Evaluate this SQL statement: SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales_amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation?（）A、The value displayed in the CALC_VALUE column will be lower.B、The value displayed in the CALC_VALUE column will be higher.C、There will be no difference in the value displayed in the CALC_VALUE column.D、An error will be reported.
Evaluate this SQL statement: SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales_amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation?（）
- A、The value displayed in the CALC_VALUE column will be lower.
- B、The value displayed in the CALC_VALUE column will be higher.
- C、There will be no difference in the value displayed in the CALC_VALUE column.
- D、An error will be reported.
相关考题：
Evaluate this SQL statement:SELECT e.emp_name, d.dept_nameFROM employees eJOIN departments dUSING (department_id)WHERE d.department_id NOT IN (10,40)ORSER BY dept_name;The statement fails when executed. Which change fixes the error? （）A. remove the ORDER BY clauseB. remove the table alias prefix from the WHERE clauseC. remove the table alias from the SELECT clauseD. prefix the column in the USING clause with the table aliasE. prefix the column in the ORDER BY clause with the table aliasF. replace the condition d.department_id NOT IN (10,40) in the WHERE clause with d.department_id 10 AND d.department_id 40
Evaluate this SQL statement: SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAME FROM EMP e, DEPARTMENT d WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID; In the statement, which capabilities of a SELECT statement are performed?（）A. Selection, projection, joinB. Difference, projection, joinC. Selection, intersection, joinD. Intersection, projection, joinE. Difference, projection, product
Evaluate this SQL statement:What will happen if you remove all the parentheses from the calculation?() A. The value displayed in the CALC_VALUE column will be lower.B. The value displayed in the CALC_VALUE column will be higher.C. There will be no difference in the value displayed in the CALC_VALUE column.D. An error will be reported.
Evaluate this SQL statement:SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAMEFROM EMPLOYEES e, DEPARTMENTS dWHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID;In the statement, which capabilities of a SELECT statement are performed?（）A.selection, projection, joinB.difference, projection, joinC.selection, intersection, joinD.intersection, projection, joinE.difference, projection, product
Click the Exhibit button to examine the data of the EMPLOYEES table. Evaluate this SQL statement:SELECT e.employee_id Emp_id, e.emp_name Employee, e.salary, m.employee_id Mgr_id, m.emp_name ManagerFROM employees e JOIN employees m ON (e.mgr_id = m.employee_id)AND e.salary 4000;What is its output?（）A.AB.BC.CD.DE.E
Click the Exhibit button to examine the data of the EMPLOYEES table.Which statement lists the ID, name, and salary of the employee, and the ID and name of the employee‘s manager, for all the employees who have a manager and earn more than 4000?（）A.SELECT employee_id Emp_id, emp_name Employee, salary, employee_id Mgr_id, emp_name Manager FROM employees WHERE salary 4000;B.SELECT e.employee_id Emp_id, e.emp_name Employee, e.salary, m.employee_id Mgr_id, m.emp_name Manager FROM employees e JOIN employees m WHERE e.mgr_id = m.mgr_id AND e.salary 4000;C.SELECT e.employee_id Emp_id, e.emp_name Employee, e.salary, m.employee_id Mgr_id, m.emp_name Manager FROM employees e JOIN employees m ON (e.mgr_id = m.employee_id) AND e.salary 4000;D.SELECT e.employee_id Emp_id, e.emp_name Employee, e.salary, m.mgr_id Mgr_id, m.emp_name Manager FROM employees e SELF JOIN employees m WHERE e.mgr_id = m.employee_id AND e.salary 4000;E.SELECT e.employee_id Emp_id, e.emp_name Employee, e.salary, m.mgr_id Mgr_id m.emp_name Manager FROM employees e JOIN employees m USING (e.employee_id = m.employee_id) AND e.salary 4000;
Evaluate this SQL statement: SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAME FROM EMP e, DEPARTMENT d WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID; In the statement, which capabilities of a SELECT statement are performed?（）A、Selection, projection, joinB、Difference, projection, joinC、Selection, intersection, joinD、Intersection, projection, joinE、Difference, projection, product
You need to create a view EMP_VU. The view should allow the users to manipulate the records of only the employees that are working for departments 10 or 20.Which SQL statement would you use to create the view EMP_VU?（）A、CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);B、CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH READ ONLY;C、CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH CHECK OPTION;D、CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);E、CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) NO UPDATE;
Evaluate this SQL statement: e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales_amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation?（）A、The value displayed in the CALC_VALUE column will be lower.B、The value displayed in the CALC_VALUE column will be higher.C、There will be no difference in the value displayed in the CALC_VALUE column.D、An error will be reported.
Evaluate the SQL statement: 1 SELECT a.emp_name, a.sal, a.dept_id, b.maxsal 2 FROM employees a, 3 (SELECT dept_id, MAX(sal) maxsal 4. FROM employees 5 GROUP BY dept_id) b 6 WHERE a.dept_id = b.dept_id 7 AND a. asl b. maxsal; What is the result of the statement? （）A、The statement produces an error at line 1.B、The statement produces an error at line 3.C、The statement produces an error at line 6.D、The statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all departments that pay less salary then the maximum salary paid in the company.E、The statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all employees who earn less than the maximum salary in their department.
