class Base {  Base() { System.out.print(“Base”); }  }  public class Alpha extends Base {  public static void main( String[] args ) {  new Alpha();  new Base();  }  }  What is the result?()  A、 BaseB、 BaseBaseC、 Compilation fails.D、 The code runs with no output.E、 An exception is thrown at runtime.

class Base {  Base() { System.out.print(“Base”); }  }  public class Alpha extends Base {  public static void main( String[] args ) {  new Alpha();  new Base();  }  }  What is the result?()  

  • A、 Base
  • B、 BaseBase
  • C、 Compilation fails.
  • D、 The code runs with no output.
  • E、 An exception is thrown at runtime.

相关考题:

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有如下程序:includeusing namespace std;Class Base{public:Base(){cout 有如下程序: #include<iostream.h> using namespace std; Class Base { public: Base(){cout<<“BB”;f();} void{(){cout<<“BF”;} }; class Derived:public Base { public: Derived(){cout<<“DD”;} void f(){cout<<“Df”;) }; int mainA.BBBfDDB.BBDfDDDfC.DDD.DDBBBf

下面程序的输出结果为:Base:: fun,请将程序补充完整。include class Base{public: 【】 下面程序的输出结果为:Base:: fun,请将程序补充完整。include <iostream.h>class Base{public:【 】 fun(){cout<<"Base::fun"<<end1:}class Derived : public Base{public:【 】 fun(){ cout<<"Derived::fun"<<end1; }};int main(){Base a,*pb;Derived b;pb = b;pb->fun();return 0;}

以下程序的执行结果为______。include using namespace std; class base { public: vir 以下程序的执行结果为______。include<iostream>using namespace std;class base{public:virtual void who(){cout<<"base class"<<endl;}};class derivel:public base{public:void who(){cout<<"d

Given:Which statement is true about the class of an object that can reference the variable base? () A.It can be any class.B.No class has access to base.C.The class must belong to the geometry package.D.The class must be a subclass of the class Hypotenuse.

下面程序的运行结果是()。includeclass base{protected:int a;public:base(){cout 下面程序的运行结果是( )。 #include<iostream.h> class base{ protected: int a; public: base(){cout<<“0”;} }; Class basel:Virtual base{ public: basel(){cout<<“1”;} }; Class base2:virtual base{ public: base2(){cout<<“2”;)A.0123B.3120C.0312D.3012

有如下程序: include using namespace std; class BASE { public 有如下程序: #include<iostream> using namespace std; class BASE { public: ~BASE(){cout<<"BASE";} }; class DERIVED:public BASE { public: ~DERIVED(){cout<<"DERIVED";} }; int main(){DERIVEDx;retum 0;} 执行后的输出结果是A.BASEB.DERIVEDC.BASEDERIVEDD.DERIVEDBASE

有如下程序:includeusing namespace std;class Base{protected:Base(){cout 有如下程序: #include<iostream> using namespace std; class Base{ protected: Base(){cout<<'Base';} Base(char c){cout<<c;} }; class Derived:public Base{ public: Derived(char c){cout<<c;} }; int main(){ Derived d('Derived'); return 0; } 执行这个程序屏幕上将显示输出( )。A.DerivedB.DerivedBaseC.BaseDerivedD.DerivedDerived

有以下程序:include using namespace std; class Base { public: Base() { K=0; } int 有以下程序:include<iostream>using namespace std;class Base{public:Base(){K=0;}int x;};class Derivedl:virtual public Base{public:Derivedl(){x=10;}};class Derived2:virtua1 public Base

有如下程序:include using namespace std;class BASE{public:~BASE(){cout 有如下程序: #include <iostream> using namespace std; class BASE{ public: ~BASE(){cout<<"BASE";} }; class DERIVED:public BASE{ public: ~DERIVED(){cout<<"DERIVED";} }; int main(){DERIVED x;return 0;} 执行后的输出结果是A.BASEB.DERIVEDC.BASEDERIVEDD.DERIVEDBASE

