—Excuse me, could you tell me which bus goes to the Fine Arts Museum? —() A、No, I can’t.B、Yes, you’re right.C、I don’t know either.D、Sorry, I don’t know.
—Excuse me, could you tell me which bus goes to the Fine Arts Museum? —()
A、No, I can’t.
B、Yes, you’re right.
C、I don’t know either.
D、Sorry, I don’t know.
相关考题：
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如图5-44所示，已知梁的弯曲刚度EI为常数，今欲使梁的挠曲线在x=l/3处出现—拐点，则比值Me1/Me2为 ( )。A.Me1/Me2=2 B. Me1/Me2= 3 C.Me1/Me2=1/2 D. Me1/Me2=1/3
Me,you是两个初始集合，则下列关于派生集合定义方式正确的是A．link/me,you/:a;B．link(me,you):a;C．link/me you/a;D．link(me,you)/a;
一跨度为l的简支梁，若仅承受一个集中力偶Me。当Me在梁上移动时，梁内产生的最大剪力FSmax和最大弯矩Mmax分别为 。A．FSmax = 0，Mmax = Me；B．FSmax = 0，Mmax = Me/2；C．FSmax = Me/l，Mmax = Me；D．FSmax ≤ Me/l，Mmax = Me/2；
3、一跨度为l的简支梁，若仅承受一个集中力偶Me。当Me在梁上移动时，梁内产生的最大剪力FSmax和最大弯矩Mmax分别为 。A．FSmax = 0，Mmax = Me；B．FSmax = 0，Mmax = Me/2；C．FSmax = Me/l，Mmax = Me；D．FSmax ≤ Me/l，Mmax = Me/2；
me是一个包含3个成员属性为a的集合，you是一个包含2个成员属性为b的集合，则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是A．ps(me,you):c;B．ps(you,me):c;C．ps(a,b):c;D．ps(b,a):c;