一个电流互感器的初级绕组由额定电流各为I1N=100A的两个相同的线圈组成,如果初级绕组的线圈串联或并联,次级额定电流均为I2N=5A,当初级绕组的两个线圈串联或并联时,确定电流互感器的额定变比系数。
一个电流互感器的初级绕组由额定电流各为I1N=100A的两个相同的线圈组成,如果初级绕组的线圈串联或并联,次级额定电流均为I2N=5A,当初级绕组的两个线圈串联或并联时,确定电流互感器的额定变比系数。
相关考题:
有一过程如下:Sub Sub1(m As Integer,total As Long)Dim i As Integertotal=1For i=1 To mtotal=total*iNextEnd Sub调用它的事件过程如下:Private Sub Command1_Click()Dim tot As Long,a As Integera=Val(InputBox("请输入数据"))Call Sub1(a,tot)Print totEnd Sub则输入数据5,运行结果为【 】。
设有如下程序:Private Sub Form_C1ick()Dim s As Long,f As LongDim n As Integer,i As Integerf=1n=4For i=1 To nf=f*is=s+fNext iPrint sEnd Sub程序运行后,单击窗体,输出结果是A.32B.33C.34 0)35
下列关于Sub过程的叙述正确的是A.一个Sub过程必须有一个Exie Sub语句B.一个Sub过程必须有一个Enb Sub语句C.在Sub过程中可以定义一个Function过程D.可以用Goto语句退出Sub过程
阅读程序: Sub p( b () As Integer)For i =1To 4 b(i) = 2(iNext i End Sub Private Sub Command1_Click()Dim a (1 To 4) As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 call p (a) For i=1 To 4 Print a(i) Next iEnd Sub运行上面的程序,单击命令按钮,输出结果为。
在窗体中添加一个名称为Command1的命令按钮,然后编写如下程序:Private Sub f(ByVal x As Integer)x=x+4End SubPrivate Sub Command1_Click()i=3Call f(i)If i>4 Then i=i*2End Sub窗体打开运行后,单击命令按钮,则消息框的输出结果为( )。
在窗体中添加一个名称为Commandl的命令按钮,然后编写如下程序:Pfivme Sub f(ByVal x As Integer)x=x+4End SubPfivate Sub Commandl_Click()i=3Call f(i)Ifi4 Then i=i*2MsgBOx IEnd Sub窗体打开运行后,单击命令按钮,则消息框的输出结果为______。
设有如下程序: Private Sub search(a()As Variant,ByVal key As Variant,index%) Dim I% For I = Lbound(a)To Ubound(A)If key=a(I)Then index=I Exit Sub End If Next I index=-1 End Sub Private Sub Form_Load() Show Dim b()As Variant Dim n As Integer b=Array(21,64,92,15,72,38,45,72) Call search(b, 45, n) Print n End Sub 程序运行后,输出的结果是A.2B.6C.10D.12
在窗体上画一个名称为CoilTlilandl的命令按钮,然后编写如下事件过程: Private Sub command1 Click() Dim m As Integer, i As Integer, x(3)As Integer For i=0 To 3:x(i)=i:Next i For i = 1 To 2: Call sub1(x,i):Next i For i = 0 To 3: Print x(i);: Next i End Sub Private Sub sub1(a()As Integer,k As Integer) Dim i As Integer Do a(k)=a(k)+a(k+1) j = j + 1 Loop While j < 2 End Sub 程序运行后,单击命令按钮,则窗体上显示的内容是A.0 3 7 5B.0 1 2 3C.3 2 4 5D.0 5 8 3
设计一个计时程序。该程序用户界面如图所示,由一个文本框(Text1)、两个按钮:命令按钮1(Command1)、命令按钮2(Command2)组成。程序运行后,单击开始按钮,则开始计时,文本框中显示秒数,单击停止按钮,则计时停止。单击窗口则退出。请在【 】、【 】和【 】处填入适当的内容,将程序补充完整。Option ExplicitDim iPrivate Sub Command1_Click()i=0Timer1.Interval=1000TimerEnabled=TrueEnd SubPrivate Sub Command2_Click()TimerEnabled=FalseEnd SubPrivate Sub Form_Click()【 】MeEnd SubPrivate Sub Form_Load()TimerEnabled=FalseTextText=0End SubPrivate Sub Timer1_【 】()i=i+1TextText=【 】End Sub
在窗体上画一个命令按钮,然后编写如下事件过程: Sub BTC(old Copy( ) As Integer,new Copy( ) As Integer) Dim i AS Integer For i=LBound(oldCopy( ))To UBound(oldCopy( )) newCopy(i)=oldCopy(i) Next i End Sub Private Sub Command1 _ Click( ) Dimm(10) As Integer,n(10)As Integer For i=1 To 10 m(i) =i*i Next i Call BTC(m,n) Print n(5) End Sub 程序运行后,单击命令按钮输出结果为A.0B.2C.10D.25
编写如下事件过程: Option Base 1 Private Sub Form Click() Dim x1()As Integer Dim i As Integer Dim s As Integer ReDim x1(3) For i = 1 To UBound(x1) x1(i)=i + 1 Next i Call sub1(x1) For i = 1 To UBound(x1) s = s + x1(i) Next i Print s End Sub Private Sub sub1(n()As Integer) Dim i As Integer ReDim Preserve n(5) For i = 3 To 5 n(i)=n(i-1)*2 Next i End Sub 程序运行后,单击窗体,则窗体上显示的内容是A.6B.12C.24D.47
设有如下程序:Private Sub Form. Click( )Dim s As Long,f As LongDim n As Integer,i As Integerf=1n=4For i=1 To nf=f*is=s+fNext iPrint sEnd Sub程序运行后,单击窗体,输出结果是( )。A.32B.33C.34D.35
以下能够正确计算n!的程序是( )。A.Private Sub Commandl_C1ick()B.hiVate Sub Commandl_C1ick() n=5:x=1 n=5:x=1:i=1 DO DO X=x*1 X=X*1 i=i+1 i=i+1 Loop while i<n Loop While<n Print x Ptinte x End Sub End SubC.Private Sub Commandl_Click ()D.Pdvate Sub Commandl C1ick() n=5:X=1:i=1 n=5=:x=1:i=1 DO DO X=X*1 X=X*1 i=i+1 i=i+1 Loop While i>n Print x Print x End Sub End Sub
class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?() A、 0B、 1C、 2D、 Compilation fails.
单选题class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?()A 0B 1C 2D Compilation fails.
单选题class super ( public int I = 0; public super (string text) ( I = 1 ) ) public class sub extends super ( public sub (string text) ( i= 2 ) public static void main (straing args) ( sub sub = new sub (“Hello”); system.out. PrintIn(sub.i); ) ) What is the result?()A Compilation will fail.B Compilation will succeed and the program will print “0”C Compilation will succeed and the program will print “1”D Compilation will succeed and the program will print “2”
单选题电流互感器的变流比为一次绕组的()与二次绕组额定电流之比。A最大电流B最小电流C额定电流