P2P是网络技术名词，英文翻译为person to person
P2P是网络技术名词，英文翻译为person to person
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（ 30 ）下列代码声明了 3 个类class Person{};class Student:public Person{};class Undergraduate:Student{};下列关于这些类之间关系的描述中，错误的是A ）类 Person 是类 Undergraduate 的基类B ）类 Undergraduate 从类 Student 公有继承C ）类 Student 是类 Person 的派生类D ）类 Undergraduate 是类 Person 的派生类
下列代码段声明了3个类：class Person()；class Student：public Person{};class Undergraduate：Student{}；下列关于这些类之间关系的描述中，错误的是( )。A．类Person是类Undergraduate的基类B．类Undergraduate从类Student公有继承C．类Student是类Person的派生类D．类Undergraduate是类Person的派生类
A gourmet always wants the best food, not the most. The word “gourmet” most probably means: _______. A、person who is expert in the choice of foodB、person who is on dietC、person who can eat a lotD、person who can cook
给出下列的不完整的类代码，则下列的( )语句可以加到横线处。 class Person{ String name，department； int age public Person(String n){name=n；} public Person(String n，int a){name=n；age=a；} pubilc Person(String n，String d，int a) { _______________ department=d； } }A．Person(n，a)；B．this(Person(n，a))；C．this(n，a)；D．this(name，age)；
下列程序中需要清理动态分配的数组,划线处应有的语句是_______。 include class pers 下列程序中需要清理动态分配的数组，划线处应有的语句是_______。include＜iostream.h＞class person{int age,tall;public:person( ){age=0;tall=40;cout＜＜"A baby is born."＜＜endl;}person(int i){age=i;tall=40;cout＜＜"A old person."＜＜endl;}person(int i,int j){age=i;tall=j;cout＜＜"a old person with tall."＜＜endl;)~person( ){cout＜＜"person dead."＜＜endl;}void show( ){cout＜＜"age="＜＜age＜＜",tall="＜＜tall＜＜endl;}};void main( ){person*ptr；ptr=new person[3];ptr[0]=person( );ptr[1]=person(18);ptr[2]=person(20,120);for(int i=0;i＜3;i++)ptr[i].show( );______}
给出下面不完整的类代码，则横线处的语句应该为( )。 class Person { String name，department； int age； public Person (Strings) {name=s；} public Person (String s，intA．{name=s；age=a;} public Person (String n，String d，intA){ __________ department=d； } }A)Person (n，A)；B．this (Person(n，A))；C．this(n，A)；D．this(name，age)；
23． What do you think of Mike?A． A person who is good at driving．B． A person who does well in drawing．C． A person who -likes drinking．D． A person who is good at writing．
The person in charge on the vessel and the person in charge at the facility must hold a meeting before starting the transfer of oil．Who must decide to start the transfer ________．A.The person in charge on the vesselB.The person in charge at the facilityC.Both persons in chargeD.The person in charge of either place that is doing the pumping
Which procedure should NOT be done for a person who has fainted ________．A.Revive the person with smelling saltsB.Loosen the clothingC.Lay the person horizontallyD.Give pain reliever
在电子商务领域，P2P是通常可以是哪两组英文单词的缩写？（）A、point-to-pointB、peer-to-peerC、person-to-personD、people-to-people
在J2EE中,使用（）选项中的代码，可以生成如下XML文档： Tony Blair A、Element people = doc.createElement（"PEOPLE"）； Element person = doc.createElement（"PERSON"）； Element name = doc.createElement（"NAME"）； name.appendChild（doc.createTextNode（"Tony Blair"））； people.appendChild（person）； person.appendChild（name）； doc.appendChild（people）；B、Element people = doc.createElement（"PEOPLE"）； Element person = doc.createElement（"PERSON"）； people.appendChild（person）； Element name = doc.createElement（"NAME"）； name.appendChild（doc.createTextNode（"Tony Blair"））； person.appendChild（name）； doc.appendChild（people）；C、Element people = doc.createElement（"PEOPLE"）； Element person = doc.createElement（"PERSON"）； people.appendChild（person）； Element name = doc.createElement（"NAME"）； name.appendText（doc.createTextNode（"Tony Blair"））； person.appendChild（name）； doc.appendChild（people）；D、Element people = doc.createElement（"PEOPLE"）； Element person = doc.createElement（"PERSON"）；Element name = doc.createElement（"NAME"）； name.createTextNode（"Tony Blair"）； people.appendChild（person）； person.appendChild（name）； doc.appendChild（people）；
public class Person { private name； public Person（String name） { this.name = name； } public int hashCode（） { return 420； } } Which is true？（） A、 The time to find the value from HashMap with a Person key depends on the size of the map.B、 Deleting a Person key from a HashMap will delete all map entries for all keys of typePerson.C、 Inserting a second Person object into a HashSet will cause the first Person object to beremoved as a duplicate.D、 The time to determine whether a Person object is contained in a HashSet is constant and does NOT depend on the size of the map.
