同时把“铁架台”、“铁夹”、“烧杯”设为从内到外的显示方式，设计图标的层设置应该为（）A、1、2、3B、3、2、1C、max、mid、minD、min、mid、max
同时把“铁架台”、“铁夹”、“烧杯”设为从内到外的显示方式，设计图标的层设置应该为（）
- A、1、2、3
- B、3、2、1
- C、max、mid、min
- D、min、mid、max
相关考题：
●试题六阅读以下说明和C＋＋程序，将应填入(n)处的字句写在答题纸的对应栏内。【说明】设计一个类模板Sample用于对一个有序数组采用二分法查找元素下标。【C＋＋程序】#includeiostream．h#define Max 100∥最多元素个数templateclass Tclass Sample{T A［Max］：∥存放有序数序int n：∥实际元素个数publicSample(){}∥默认构造函数Sample(T a［］，int i)；∥初始化构造函数int seek(T c)；void disp(){for(int i=0；in；i＋＋)coutA［i］""；coutend1：}}；templateclass TSampleT：：Sample(T a［］，int i){n=i；for(intj=0；ji；j＋＋)(1) ；}templateclass Tint SampleT：：seek(T c){int low=0，high=n-1，mid；while( (2) ){mid=(low+high)／2；if( (3) )return mid；else if( (4) )low=mid+l；else(5) ；}return-1；}void main(){char a［］="acegkmpwxz"；Samplechars(a，1。)；cout"元素序列："；s．disp()；cout"元素′g′的下标："s．seek(′g′)endl；}
x线最强波长(λmax)与最短波长(λmin)的关系是A.λmax =0．5λminB.λmax =λminC.λmax =1．5λminD.λmax =2λminE.λmax =2．5λmin
阅读以下说明和C++程序，将应填入(n)处的字句写在对应栏内。【说明】设计一个类模板SamPle用于对一个有序数组采用二分法查找元素下标。【C++程序】include ＜ iostream. h ＞define Max 100 //最多元素个数template ＜ class T ＞class Sample{T A[Max]: //存放有序数序int n: //实际元素个数publicSample( ) { } //默认构造函数Sample(T a[] ,int i); //初始化构造函数int seek(T c);void disp( ){for(int i=0;i ＜n;i ++)cout＜＜A[i] ＜＜" ";cout＜＜endl:} } template ＜ class T ＞Sample ＜T＞: :Sample(T a[ ],int i){n=i:for( intj =0;j ＜ i;j ++ )(1);}template ＜ class T ＞int Sample ＜ T ＞:: seek( T c){int low =0,high = n-1 ,mid;while((2)){mid = (low + high)/2;if((3))return mid;else if( (4) )low=mid+|;else(5);}return-1;}void main( ){char a[ ] ="acegkmpwxz";Sample ＜ char ＞ s(a, 1);cout＜＜"元素序列:" ;s. disp( );cout＜＜"元素'g'的下标:"＜＜s. seek('g') ＜＜endl;}
某人编写了下列程序，用来求10个整数(整数从键盘输入)中的最大值： Private Sub Command1_Click() Dim a(10) As Integer, max As Integer For k=1 To 10 a(k)=InputBox("输入一个整数") Next k max=0 For k=1 To 10 If a(k)＞max Then max=a(k) End If Next k Print max End Sub 运行程序时发现，当输入10个正数时，可以得到正确结果，但输入10个负数时结果是错误的。程序需要修改。下列修改中可以得到正确运行结果的是( )。A．把Ifa(k)＞max Then 改为 If a(k)＜max ThenB．把max=a(k)改为a(k)=maxC．把第2个循环语句For k=1 To 10改为For k=2 To 10D．把max=O改为max=a(10)
Asystemadministratorisimplementinganew2－way&ensp Asystemadministratorisimplementinganew2-wayPOWER5serverwithAPVthatistobedividedintothreepartitions.TheapplicationgroupshaverequestedthefollowingCPUentitlementsforthepartitions：Partition1：min=1.0，max=2.0，desired=1.5Partition2：min=1.0，max=2.0，desired=1.0Partition3：min=0.1，max=1.0，desired=0.8Theadministratorimmediatelyfindsthatthethreepartitionscannotbestartedinordertorunconcurrently.Whatchangescanbemadetoentitlementconfigurationtoallowallthreepartitionstobestartedinorder？（）
受扭实心等直圆轴，当直径增大一倍时，其最大剪应力τ2max和两端相对扭转角与原来的τ1max和的比值为（）。A.τ2max：τ1max=1:2，：=1:4B.τ2max：τ1max=1:4，：=1:8C.τ2max：τ1max=1:8，：=1:16D.τ2max：τ1max=1:4，：=1:16
对于一循环应力，以σmin表示最小应力，σmax表示最大应力，则此循环应力的静力成分σm为()。A:σm=σminB:σm=1/2(σmin+σmax)C:σm=1/2(σmax-σmin)D:σm=σmax