The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）A、All of the desired resultsB、Two of the desired resultsC、One of the desired resultsD、An error statement
Examine the structures of the EMPLOYEES and TAX tables. EMPLOYEES EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER References MGR_ID NUMBER EMPLOYEE_ID column DEPARTMENT_ID NUMBER Foreign key to DEPARTMENT _ID column of the DEPARTMENT table TAX MIN_SALARY NUMBER MAX_SALARY NUMBER TAX_PERCENT NUMBER Percentage tax for given salary range You need to find the percentage tax applicable for each employee. Which SQL statement would you use?（）A、SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE e.salary BETWEEN t.min _ salary AND t.max_salaryB、SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE e.salary t.min_salary, tax_percentC、SELECT employee_id, salary, tax_percent FROM employees e, tax t WHERE MIN(e.salary) = t.min_salary AND MAX(e.salary) = t.max_salaryD、You cannot find the information because there is no common column between the two tables.
You need to display the last names of those employees who have the letter "A" as the second character in their names. Which SQL statement displays the required results? （）A、SELECT last_name FROM EMP WHERE last_ name LIKE '_A%';B、SELECT last_name FROM EMP WHERE last name ='*A%'C、SELECT last_name FROM EMP WHERE last name ='_A%';D、SELECT last_name FROM EMP WHERE last name LIKE '*A%'
Evaluate this SQL statement: SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAME FROM EMP e, DEPARTMENT d WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID; In the statement, which capabilities of a SELECT statement are performed?（）A、Selection, projection, joinB、Difference, projection, joinC、Selection, intersection, joinD、Intersection, projection, joinE、Difference, projection, product
Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?（）A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C、SELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E、SELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));
Evaluate this SQL statement: SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation? （）A、The value displayed in the CALC_VALUE column will be lower.B、The value displayed in the CALC_VALUE column will be higher.C、There will be no difference in the value displayed in the CALC_VALUE column.D、An error will be reported.
Evaluate this SQL statement: SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAME FROM EMPLOYEES e, DEPARTMENTS d WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID; In the statement, which capabilities of a SELECT statement are performed?（）A、selection, projection, joinB、difference, projection, joinC、selection, intersection, joinD、intersection, projection, joinE、difference, projection, product
You need to create a view EMP_VU. The view should allow the users to manipulate the records of only the employees that are working for departments 10 or 20. Which SQL statement would you use to create the view EMP_VU? （）A、CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department _ id IN (10,20);B、CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH READ ONLY;C、CREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH CHECK OPTION;D、CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WITH department_id IN (10,20);E、CREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) NO UPDATE;
单选题Evaluate this SQL statement: SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales_amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation?（）AThe value displayed in the CALC_VALUE column will be lower.BThe value displayed in the CALC_VALUE column will be higher.CThere will be no difference in the value displayed in the CALC_VALUE column.DAn error will be reported.
单选题Evaluate the SQL statement: 1 SELECT a.emp_name, a.sal, a.dept_id, b.maxsal 2 FROM employees a, 3 (SELECT dept_id, MAX(sal) maxsal 4. FROM employees 5 GROUP BY dept_id) b 6 WHERE a.dept_id = b.dept_id 7 AND a. asl b. maxsal; What is the result of the statement?（）AThe statement produces an error at line 1.BThe statement produces an error at line 3.CThe statement produces an error at line 6.DThe statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all departments that pay less salary then the maximum salary paid in the company.EThe statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all employees who earn less than the maximum salary in their department.
单选题Evaluate this SQL statement: SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAME FROM EMP e, DEPARTMENT d WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID; In the statement, which capabilities of a SELECT statement are performed?（）ASelection, projection, joinBDifference, projection, joinCSelection, intersection, joinDIntersection, projection, joinEDifference, projection, product
单选题Evaluate this SQL statement: SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation? （）AThe value displayed in the CALC_VALUE column will be lower.BThe value displayed in the CALC_VALUE column will be higher.CThere will be no difference in the value displayed in the CALC_VALUE column.DAn error will be reported.
单选题You need to create a view EMP_VU. The view should allow the users to manipulate the records of only the employees that are working for departments 10 or 20. Which SQL statement would you use to create the view EMP_VU?（）ACREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);BCREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH READ ONLY;CCREATE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) WITH CHECK OPTION;DCREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20);ECREATE FORCE VIEW emp_vu AS SELECT * FROM employees WHERE department_id IN (10,20) NO UPDATE;
单选题Evaluate this SQL statement: SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation? （）AThe value displayed in the CALC_VALUE column will be lower.BThe value displayed in the CALC_VALUE column will be higher.CThere will be no difference in the value displayed in the CALC_VALUE column.DAn error will be reported.
单选题Evaluate this SQL statement: What will happen if you remove all the parentheses from the calculation?（）A The value displayed in the CALC_VALUE column will be lower.B The value displayed in the CALC_VALUE column will be higher.C There will be no difference in the value displayed in the CALC_VALUE column.D An error will be reported.
单选题Evaluate this SQL statement: e.employee_id, (.15* e.salary) + (.5 * e.commission_pct) + (s.sales_amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id; What will happen if you remove all the parentheses from the calculation?（）AThe value displayed in the CALC_VALUE column will be lower.BThe value displayed in the CALC_VALUE column will be higher.CThere will be no difference in the value displayed in the CALC_VALUE column.DAn error will be reported.
单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）AAll of the desired resultsBTwo of the desired resultsCOne of the desired resultsDAn error statement