下面的代码用于执行()操作。 updte tb_student SET nme = ’明日’ WHERE id =1;A.添加名字为明日的记录B.查询名字为明日的记录C.更新名字为明日D.删除名字为明日的记录

下面的代码用于执行()操作。 updte tb_student SET nme = ’明日’ WHERE id =1;

A.添加名字为明日的记录

B.查询名字为明日的记录

C.更新名字为明日

D.删除名字为明日的记录


参考答案和解析
C

相关考题:

在执行语句SELECT department_id FROM employees,departments WHERE employees.department_id= departments.department_id;时报错,原因是()。 A.没有给表employees和表departments加别名B.没有给列department_id加别名C.不能用employees.department_id=departments.department_id作为条件D.SELECT后面的department_id没有指定是哪个表

( 32 )下列哪个(些)更新操作可以执行?I. UPDATE S SET 所在城市 =' 广州 ' WHERE 所在城市 =' 北京 ' ;II. UPDATE P SET 供应商号 =`B02' WHERE 供应商号 =`B01';A )仅 IB )仅 IIC )都可以D )都不可以

update student set s_name = ’王军’ where s_id =1 该代码执行的是哪项操作?A.添加姓名叫王军的记录B.删除姓名叫王军的记录C.返回姓名叫王军的记录D.更新姓名叫王军的记录

delete from student where s_id >5 该代码执行的是哪项操作?A.添加记录B.修改记录C.删除记录D.查询记录

下面SQL语句不正确的是() A.Select*from userB.update user set username=’zhangsan’where id=’2’C.Delete*from userD.insert into user values(1,’zhang’,’pass’);

Review the definition of the phone_list view.CHEATE OR REPLACE ALGORITHM=MERGE DEFINER= ‘root‘@localhost‘ SQL SECURITY DEFINER VIEW ‘phone_list‘ AS SELECTe . id as id ‘e . first_name AS ‘first_name‘ ‘e . last_name AS ‘last_name‘ ‘coalesce ( ph1.phone_no, ‘ – ‘) AS ‘office_no‘ ‘coalesce (ph2 .phone_no, ‘ – ‘) AS ‘cell_no‘ FROM employees e LEFT JOIN employee_phone ph1 ON ph1.emp_id = e.id AND ph1.type = ‘office‘ LEFT JOIN employee_phone ph2 ON ph2 .emp_id = e.id AND ph2 .type = ‘mobile‘The tables employees and employee_phone are InnoDB tables;all columns are used in this view. The contents of the phone_list view are as follows: Mysql select * from phone_list; 1 row in set (0.00 sec)Which method can you use to change the cell_no value to ‘555-8888‘ for John Doe?()A.INSERT INTO employee_phone (emp_id, phone_no, type) VALUES (1, ‘555-8888‘,‘mobile‘)B.UPDATE phone_list SET cell_name ‘555-8888‘ WHERE first_name= ‘John‘ and last_name= ‘Doe‘C.DELETE FROM phone_list WHERE first_name= ‘John‘ and last_name= ‘Doe‘; INSERT INTO phone_list (first_name, last_name, office_no, cell_no) VALUES (‘John‘ , ‘Doe‘ , ‘x1234‘ , ‘555-8888)D.UPDATE employee_phone SET phone_no= ‘555-8888‘ where emp_id=1

在下列所给的操作中,哪个操作能被执行A.UPDATE部门SET部门号=′05′WHERE部门名=′财务部′B.UPDATE部门SET部门号=′05′WHERE部门名=′服务部′C.UPDATE雇员SET工资=600 WHERE雇员号=′010′D.UPDATE雇员SET部门号=′05′WHERE雇员号=′101′

设S_VG(SNO,VG_GRDE)是一个基于关系SC定义的学生号和他的平均成绩的视图;下面对该视图的操作语句中,哪一个(些)是不能正确执行的Ⅰ.UPDTE S_VG SET VG_GRDE=90 WHERE SNO="2004010601";Ⅱ.SELECTSNO,VG_GRDE FROM S_VG WHERE SNO="2004010601";A.仅ⅠB.仅ⅡC.都能D.都不能

