If the building project ________ by the end of this month is delayed, the construction company will be fined. A. being completedB. to be completedC. is completedD. completed
If the building project ________ by the end of this month is delayed, the construction company will be fined.
A. being completed
B. to be completed
C. is completed
D. completed
相关考题：
Which order of steps is followed in carrying out the project?A. Assessment－Prototype－Design－Construction.B. Assessment－Design－Prototype－Construction.C. Design－Assessment－Prototype－Construction.D. Design－Prototype－Assessment－Construction.
在下面程序的横线处填上______,使程序执行后的输出结果为1／2005。 include using nam 在下面程序的横线处填上______，使程序执行后的输出结果为1/2005。include＜iostream.h＞using namespace std;class Date{Public:Date(int m=1,int y=0): month(m),year(y){}void Print(){cout＜＜month＜＜"/"＜＜year＜＜end1;}______operator+(const Dated1,const Dated2);private:int month, year;};Date operator+(const Dated1，const Dated2){int year,month;year=d1.year+d2.year;month=d1.month+d2.month;year+=(month-1)／12;month=(month-1)%12+1;return Date(month,year);}void main(){Date d1(3,2004),d2,d3(10);d2=d3+d1;d2.Print();}
有以下程序： class Date { public： Date(int y,int m,int D) ； { year =y； month=m； day=d； } Date(int y=2000) { year=y； month=10； day=1； } Date(Date D) { year=d.year； month=d.month； day=d.day； } void print () { cout＜＜year＜＜"．"＜＜month＜＜"."＜＜day＜＜end1； } private： int year,month,day； }； Date fun(Date D) { Date temp； temp=d； return temp； } int main() { Date date1(2000,1，1)，date2(0，0,0)； Date date3(date1)； date2=fun(date3)； return 0； } 程序执行时，Date类的拷贝构造函数被调用的次数是A．2B．3C．4D．5
在下面程序的横线处填上适当的内容,使程序执行后的输出结果为1／2005。includeusing n 在下面程序的横线处填上适当的内容，使程序执行后的输出结果为1/2005。include ＜iostream.h＞using namespace std:class Datepublic:Date (int m=1,int y=0):month(m .year(y}{}void Print() {cout＜＜month＜＜"/"＜＜year＜＜end1;}______operator+(const Date d1,const Dated2;private:int month year;};______operaror+(const Dated1,const Date d2)int year, month;year=d1.year+d2.year;month=d1.month+d2.month;year+=(month-1)/12;month=(month-1)%12+l;return Date{month, year}:}void main(){Date d1(3,2004),d2,d3(10);d2=d3+d1;d2.Print();}
在下向程序和横线处填上适当的内容,使程序执行后的输出结果为1／2005。 include using 在下向程序和横线处填上适当的内容，使程序执行后的输出结果为1/2005。include ＜iostream＞using namespace std;class Date{public:Date(int m=1,int y=0):month(m),year(y){}void Print() {cout＜＜month＜＜"/"＜＜year＜＜end 1; }【 】 operator+(eonst Date d1, const Date d2);private:int month,year;};【 】 operator+(const Date d1, const Date d2){int year,month;year=d1.year+d2.year;month=d1. month+d2.month;year+=(month-1 )/12;month=(month-1 )% 12+1;return Date(month,year);}void main()Date d1 (3,2004),d2,d3(10);d2=d3+d1;d2,Print();}
有以下程序： class Date { public: Date(int y, int m, int d); year = y; month = m; day = d; Date(int y = 2000) year = y; month = 10; day = 1; Date(Date d) { year = d.year; month = d.month; day = a.day; } void print() cout＜＜year＜＜"."＜＜month＜＜"."＜＜day＜＜end1; } private: int year, month,day; }; Date fun(Date d) Date temp; temp = d; return temp; } int main() { Date date 1 (2000,1,1),date2(0,0,0); Date date3(date 1); date2 = fun(date3); return 0; } 程序执行时，Date 类的拷贝构造函数被调用的次数是A．2B．3C．4D．5
Software Engineering is best described as （ ）.A.the practice of designing, building, and maintaining off-the-shelf software from prefabricated partsB.the practice of designing, building, and maintaining ad-hoc software without the use of formal methodsC.the practice of designing, building, and maintaining reliable and cost-effective software using standard techniquesD.the practice of designing, building, and maintaining fast and flexible software specifically for engineering applications
下面哪个陈述最准确地表达Architecture(建筑学)的含义？( )A.form and function of buildingB.science and art of buildingC.art and style of buildingD.design and construction of building注：building-房屋；science-科学；design-设计；form-形式；art-艺术；construction-建造；function 功能；style-风格；and-和