人体内维生素B12贮存量为()A、1~2mgB、2~3mgC、3~4mgD、4~5mgE、5~10mg

人体内维生素B12贮存量为()

  • A、1~2mg
  • B、2~3mg
  • C、3~4mg
  • D、4~5mg
  • E、5~10mg

相关考题:

设在工程中定义了下列类型: Type Stutype ino As Integer strname As String*20 Strsex As String*1 Smark As Single End Type在窗体上正确使用这个类型的是下列哪个操作 A. Sub Command1_Click() Dim student As Stutype With student .ino=12 .strname=smith .strsex=男 .smark=89 End With End Sub B. Sub Command1_Click() Dim student As Stutype With student .ino=12 .strname="smith" .strsex="男" .smark=89 End With End Sub C. Sub Command1_Click() Dim student As Stutype With Stutype .ino=12 .strname="smith" .strsex="男" .smark=89 End With End Sub D. Sub Command1_Click() Dim student As Stutype With student .ino=12 .strname="smith" .strsex="男" .smark=89 End student End Sub

(12)有下列Sub过程: Sub Sub(x As Single,y As Single) t=x x=t/y y=t Mody End Sub 在窗体上的命令按钮Commandl中,编写下列事件过程,执行该事件过程调用Sun过程,结果是( )。 Private Sub Commandl_Click() Dim a As Single Dim b As Single a=5 b=4 Sun a,b Print a;b End Sub A.1.25 1 B.5 4 C.4 5 D.1 1.25

下面程序: Private Sub Form. _Click () Dim x, y, z As Integer x=5 y=7 z=0 Call P1(x, y, z) Print Str (z) End Sub Sub P1 (ByVal a As Integer, ByVal b As Integer , c As Integer) c= a+b End Sub 运行后的输出结果为______。A.0B.12C.Str(z)D.显示错误信息

以下程序的运行结果是sub(int x,int y,int *z){*z=y-x;}main(){ int a,b,c;sub(10,5,a);sub(7,a,b);sub(a,b,c);printf("M,M,M\n",a,b,c);}A.5,2,3B.-5,-12,-7C.-5,-12,-17D.5,-2,-7

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单击命令按钮时,下列程序代码的执行结果为 Public Sub proc1(n As Integer,Byva1 m As Integer) n=n Mod 10 m=m Mod 10 End Sub Private Sub Cmmand1_Click( ) Dim x As Integer,y As lngeger x=12:y=12 Call Proe1(x,y) Print x;y End SubA.12 2B.2 12C.2 2D.12 12

以下程序的运行结果是()。includevoid sub(int x,int y,int*z){*Z=y-x;}void main() 以下程序的运行结果是( )。 #include<iostream.h> void sub(int x,int y,int*z) {*Z=y-x;} void main() {int a,b,c; sub(10,5,a); sub(7,a,b); sub(a,b,c); cout<<a<<“,”<<b<<“,”<<c<<endl;}A.5,2,3B.-5,-12,-7C.-5,-12,-17D.5,-2,-7

有如下一个Sub过程: Sub mlt(ParamArray numbers()) n=1 For Each x In numbers n=n*x Next x Print n End Sub 在一个事件过程中如下调用该Sub过程: Private Sub Command1_Click() Dim a As Integer Dim b As Integer Dim c As Integer Dim d As Integer a=1 b=2 c=3 d=4 mlt a,b,c,d End Sub 该程序的运行结果为( )。A.12B.24C.36D.48

假定有如下的Sub过程:Sub Sub1(x As Single,y As single)t=xx=t/yy=t Mod yEnd Sub在窗体上画一个命令按钮,然后编写如下事件过程:Private Sub Command1_click()Dim a As SingleDim b As Singlea=5b=4Sub1 a,bPrint a;bEnd Sub程序运行后,单击命令按钮,输出结果为A.B.C.D.

单击命令按钮时,下列程序代码的执行结果为 Public Sub Procl(n As Integer,ByVal m As integer) n=n Mod 10 m=m\10 End sub Private Sub Commandl_Click() Dim x AS Integer,y AS Integer x=12:y=24 Call Procl(x,y) Print x;y End subA.12 24B.2 24C.2 3D.12 2

下列程序的执行结果为 Private Sub Comrnandl_Click( ) Dim p As Integer, q As Integer p=12:q=20 Call Value(p, q) Print p; q End Sub Private Sub Value(ByVal m As Integer, ByVal n As Integer) m=m * 2: n=n - 5 Print m; n End SubA.20 12 20 15B.12 20 12 25C.24 15 12 20D.24 12 12 15

单击命名按钮时,下列程序代码的执行结果为 Public Sub procl ( n As Integer, Byval m As Integer) n=n Mod 10 m=m Mod 10 End Sub Private Sub Cmmand1 Click() Dim x As Integer, y As Integer x=12:y=12 Call Procl (x, y) Print x;y End SubA.12 2B.2 12C.2 2D.12 12

人体内O2、CO2进出细胞膜是通过A.单纯扩散B.易化扩散C. 人体内O<sub>2</sub>、CO<sub>2</sub>进出细胞膜是通过A.单纯扩散B.易化扩散C.主动转运D.人胞作用E.出胞作用

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1. class Super {  2. private int a;  3. protected Super(int a) { this.a = a; }  4. }  .....  11. class Sub extends Super {  12. public Sub(int a) { super(a); }  13. public Sub() { this.a= 5; }  14. }  Which two, independently, will allow Sub to compile?()A、 Change line 2 to: public int a;B、 Change line 2 to: protected int a;C、 Change line 13 to: public Sub() { this(5); }D、 Change line 13 to: public Sub() { super(5); }E、 Change line 13 to: public Sub() { super(a); }

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人体内维生素B12贮存量为()A、1~2mgB、2~3mgC、3~4mgD、4~5mgE、5~10mg

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