有如下程序:includeusing namespace std;class BASE{public:~BASE( ){cout 有如下程序: #include<iostream> using namespace std; class BASE{ public: ~BASE( ){cout<<"BASE";} }; class DERIVED:public BASE{ public: ~DERIVED( ){cout<<"DERIVED";} }; int main( ){DERIVED x;return 0;} 程序的输出结果是A.BASEB.DERIVEDC.BASEDERIVEDD.DERIVEDBASE

下面程序的输出结果是【】。include using namespace std; class base { protected: int 下面程序的输出结果是【 】。include <iostream>using namespace std;class base{protected:int a;public:base(){cout<<"0":}};class basel: virtual public base{public:base1(){ cout<<"1";}};class base2 : virtual public base{public:base2(){cout<<"2";}};class derived : public base1,public base2{public:derived () {cout<<"3"; }}int main (){derived obj;cout<<end1;return 0;}

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若有以下程序: include using namespace std; class Base { public:void who(){ cout 若有以下程序:include <iostream>using namespace std;class Base{public:void who(){cout<<"class Base"<<end1;}};class Derivedl : public Base{public:void who(){cout<<"class Derivedl"<<end1;}};class Derived2 : public Base{public:void who(){cout<<"class Derived2"<<end1;}};int main(){Base *p;Derivedl obj1;Derived2 obi2;p=obj 1;p=obj2;p->who ( );return 0;}则该程序运行后的输出结果是【 】。

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若有以下程序:include using namespace std;class Base{private: int a,b;public: Ba 若有以下程序: #include <iostream> using namespace std; class Base { private: int a,b; public: Base(int x, int y) { a=x; b=y; } void show() { cout<<a<<", "<<b<<end1; } }; class Derive : public Base { private: int c, d; public: Derive(int x, int y, int z,int m):Base(x,y) { c=z; d=m; } void show() { cout<<c<<", "<<d<<end1; } }; int main ( ) { Base b(50,50) ,*pb; Derive d(10,20,30,40); pb=d; pb->show {); return 0; }A.10,20B.30,40C.20,30D.50,50

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有如下程序includeusing namespace std;class Base{protected:Base(){cout 有如下程序 #include<iostream> using namespace std; class Base{ protected: Base(){cout<<'A';} Base(char c){cout<<c;) }; class Derived: public Base{ public: Derived(char c){cout<<c;) }; int main(){ Derived dl('B'); return 0; } 执行这个程序屏幕上将显示输出( )。A.BB.BAC.ABD.BB

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下面程序的运行结果是includeclass base{protected: int a;public: base(){cout 下面程序的运行结果是 #include<iostream.h> class base{ protected: int a; public: base(){cout <<"0";} }; class basel:virtual base{ public: basel () {cout <<"1";} }; class base2:virtual base{ public: base2(){cout <<"2";} }; class derived:public basel,public base2{ public: derived(){cout <<"3";} }; void main() { derived obj; cout <<end1; }A.123B.3120C.312D.3012

下列程序的运行结果是______。 include class Base { public: virtual void func(int 下列程序的运行结果是______。include<iostream.h>class Base{public:virtual void func(int i){cout<<"class Base:"<<i<<end1;)};class Derived: public Base{public:void func(double d){cout<<"class Derived:"<<d<<endl;}};void main( ){Base a,*p=a;Derived b;p=b;(*p).func(3.3);}

package geometry;  public class Hypotenuse {  public InnerTriangle it = new InnerTriangle();  class InnerTriangle {  public int base;  public int height;  }  }  Which is true about the class of an object that can reference the variable base? ()A、 It can be any class.B、 No class has access to base.C、 The class must belong to the geometry package.D、 The class must be a subclass of the class Hypotenuse.

单选题package geometry;  public class Hypotenuse {  public InnerTriangle it = new InnerTriangle();  class InnerTriangle {  public int base;  public int height;  }  }  Which is true about the class of an object that can reference the variable base? ()A It can be any class.B No class has access to base.C The class must belong to the geometry package.D The class must be a subclass of the class Hypotenuse.