已知下列员工关系表。Employees对该表的工资属性和完整性约束为:2000≤工资≤5000 现将如下2个操作组织为事务T,操作1先执行,操作2后执行。 操作1:INSERT INTO Employees VALUES(‘03650’,‘研发’,‘4600’) 操作2:UPDATE Employees SET工资=工资1.2 WHERE部门=‘市场OR部门=研发’事务T执行完毕后,关系表Employees.的数据是

Which command would you use to enable chassis cluster on an SRX device, setting the cluster ID to 1 and node to 0?() A. user@host# set chassis cluster cluster-id 1 node 0 rebootB. user@host set chassis cluster id 1 node 0 rebootC. user@host set chassis cluster cluster-id 1 node 0 rebootD. user@host# set chassis cluster id 1 node 0 reboot

在Pandas中我们可以设定某一列为特定的索引列,如我们希望把id这一列设置为索引列,那么可以用以下哪种代码实现。A.df.set_index(‘id’)B.df.set(‘id’)C. df.load_index(‘id’)D.df.get_index(‘id’)

客服业务受到SQL语句的影响非常大,以下哪些是执行效率比较低的SQL语句,可以进行优化()A、select*from record where substrb(CardNo,1,4)=’5378’;B、表tab1中的列col1是字符型(char),执行select col1,col2 from tab1 where col1’10’;C、select count(*)from stuff where id_no in(’0’,’1’);D、UPDATE SERVICEINFO SET STATE=0WHERE STATE0。

在执行语句SELECT department_id FROM employees,departments WHERE employees.department_id= departments.department_id;时报错,原因是()。A、没有给表employees和表departments加别名B、没有给列department_id加别名C、不能用employees.department_id=departments.department_id作为条件D、SELECT后面的department_id没有指定是哪个表

要在tbAddress表中更新记录,下面()语句是正确的。A、Update tbAddress Set strName="萌萌",intAge=22 Where ID=2B、Update tbAddress Set strName=萌萌,intAge=22 Where strName=萌萌C、Update tbAddress Set dtmSubmit=2008-10-1 Where strName="萌萌"D、Update tbAddress Set intAge=18

下列哪个(些)更新操作可以执行?() I.UPDATE S SET所在城市=‘广州’WHERE所在城市=’北京‘; II.UPDATE P SET供应商号=`B02’WHERE供应商号=`B01’;A、仅IB、仅IIC、都可以D、都不可以

V5.x系统中,删除动环网管Sybase数据库scanbus表中前置机ID为1且总线ID为3的SQL语句应该是()A、delete*from scanbus where qzj_id=1 and scanbus_id=3B、deletefrom scanbus whereqzj_id=1 and scanbus_id=3C、del*from scanbus where qzj_id=1 and scanbus_id=3D、delfrom scanbus where qzj_id=1 and scanbus_id=3

您需要更新居住地为亚特兰大(Atlanta)的雇员的区域代码。考虑下面的部分UPDATE语句: UPDATE 雇员 SET 区域代码=770 应在UPDATE语句中包含以下哪个子句,才能得到想要的结果?()A、UPDATE城市=Atlanta;B、SET城市=’Atlanta’;C、WHERE城市=’Atlanta’;D、LIKE’At%’;

Which command would you use to enable chassis cluster on an SRX device, setting the cluster ID to 1 and node to 0?()A、user@host# set chassis cluster cluster-id 1 node 0 rebootB、user@host set chassis cluster id 1 node 0 rebootC、user@host set chassis cluster cluster-id 1 node 0 rebootD、user@host# set chassis cluster id 1 node 0 reboot

