I had the lonely child's habit of making up stories and holding conversations with imaginative persons.(语法上正确与否)() 此题为判断题(对，错)。
I had the lonely child's habit of making up stories and holding conversations with imaginative persons.(语法上正确与否)()
此题为判断题(对，错)。
相关考题：
I _____my breakfast at 8, but_____ I lunch yet. .A. had, haven't hadB. had, didn't haveC. have had, didn't have
From a very early age, perhaps the age of five or six, I knew that when I grew I should be a writer.(语法上正确与否)() 此题为判断题(对，错)。
Between the ages of about seventeen and twenty－four I tried to abandon this idea, but I did so with the conscience that I was outraging my true nature.(语法上正确与否)() 此题为判断题(对，错)。
The grammatical words which play so large a part in English grammar are for the most part sharply and obviously different from the lexical words.(语法上正确与否) () 此题为判断题(对，错)。
Wheat prices were generally low in the autumn, so farmers could not wait for markets to improve.(语法上正确与否)() 此题为判断题(对，错)。
阅读下列函数说明和C代码及流程图，将应填入(n)处的字句写在对应栏内[说明]分糖果问题是一个经典问题。问题描述如下：幼儿国有n(＜20)个孩子围成一圈分糖果，老师先随机地发给每个孩子若干颗糖果，然后按以下规则调整：每个孩子同时将自己手中的糖果分一半给坐在他右边的小朋友；如共有8个孩子，则第1个将原来的一半分给第2个，第2个将原有的一半分给第3个……第8个将原来的一半分给第1个，这样的平分动作同时进行；若平分前，某个孩子手中的糖果是奇数颗，则必须从老师那里要一颗，使他的糖果变成偶数。小孩人数和每个小孩的初始数由键盘输入。经过多少次调整，使每个孩子手中的糖果一样多，调整结束时每个孩子有糖果多少颗，在调整过程中老师又新增发了多少颗糖果。[C程序]include ＜stdlib.h＞include ＜stdio.h＞bool allequall (int child[], int n ) //判断各小孩子手中的糖果是否相等{for ( int i=0; i＜n-1; i++)if (child[i]!=child[i+1] )return false; //不相等返回假return true; //相等返回真}const int MaxNum=20; //定义最大人数//主函数void main ( ){int Num=0;int *child;int *child1;//构造两个相应大小的数组child代表小朋友现有的粮果数child1代表小朋友原来有的糖果数int Tnum=0;int i=0;do{printf ( "Pelase input the number of the children: ").,scanf ( "%d",Num );if ( Num＞MaxNum )printf ( "Error Number!!" );} while ( Num＞MaxNum );child=new int [Nmn];child1=new int [Num];for ( i=0; i＜Num; i++ ) //将数组赋值{printf ( "Input NO. %d child's candy numbers: ",i+1);scanf ( "%d", child[i] );}while ( (1) ){for (i=0; i＜Num; i++ ){if( (2) ){(3)Tnum++;}}for ( i=0; i＜Num; i++ )child1[i]=child[i]; //将child1赋值用来记忆原来小朋友的粮果数for ( i=0; i＜Nam; i++ )(4)for (i=0; i＜Num-1; i++)//用循环实现前一个小朋友粮果数加后一个小朋友粮果数的一半{child[i]/=2;child[i]+=child 1 [i+1];}child[Num-1]/=2;(5)}printf ( "每个同学最后分到糖果数目是%d\n", child[1]);printf ( "老师分发出的糖果是%d\n", Tnum );}图12-7是一种解决问题的流程图，请根据该流程图将对应C代码(n)处补充完整。
—Why didn't you go to the cinema yesterday?—I______, but my daughter returned from America the moment I was leaving.A. didB. wouldC. was going toD. had