Could you find someone _________?(A) for me to play tennis with(B) play tennis with(C) for me to play tennis(D) playing tennis with

Could you find someone _________?

(A) for me to play tennis with

(B) play tennis with

(C) for me to play tennis

(D) playing tennis with


相关考题:

When it ________ table-tennis, you can never defeat him.A.goesB.isC.aboutD.comes

You ( ) me, because I never said I liked coffee without milk. A、must misunderstandB、must have misunderstoodC、must be misunderstandingD、had to misunderstand

不可用Windows XP提供的媒体播放机播放的文件是()。 A.play.mp3B.play.aviC.play.pptD.play.mpg

8.—Can we _______ ping-pong?—No,_______ tennis.A. play; let's playB. plays; let's playC. play; let's to playD. plays; let's to play

49.—What about some drinks?—__________.A. Help, yourselfB. Good ideaC. You're welcomeD. Me,too

I__________have been there,but I__________not find the time.A.should;wouldB.should;couldC.might;couldD.could;could

Me,you是两个初始集合,则下列关于派生集合定义方式正确的是A.link/me,you/:a;B.link(me,you):a;C.link/me you/a;D.link(me,you)/a;

以下对于字符串的相关操作,正确的输出结果是哪些选项?A.>>> 'Life is short, you need Python.'.find('you') 15B.>>> seq = [1, 2, 3, 4]; >>> sep = '+'; >>> sep.join(seq) '1+2+3+4'C.>>> print('{:5.3f}'.format(math.pi)) 3.1416D.>>> print('you' in 'Life is short, you need Python.') True

9、以下对于字符串的相关操作,正确的输出结果是哪些选项?A.>>> 'Life is short, you need Python.'.find('you') 15B.>>> seq = [1, 2, 3, 4]; >>> sep = '+'; >>> sep.join(seq) '1+2+3+4'C.>>> print('{:5.3f}'.format(math.pi)) 3.1416D.>>> print('you' in 'Life is short, you need Python.') True

me是一个包含3个成员属性为a的集合,you是一个包含2个成员属性为b的集合,则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是A.ps(me,you):c;B.ps(you,me):c;C.ps(a,b):c;D.ps(b,a):c;