Assumethatcountryissetforeachclass.Given:10.publicclassMoney{11.privateStringcountry,name;12.publicgetCountry(){returncountry;}13.}and:24.classYenextendsMoney{25.publicStringgetCountry(){returnsuper.country;}26.}27.28.classEuroextendsMoney{29.publicStringgetCountry(StringtimeZone){30.returnsuper.getCountry();31.}32.}Whichtwoarecorrect?()A.Yenreturnscorrectvalues.B.Euroreturnscorrectvalues.C.Anexceptionisthrownatruntime.D.YenandEurobothreturncorrectvalues.E.Compilationfailsbecauseofanerroratline25.F.Compilationfailsbecauseofanerroratline30.

Assumethatcountryissetforeachclass.Given:10.publicclassMoney{11.privateStringcountry,name;12.publicgetCountry(){returncountry;}13.}and:24.classYenextendsMoney{25.publicStringgetCountry(){returnsuper.country;}26.}27.28.classEuroextendsMoney{29.publicStringgetCountry(StringtimeZone){30.returnsuper.getCountry();31.}32.}Whichtwoarecorrect?()

A.Yenreturnscorrectvalues.

B.Euroreturnscorrectvalues.

C.Anexceptionisthrownatruntime.

D.YenandEurobothreturncorrectvalues.

E.Compilationfailsbecauseofanerroratline25.

F.Compilationfailsbecauseofanerroratline30.


相关考题:

选出正确的关系代数表达式。查询所有“外科”病区和“内科”病区的所有医生姓名; A.σName="外科"∨Name="内科"(π4(Q))B.σName="外科"∧Name="内科"(π4(Q))C.π4(σName="外科"∨Name="内科"(Q))D.π4(σName="外科"∧Name="内科"(Q))

声明一个对象,给它加上name属性和show方法显示其name值,以下代码中正确 的是( )。 Avarobj = [name:"zhangsan",show:function(){alert(name);}];Bvarobj = {name:"zhangsan",show:”alert()”};Cvarobj = {name:"zhangsan",show:function(){alert(name);}};Dvarobj = {name:"zhangsan",show:function(){alert();}};

在JavaScript中,若对象A具有Name属性,则对该属性的引用方式可以是( )。 A.Name=”a”B.A{“Name”}=”a”C.A[“Name”]=”a”D.A(Name)=”a”

Which statement adds a constraint that ensures the CUSTOMER_NAME column of the CUSTOMERS table holds a value?() A. ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;B. ALTER TABLE customers MODIFY CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;C. ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn NOT NULL;D. ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn IS NOT NULL;E. ALTER TABLE customers MODIFY name CONSTRAINT cust_name_nn NOT NULL;F. ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name NOT NULL;

Examine the structure of the EMPLOYEES table:Column name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyLAST_NAME VARCNAR2(30)FIRST_NAME VARCNAR2(30)JOB_ID NUMBERSAL NUMBERMGR_ID NUMBER References EMPLOYEE_ID column DEPARTMENT_ID NUMBERYou need to create an index called NAME_IDX on the first name and last name fields of the EMPLOYEES table. Which SQL statement would you use to perform this task? ()A. CREATE INDEX NAME _IDX (first_name, last_name);B. CREATE INDEX NAME _IDX (first_name, AND last_name)C. CREATE INDEX NAME_IDX ON (First_name, last_name);D. CREATE INDEX NAME_IDX ON employees (First_name, AND last_name);E. CREATE INDEX NAME_IDX ON employees (First_name, last_name);F. CREATE INDEX NAME_IDX FOR employees (First_name, last_name);

Which syntax turns an existing constraint on? () A. ALTER TABLE table_name ENABLE constraint_name;B. ALTER TABLE table_name STATUS = ENABLE CONSTRAINT constraint _ name;C. ALTER TABLE table_name ENABLE CONSTRAINT constraint _ name;D. ALTER TABLE table_name TURN ON CONSTRAINT constraint _ name;

html语言中,创建一个位于文档内部的锚点的语句是()。A.name=“NAME”B.name=“NAME”/nameC.aname=“NAME”/aD.aname=“NAME”/a

有以下程序段char.name[20];int num;scanf(“name=%s num=%d”,name,&num);当执行上述程序段,并从键盘输入:name=Lili num=1001回车后,name的值为A.LillB.name=LiliC.Lili.num=D.name=Lili num—1001

康唑类药品的药名词干是A.#NAME?B.#NAME?C.#NAME?D.#NAME?E.#NAME?