分析下面的JavaScript代码段,输出的结果是()。 emp=new Array(5); emp[1]=1 emp[2]=2 document.write(emp.length);A、2B、3C、4D、5

分析下面的JavaScript代码段,输出的结果是()。 emp=new Array(5); emp[1]=1 emp[2]=2 document.write(emp.length);

  • A、2
  • B、3
  • C、4
  • D、5

相关考题:

● 撤销 U5 对 Emp 表的查询权限,并收回 U5 授予其它用户的该权限,SQL 语句是 (51) 。(51)A. REVOKE SELECT ON TABLE Emp FROM U5 CASCADE;B. REVOKE SELECT ON TABLE Emp FROM U5 RESTRICT;C. REVOKE QUERY ON TABLE Emp FROM U5 CASCADE;D. GRANT SELECT ON TABLE Emp TO U5 WITH GRANT OPTION;

以下插入记录正确的( )A.insert into emp(ename,hiredate,sal) values (value1,value2,value3);B.insert into emp (ename,sal)values(value1,value2,value3);C.insert into emp (ename)values(value1,value2,value3);D.insert into emp (ename,hiredate,sal)values(value1,value2);

Which is a valid CREATE TABLE statement? () A. CREATE TABLE EMP9$# AS (empid number(2));B. CREATE TABLE EMP*123 AS (empid number(2));C. CREATE TABLE PACKAGE AS (packid number(2));D. CREATE TABLE 1EMP_TEST AS (empid number(2));

The EMP table has these columns:ENAME VARCHAR2(35)SALARY NUMBER(8,2)HIRE_DATE DATEManagement wants a list of names of employees who have been with the company for more than five years. Which SQL statement displays the required results? ()A. SELECT ENAME FROM EMP WHERE SYSDATE-HIRE_DATE 5;B. SELECT ENAME FROM EMP WHERE HIRE_DATE-SYSDATE 5;C. SELECT ENAME FROM EMP WHERE (SYSDATE_HIRE_DATE)/365 5;D. SELECT ENAME FROM EMP WHERE (SYSDATE_HIRE_DATE)*/365 5;

阅读以下说明C++代码,将应填入(n)处的字句写在对应栏内。[说明]本程序实现了雇员信息管理功能,其中封装了雇员信息及其设置、修改、删除操作。已知当输入为“Smith 31 2960.0”时,程序的输出是:姓名:Smith 年龄:31 工资:2960姓名:Smith 年龄:31 工资:3500姓名:Mary 年龄:23 工资:2500[C++程序]include <iostream.h>include <string.h>class employee{char *name; //雇员姓名short age; //年龄float salary;//工资public:employee();void set_name(char *);void set_age(short a) {age=a;}void set_salary(float s) {salary=s;}(1);~ employee(){delete[] name;}};employee::employee() { name="";age=0;salary=0.0;void employee::set_name(char *n){ name=new char[strlen(n)+1];(2) (name,n);}void employee::print(){ cout<<"姓名":"<<name<<" 年龄:"<<agc<<" 工资:" <<salary<<endl;}void main(){ char *na;short ag=0;float sa=0;(3);na=new char[10];cin>>na>>ag>>sa;emp.set_name(na);emp.set_age(ag);emp.set_salary(sa);emp.print();(4) (3500.0);emp.print();(5);emp.set_name("Mary");emp.set_age(23);emp.set_salary(2500.0);emp.print();}

( )A.π2,4 (σ8='开发部'(EMP×DEP))B.π2,4 (σ1=9(EMP σ2='开发部'(DEP)))C.π2,3 (EMP×σ2='开发部'(DEP))D.π2,3 (π1,2,4,6(EMP) σ2='开发部'(DEP))

分析下面的JavaScript代码段,输出结果是( )var mystring="I am a student";a=mystring.charAt(9);document.write(a); A.I am a stB.UC.UdentD.T

分析下面的JavaScript代码段,输出的结果是( )。emp=new Array(5);emp[1]=1;emp[2]=2;document.write(emp.length); A.2B.3C.4D.5

假设今天是2006年4月1日星期六,请问以下javascript代码输出结果是:( )var time = new Date( );document.write(time.getMonth( )); A.3B.4C.5D.4月

分析下面的JavaScript代码段,输出的结果是( )。emp=new Array(3);emp[0]=0;emp[1]=1;emp[2]=2;emp[3]=3;document.write(emp.length); A.2B.3C.4D.5

int [] my_Array;   My_Array=new int [5];   For(int count = 0 ;  count =5; count ++)    System.out.pringtln(my_Array[count]);   以上Java代码运行的结果是()  A、将1,2,3,4,5输出到屏幕B、将0,1,2,3,4输出到屏幕C、将0,1,2,3,4,5输出到屏幕D、将出现运行时异常

