有以下程序includestruct ord{ int x,y;} dt[2]={1,2,3,4};mare(){struct ord*p=dt; p 有以下程序 #include<stdio.h> struct ord { int x,y;} dt[2]={1,2,3,4}; mare() { struct ord*p=dt; printf("%d,",++p->x); printf("%d\n",++p->y); } 程序的运行结果是______。A.1,2B.2,3C.3,4D.4,1

有以下程序includestruct ord{ int x,y;} dt[2]={1,2,3,4};mare(){struct ord*p=dt; p

有以下程序 #include<stdio.h> struct ord { int x,y;} dt[2]={1,2,3,4}; mare() { struct ord*p=dt; printf("%d,",++p->x); printf("%d\n",++p->y); } 程序的运行结果是______。

A.1,2

B.2,3

C.3,4

D.4,1


相关考题:

有以下程序#include stdio.hstruct ord{ int x,y; } dt[2]={1,2,3,4};main(){ struct ord *p=dt;printf("%d,",++p-x); printf("%d\n",++p-y);}程序的运行结果是A)1,2B)2,3C)3,4D)4,1

(37)有以下程序#include stdio.hstruct ord{ int x,y;} dt[2]={1,2,3,4};main(){ struct ord *p=dt;printf (“%d,”,++p-x); printf(“%d\n”,++p-y);}程序的运行结果是A)1,2 B)2,3 C)3,4 D)4,1

以下程序的输出是( )。 struct st { int x;int *y; } *p; int dt[4]={10,20,30,40}; struct st aa[4]= {50,dt[0],60,dt[1],70,dt[2],80,dt[3]}; main() { p=aa; cout<<++p->x; cout<<(++p)->x; cout<<++(*p->y); }A.10 20 20B.50 60 21C.51 60 21D.60 70 31

以下程序的输出结果是( )。 {int x;int*y;}*p; int dt[4]={1,2,3,4}; struct st aa[4]={2,dt[0],3,dt[0],4,dt[0],5,dt[0],}; {p=aa; pfintf("%d\n",++(p->x)); }A.1B.2C.3D.4

有以下程序#includestdio.hstruct ord{int x,y;} dt[2]={1,2,3,4};main(){struct ord*p=dt;printf(“%d,”,++(p一x));printf(“%d\n”,++(p一y));}程序运行后的输出结果是A.1,2B.4,1C.3,4D.2.3

有以下程序: #includestdio.h struct ord {int X,y;)dt[2]={1,2,3,4}; main( ) { struct ord*p=dt; printf("%d,",++(p-x));printf("%d\n",++(p-y)); } 程序运行后的输出结果是( )。A.1,2B.4,1C.3,4D.2,3

以下程序的输出结果是includestruct st{ int x;int *y;}*p;int dt[4]={10,20,30,40};s 以下程序的输出结果是 #include<stdio.h> struct st { int x;int *y;}*p; int dt[4]={10,20,30,40}; struct st aa[4]={50,dt[0],60,dt[0],60,dt[0],60,dt[0],}; main() { p=aa; printf("%d\n",++(p->x));}A.10B.11C.51D.60

以下程序的输出结果是()。includestruct st{int x;int*y;}*p; int dt[4] ={ 10,20,30,4 以下程序的输出结果是( )。 #include<stdio.h> struct st { int x; int *y;} *p; int dt[4] ={ 10,20,30,40 }; struct st aa[4]={ 50,dt[0],60,dt[0],60,dt[0],60,dt[0]}; main() { p=aa; printf("%d\n",++(p->x)); }A.10B.11C.51D.60

(37)有以下程序#include stdio.hstruct ord{ int x,y;}dt[2]={1,2,3,4};main(){struct ord *p=dt;printf("%d,",++(p-x)); printf("%d\n",++(p-y));}程序运行后的输出结果是A)1,2B)4,1C)3,4D)2,3