Take an umbrella with you _________ it rains.A、in any caseB、in caseC、becauseD、for
Take an umbrella with you _________ it rains.
A、in any case
B、in case
C、because
D、for
相关考题：
It is easy to ____ a machine ____ but difficult to put it together. A、tear…apartB、take …awayC、take …apartD、bring…away
现有如下程序段，此程序段编译有错误，则程序段的错误出在#includemain（）{ int a=30,b=40,c=50,d;d=a 30?b:c;switch（d）{case a:printf（"%d,",a）;case b:printf（"%d,",b）;case c:printf（"%d,",c）;default:printf（"#"）;}}A．default:printf（"#"）;这个语句B．d=a30?b:c;这个语句C．case a:printf（"%d,",a）; case b:printf（"%d,",b）; case c:printf（"%d,",c）;这三个语句D．switch（d）这个语句
10．—Could you buy_________ drinks for me?—Sorry，but I don't have _________ money．A． some， someB． any，anyC． any， someD． some，any
We don’t have ______ fruit in the house.Let me buy ______.A、any, anyB、any, someC、a little, anyD、some, any
You can ______the seat belt ____ as soon as the light overhead goes off. A.turn…onB.take…offC.take…outD.pick…out
There are ______ books in your bag. But there aren’t ______ pens in it. A、some, someB、any ,someC、some, anyD、any,any
现有如下程序段,此程序段编译有错误,则程序段的错误出在includemain(){int a=30,b=40, 现有如下程序段，此程序段编译有错误，则程序段的错误出在 #include＜stdio.h＞ main() { int a=30，b=40，c=50，d； d=a＞30? b：c； swish(d) { case a： Printf("%d，"，a)； case b： printf("%d，"，b)； case c： printf("%d，"，c)； default printf("#")；}}A．default：printf("#")；这个语句B．d=a＞30? b：c；这个语句C．case a：printf("%d，"，a)；case b：printf("%d，"，b)；case c：printf("%d，"，c)；这三个语句D．switch(d)这个语句
下列程序段的输出结果是【】。int n=c; switch(n＋＋) {default:printf(errorc；switch(n++){default:printf(error)；break；case a：case A：case b：case B：printf(good);break；case c：caseC：printf(pass)；case d：caseD：printf(warn);}
1、利用艾拉托斯特尼筛法无穷素数列表primes （参见讲义第8章) 获得介于100000和200000之间素数的方法是A．take 200000 (take 100000 primes)B．take 100000 (take 200000 primes)C．take 100000 (drop 100000 primes)D．takeWhile (\x - x = 200000) (dropWhile (\x - x = 100000) primes)E．takeWhile (\x - x = 200000) (take 200000 primes)F．[x | x - primes, x 100000, x 200000]G．[x | x - take 200000 primes, x 100000, x 200000]