI系统的微分方程为y′(t)+2y(t)=f(t),在f(t)作用下其零状态响应为1+e-t,则当输入为2f(t)+f′(t)时,其零状态响应为:()
- A、2+e-t
- B、2-e-t
- C、2+3e-t
- D、1
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