单选题使用SQL语句完成“将所有冷饮类商品的单价优惠1元",正确的操作是(  )。AUPDATE商品SET单价=单价-1 WHERE类别="冷饮"BUPDATE商品SET单价=1 WHERE类别="冷饮"CUPDATE商品SET单价-1 WHERE类别="冷饮"D以上都不对

单选题Given the following table definitions: EMPLOYEE ID NAME DEPTID 01Smith 10 02Bossy 20 03 20 Peterson 04Goss 30 05Pape 40 06Avery 50 07O'Neal 60 08Carter 50 DEPARTMENT ID DEPTNAME 05 Hardware 10 Kitchen 20 Shoes 30 Toys 40 Electronics 50 Automotive and the following query: SELECT e.id, d.deptname FROM employee e, department d WHERE e.deptid = d.id AND e.id 4 Which of the following queries will produce the same result set as the query above?()ASELECT e.id, d.deptname FROM employee e, department d WHERE e.id 4BSELECT e.id, d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE e.id 4CSELECT e.id, d.deptname FROM employee e FULL OUTER JOIN department d ON e.id = d.id WHERE e.id 4DSELECT e.id, d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4 UNION ALL SELECT e.id, d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4

单选题Given the following table definitions: EMPLOYEE ID NAME DEPTID 01Smith 10 02Bossy 20 03 20 Peterson 04Goss 30 05Pape 40 06Avery 50 07O'Neal 60 08Carter 50 DEPARTMENT ID DEPTNAME 05 Hardware 10 Kitchen 20 Shoes 30 Toys 40 Electronics 50 Automotive and the following query: SELECT e.id, d.deptname FROM employee e, department d WHERE e.deptid = d.id AND e.id 4 Which of the following queries will produce the same result set as the query above?()ASELECT e.id, d.deptname FROM employee e, department d WHERE e.id 4BSELECT e.id, d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE e.id 4CSELECT e.id, d.deptname FROM employee e FULL OUTER JOIN department d ON e.id = d.id WHERE e.id 4DSELECT e.id, d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4 UNION ALL SELECT e.id, d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4

单选题如何实现文章表news,id字段值为5记录的点击数字段num自增()。AUpdate news set num=num+1;BUpdate news set num=num+1 where id==5CUpdate news set num=num++ where id=5DUpdate news set num=num+1 where id=5

单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2 (25) LAST_NAME VARCHAR2 (25) HIRE_DATE DATE Which UPDATE statement is valid?()AUPDATE employees SET first_name = 'John' SET last_name = 'Smith' WHERE employee_id = 180;BUPDATE employees SET first_name = 'John', SET last_name = 'Smoth' WHERE employee_id = 180;CUPDATE employee SET first_name = 'John' AND last_name = 'Smith' WHERE employee_id = 180;DUPDATE employee SET first_name = 'John', last_name = 'Smith' WHERE employee_id = 180;

单选题使用SQL语句完成“将所有女职工的工资提高5%”,正确的操作是(  )。AUPDATE 职工 SET 工资=工资*1.05 WHERE 性别=“女”BUPDATE 职工 SET 工资*0.05 WHERE 性别=“女”CUPDATE 职工 SET 工资=工资*5%WHERE 性别=“女”DUPDATE 职工 SET 工资*1.05 WHERE 性别=“女”