在C#中，假设Person是一个类，而ITeller是一个接口，下面的（）类声明是正确的。A、class Employee：Person，ITeller B、class Employee：ITeller，PersonC、class Employee-Person，ITellerD、class Employee：Person / ITeller
已知：DataSet data=new DataSet（）；则删除数据集data中person数据表的第5行数据的方法为（）A、 data.Tables["person "].Rows[5].Delete（）；B、 data.Tables["person "].Rows.Delete（5）；C、 data.Tables["person "].Rows[4].Delete（）；D、 data.Tables["person "].Rows[].Delete（4）；
在Person的一个派生类Employee里调用Person类的构造函数正确方式为（）。A、base.Person（name，age）B、base（name，age）C、Person（name，age）D、this（name，age）
Given the uncompleted code of a class： class Person { String name， department； int age； public Person（String n）{ name = n； } public Person（String n， int a）{ name = n； age = a； } public Person（String n， String d， int a） { // doing the same as two arguments version of constructor // including assignment name=n，age=a department = d； } } Which expression can be added at the "doing the same as..." part of the constructor？（） A、 Person（n，a）；B、 this（Person（n，a））；C、 this（n，a）；D、 this（name，age）；
public class Person { private name； public Person（String name） { this.name = name； } public boolean equals（Object o） { if（ !o instanceof Person ） return false； Person p = （Person） o； return p.name.equals（this.name）； } } Which is true？（） A、 Compilation fails because the hashCode method is not overridden.B、 A HashSet could contain multiple Person objects with the same name.C、 All Person objects will have the same hash code because the hashCode method is not overridden.D、 If a HashSet contains more than one Person object with name=”Fred”， then removing another person， also with name=”Fred”， will remove them all.
You are developing a Windows Communication Foundation (WCF) service that contains the following service contract.[ServiceContract（ ）]public interface IPaymentService{ [OperationContract（ ）] void RecordPayments(Person person);}public class Person{ ... }public class Employee : Person{ ... }public class Customer : Person{ ... }You need to ensure that RecordPayments can correctly deserialize into an Employee or a Customer object. What should you do?（）A、Add the following KnownType attribute to the Employee class and to the Customer class. [KnownType(GetType(Person))]B、Implement the IExtensibleDataObject interface in the Person class.C、Implement the IExtension(ofType(T)) interface in the Person class.D、Add the following KnownType attributes to the Person class. [KnownType(GetType(Employee))] [KnownType(GetType(Customer))]
单选题The need for sleep varies ____ from person to person.AconservativelyBalternativelyCconsiderablyDinfluentially
单选题public class Person { private name； public Person（String name） { this.name = name； } public int hashCode（） { return 420； } } Which is true？（）A The time to find the value from HashMap with a Person key depends on the size of the map.B Deleting a Person key from a HashMap will delete all map entries for all keys of typePerson.C Inserting a second Person object into a HashSet will cause the first Person object to beremoved as a duplicate.D The time to determine whether a Person object is contained in a HashSet is constant and does NOT depend on the size of the map.
单选题已知：DataSet data=new DataSet（）；则删除数据集data中person数据表的第5行数据的方法为（）A data.Tables[person ].Rows[5].Delete（）；B data.Tables[person ].Rows.Delete（5）；C data.Tables[person ].Rows[4].Delete（）；D data.Tables[person ].Rows[].Delete（4）；
单选题在Person的一个派生类Employee里调用Person类的构造函数正确方式为（）。Abase.Person（name，age）Bbase（name，age）CPerson（name，age）Dthis（name，age）
单选题According to the context we can guess that a genius is _____ while an idiot is _____.Aa normal person . . . a funny personBa strong person . . . a weak personCa highly intelligent person . . . a foolish or weak-minded personDa famous person . . . an ordinary person