在JavaScript中,下列定义数组的方法正确的是()。A、emp=newArray[3];B、emp=newArray(3);C、emp=new()array;D、emp=newArray[];

分析下面的JavaScript代码段: var mystring="I am a student"; a=mystring.indexOf("am"); document.write(a); 输出结果是()。A、3B、4C、2D、1

分析下面的Javascript代码段,输出结果是() var s1=parseInt(“101中学”); document.write(s1);A、NaNB、101中学C、101D、出现脚本错误

分析下面的JavaScript代码段,输出结果是()。var a=15.59;document.write(Math.round(a));A、15B、16C、15.5D、15.4

分析下面的JavaScript代码段,输出的结果是() emp = new Array(5); emp[1]=1; emp[2]=2; document.write(emp.length);A、2B、3C、4D、5

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分析下面的Javascript代码段,输出结果是() var mystring=”I am a student”; var a=mystring.substring(9,13); document.write(a);A、studB、tudenC、udenD、udent

有如下三步操作,并且均成功执行,请选择结果() delete from emp; alter table emp add(addr varchar2(40)); rollback;A、emp表中数据处于回滚段中B、emp表中的数据被永久删除C、emp表中的数据没有变化D、原来的emp表中的数据被添加到新emp表中E、以上所述都不正确

Which is a valid CREATE TABLE statement? ()A、CREATE TABLE EMP9$# AS (empid number(2));B、CREATE TABLE EMP*123 AS (empid number(2));C、CREATE TABLE PACKAGE AS (packid number(2));D、CREATE TABLE 1EMP_TEST AS (empid number(2));

Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE You issue these statements: CREATE table new_emp ( employee_id NUMBER, name VARCHAR2(30)); INSERT INTO new_emp SELECT employee_id , last_name from employees; Savepoint s1; UPDATE new_emp set name = UPPER(name); Savepoint s2; Delete from new_emp; Rollback to s2; Delete from new_emp where employee_id =180; UPDATE new_emp set name = 'James'; Rollback to s2; UPDATE new_emp set name = 'James' WHERE employee_id =180; Rollback; At the end of this transaction, what is true?()A、You have no rows in the table.B、You have an employee with the name of James.C、You cannot roll back to the same savepoint more than once.D、Your last update fails to update any rows because employee ID 180 was already deleted.

Which SQL statement defines the FOREIGN KEY constraint on the DEPTNO column of the EMP table?()A、CREATE TABLE EMP (empno NUMBER(4), ename VARCNAR2(35), deptno NUMBER(7,2) NOT NULL CONSTRAINT emp_deptno_fk FOREIGN KEY deptno REFERENCES dept deptno);B、CREATE TABLE EMP (empno NUMBER(4), ename VARCNAR2(35), deptno NUMBER(7,2) CONSTRAINT emp_deptno_fk REFERENCES dept (deptno));C、CREATE TABLE EMP (empno NUMBER(4) ename VARCHAR2(35), deptno NUMBER(7,2) NOT NULL, CONSTRAINT emp_deptno_fk REFERENCES dept (deptno) FOREIGN KEY (deptno));D、CREATE TABLE EMP (empno NUMBER(4), ename VARCNAR2(35), deptno NUMBER(7,2) FOREIGN KEY CONSTRAINT emp deptno fk REFERENCES dept (deptno));

The EMP table has these columns: ENAME VARCHAR2(35) SALARY NUMBER(8,2) HIRE_DATE DATE Management wants a list of names of employees who have been with the company for more than five years. Which SQL statement displays the required results? ()A、SELECT ENAME FROM EMP WHERE SYSDATE-HIRE_DATE 5;B、SELECT ENAME FROM EMP WHERE HIRE_DATE-SYSDATE 5;C、SELECT ENAME FROM EMP WHERE (SYSDATE_HIRE_DATE)/365 5;D、SELECT ENAME FROM EMP WHERE (SYSDATE_HIRE_DATE)*/365 5;

单选题分析下面的JavaScript代码段: var mystring="I am a student"; a=mystring.indexOf("am"); document.write(a); 输出结果是()。A3B4C2D1

单选题分析下面的JavaScript代码段,输出的结果是()。 emp=new Array(5); emp[1]=1 emp[2]=2 document.write(emp.length);A2B3C4D5

单选题分析下面的JavaScript代码段,输出的结果是() emp = new Array(5); emp[1]=1; emp[2]=2; document.write(emp.length);A2B3C4D5

( 难度:中等)var emp = new Array(3); for(var i in emp) 以下答案中能与for循环代码互换的是:A.for(var i =0; i<emp; i++)B.for(var i =0; i<Array(3); i++)C.for(var i =0; i<emp.length(); i++)D.for(var i =0; i<emp.length; i++)