Such is the case, I have no other choices.()

Such is the case, I have no other choices.()


相关考题:

针对下列程序段,需要(52)个测试用例才可以满足语句覆盖的要求。 switch(value){ case 0: ther=30; break; case 1: ther=50; break; case 2: ther=300; case 3: ther=other/value; break; default: ther=other * value; }A.2B.3C.4D.5

针对下列程序段,需要______个测试用例才可以满足语句覆盖的要求。Switch(value){Case 0:0ther=30;Break;Case 1:ther=50;Break;Case 2:ther=300;Case 3:ther=other/value;Break;Default:ther=other * value;}A) 2B) 3C) 4D) 5A.B.C.D.

请补充函数fun(),该函数的功能是:分类统计一个字符串中元音字母和其他字符的个数(不区分大小写)。例如,输入aeiouAOUpqn,结果为A∶2 E∶1 1∶1 O∶2 U∶2 Other∶4。注意:部分源程序给出如下。请勿改动主函数main和其他函数中的任何内容,仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序:include<stdiO.h>include<conio.h>define N 100void fun(char *str,int bb[ ]){char *p=str;int i=0;for(i=0;i<6;i++)【 】;while(*p){switch(*p){case 'A':case 'a':bb[0]++;break;case 'E':case 'e':bb[1]++;break;case 'I':case 'i':bb[2]++;break;case 'O':case 'o':bb[3]++;break;case 'U':case 'u':bb[4]++;break;default:【 】;}【 】}}main(){char str[N),ss[6]="AEIOU";int i;int bb[6];clrscr();printf("Input a string:\n");gets(str);printf("the string is:\n");puts(str);fun(str,bb);for(i=0;i<5;i++)printf("\n%c:%d",ss[i],bb[i]);printf("\nother:%d",bb[i]);}

—I'd met Smith several times before.—So (have) ( ) I.

public static void main(String[]args){Integer i=new Integer(1)+new Integer(2);switch(i){case3:System.out.println(three);break;default:System.out.println(other);break;}}Whatistheresult?()A.threeB.otherC.Anexceptionisthrownatruntime.D.Compilationfailsbecauseofanerroronline12.E.Compilationfailsbecauseofanerroronline13.F.Compilationfailsbecauseofanerroronline15.

针对下列程序段,需要______个测试用例才可以满足语句覆盖的要求。Switch(value){Case 0:ther=30;Break;Case 1:ther=50;Break;Case 2:ther=300;Case 3:ther=other/value;Break;Default;ther=other*value;}A) 2B) 3C) 4D) 5A.B.C.D.

针对下列程序段,需要( )个测试用例才可以满足语句覆盖的要求。switch(value){case 0:other=30;break;case 1:other=50;break;case 2:other=300;case 3:other=other/value;break;default:other=other*value;}A.2B.3C.4D.5

MySQL的case语句中可能会出现以下______关键词。A.THENB.WHENC.ELSED.OTHER

1、针对下列程序段,需要()个测试用例才可以满足语句覆盖的要求。 switch (value ) { case 0: other = 30; break; case 1: other = 50; break; case 2: other = 300; case 3: other = other/value; break; default: other = other * value; }A.2B.3C.4D.5

13、运行以下程序,输出结果是 。 void main() { char x=‘E’; switch(x) { case ‘A’: printf(“a");break; case ‘B’: printf(“b");break; default: printf(“other”); case ‘C’: printf(“c"); } }A.eB.otherC.othercD.error