单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER NOT NULL EMP_NAME VARCHAR2(30) JOB_ID VARCHAR2(20) DEFAULT 'SA_REP' SAL NUMBER COMM_PCT NUMBER MGR_ID NUMBER DEPARTMENT_ID NUMBER You need to update the records of employees 103 and 115. The UPDATE statement you specify should update the rows with the values specified below: JOB_ID: Default value specified for this column definition. SAL: Maximum salary earned for the job ID SA_REP. COMM_PCT: Default value specified for this commission percentage column, if any. If no default value is specified for the column, the value should be NULL. DEPARTMENT_ID: Supplied by the user during run time through substitution variable. Which UPDATE statement meets the requirements?()AUPDATE employees SET job_id = DEFAULT AND Sal = (SELECT MAX(sal) FROM employees WHERE job_id = 'SA_REP') AND comm_pct = DEFAULT AND department_id = did WHERE employee_id IN (103,115);BUPDATE employees SET job_id = DEFAULT AND Sal = MAX(sal) AND comm_pct = DEFAULT OR NULL AND department_id = did WHERE employee_id IN (103,115) AND job_id = 'SA_REP';CUPDATE employeesC.UPDATE employees SET job_id = DEFAULT, Sal = (SELECT MAX(sal) FROM employees WHERE job_id = 'SA_REP'), comm_pct = DEFAULT, department_id = did WHERE employee_id IN (103,115);DUPDATE employeesD.UPDATE employees SET job_id = DEFAULT, Sal = MAX(sal), comm_pct = DEFAULT, department_id = did WHERE employee_id IN (103,115) AND job_id = 'SA_REP';EUPDATE employees SET job_id = DEFAULT, Sal = (SELECT MAX(sal) FROM employees WHERE job_id = 'SA_REP'), comm_pct = DEFAULT OR NULL, department_id = did WHERE employee_id IN (103,115);

单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER NOT NULL EMP_NAME VARCHAR2(30) JOB_ID VARCHAR2(20) DEFAULT 'SA_REP' SAL NUMBER COMM_PCT NUMBER MGR_ID NUMBER DEPARTMENT_ID NUMBER You need to update the records of employees 103 and 115. The UPDATE statement you specify should update the rows with the values specified below: JOB_ID: Default value specified for this column definition. SAL: Maximum salary earned for the job ID SA_REP. COMM_PCT: Default value specified for this commission percentage column, if any. If no default value is specified for the column, the value should be NULL. DEPARTMENT_ID: Supplied by the user during run time through substitution variable. Which UPDATE statement meets the requirements?()AUPDATE employees SET job_id = DEFAULT AND Sal = (SELECT MAX(sal) FROM employees WHERE job_id = 'SA_REP') AND comm_pct = DEFAULT AND department_id = did WHERE employee _id IN (103,115);BUPDATE employees SET job_id = DEFAULT AND Sal = MAX(sal) AND comm_pct = DEFAULT OR NULL AND department_id = did WHERE employee_id IN (103,115) AND job _ id = 'SA_ REP';CUPDATE employees SET job_id = DEFAULT, Sal = (SELECT MAX(sal) FROM employees WHERE job_id = 'SA_REP'), comm_pct = DEFAULT, department_id = did WHERE employee_id IN (103,115);DUPDATE employees SET job_id = DEFAULT, Sal = MAX(sal), comm_pct = DEFAULT, department_id = did WHERE employee_id IN (103,115) AND job _ id = 'SA_ REP';EUPDATE employees SET job_id = DEFAULT, Sal = (SELECT MAX(sal) FROM employees WHERE job_id = 'SA_REP') comm_pct = DEFAULT OR NULL, department_id = did WHERE employee_id IN (103,115);

单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE You issue these statements: CREATE table new_emp ( employee_id NUMBER, name VARCHAR2(30)); INSERT INTO new_emp SELECT employee_id , last_name from employees; Savepoint s1; UPDATE new_emp set name = UPPER(name); Savepoint s2; Delete from new_emp; Rollback to s2; Delete from new_emp where employee_id =180; UPDATE new_emp set name = 'James'; Rollback to s2; UPDATE new_emp set name = 'James' WHERE employee_id =180; Rollback; At the end of this transaction, what is true?()AYou have no rows in the table.BYou have an employee with the name of James.CYou cannot roll back to the same savepoint more than once.DYour last update fails to update any rows because employee ID 180 was already deleted.

单选题下列哪个(些)更新操作可以执行?() I.UPDATE S SET所在城市=‘广州’WHERE所在城市=’北京‘; II.UPDATE P SET供应商号=`B02’WHERE供应商号=`B01’;A仅IB仅IIC都可以D都不可以