受扭实心等直圆轴，当直径增大一倍时，其最大剪应力τ2max和两端相对扭转角φ2与原来的τ1max和φ1的比值为（）。A.τ2max：τ1max=1:2，φ2：φ1=1:4B.τ2max：τ1max=1:4，φ2：φ1=1:8C.τ2max：τ1max=1:8，φ2：φ1=1:16D.τ2max：τ1max=1:4，φ2：φ1=1:16
三种受压杆如图所示。若用σmax1，σmax2，σmax3分别表示杆①、杆②、杆③中横截面上的最大压应力，则下列四个结论中正确的结论是：A.σmax1=σmax2=σmax3B.σmax1>σmax2=σmax3C.σmax2>σmax1=σmax3D.σmax1>σmax2>σmax3
受力情况相同的三种等截面梁,如图5-34所示。若用(σmax)1、 (σmax)2、(σmax)3分别表示这三种梁内横截面上的最大正应力，则下列结论中正确的是（ ）。A.(σmax)1=(σmax)2=(σmax)3 B.(σmax)1max)2=(σmax)3 C.(σmax)1= (σmax)2max)3 D.(σmax)1max)2max)3
受力情况相同的三种等截面梁，它们分别由整块材料或两块材料并列或两块材料叠合（未粘接）组成，如图5-33所示。若用(σmax)1 、(σmax)2、(σmax)3分别表示这三种梁中横截面上的最大正应力，则下列结论中正确的是（ ）。A. (σmax)1max)2max)3 B. (σmax)1 =(σmax)2max)3 C. (σmax)1max)2=(σmax)3 D. (σmax)1= (σmax)2=(σmax)3
紫外法做定性鉴别时，常用的特征数据有（）Aλmax，α，肩峰Bλmax，λmin，A1/A2，E1%cmCλmax/λmin，末端吸收，E1%cmDλmax/λmin，肩峰，末端吸收Eλmax，λmin，ΣA
Companycom has the following: 8 x 1.65GHz CPUs 16GB Memory 4 LPARs LPAR 1: Test/Dev 1 CPU, 2GB Memory, 1 Fibre Channel HBA, AIX 5.3 LPAR 2: QA 1 CPU, 2GB Memory, 1 Fibre Channel HBA, AIX 5.3 LPAR 3: Prod 3 CPUs, 6GB Memory, 1 Fibre Channel HBA, AIX 5.3 LPAR 4: Web App 3 CPUs, 6GB Memory, 1 Fibre Channel HBA, SUSE Linux Utilization over a 30 day period LPAR 1: Average utilization was 15%, Peak utilization was 100% LPAR 2: Average utilization was 25%, Peak utilization was 100% LPAR 3: Average utilization was 50%, Peak utilization was 90% LPAR 4: Average utilization was 35%, Peak utilization was 100% If the customer has a requirement for all four LPARs moved to a p5 590 and to have dedicated CPU resources. Which of the following would best describe the profile requirements?（）A、LPARs 1 and 2, SMT on, min CPU 1.0, max CPU 1.0, desired CPU 1.0 LPARs 3 and 4, SMT on, min CPU 1.0, max CPU 3.0, desired CPU 2.0 B、LPARs 1 and 2, SMT on, min CPU 1.0, max CPU 1.0, desired CPU 1.0 LPARs 3 and 4, SMT on, min CPU 2.0, max CPU 3.0, desired CPU 3.0 C、LPARs 1 and 2, SMT on, min CPU 1.0, max CPU 3.0, desired CPU 3.0 LPARs 3 and 4, SMT on, min CPU 1.0, max CPU 3.0, desired CPU 2.0 D、LPARs 1 and 2, SMT off, min CPU 1.0, max CPU 1.0, desired CPU 1.0 LPARs 3 and 4, SMT off, min CPU 1.0, max CPU 3.0, desired CPU 3.0
A system administrator is implementing a new 2-way POWER5 server with APV that is to be divided into three partitions. The application groups have requested the following CPU entitlements for the partitions： Partition 1： min = 1.0， max = 2.0， desired = 1.5 Partition 2： min = 1.0， max = 2.0， desired = 1.0 Partition 3： min = 0.1， max = 1.0， desired = 0.8 The administrator immediately finds that the three partitions cannot be started in order to run concurrently. What changes can be made to entitlement configuration to allow all three partitions to be started in order？（）A、Change the max on Partition 1 to 1.5.B、Change the desired on Partition 1 to 1.0.C、Change the max and desired on Partition 1 and 2 to 1.0.D、Change the min and desired on Partition 1 and 2 to 0.9.
单选题变应力的循环特性γ的表示方法是（ ）。Aγ＝σmax＋σminBγ＝σmax－σminCγ＝σmax/σminDγ＝σmin/σmax