package geometry;  public class Hypotenuse {  public InnerTriangle it = new InnerTriangle();  class InnerTriangle {  public int base;  public int height;  }  }  Which is true about the class of an object that can reference the variable base? ()A、 It can be any class.B、 No class has access to base.C、 The class must belong to the geometry package.D、 The class must be a subclass of the class Hypotenuse.

package geometry;  public class Hypotenuse {  public InnerTriangle it = new InnerTriangle();  class InnerTriangle {  public int base;  public int height;  }  }  Which is true about the class of an object that can reference the variable base? ()

  • A、 It can be any class.
  • B、 No class has access to base.
  • C、 The class must belong to the geometry package.
  • D、 The class must be a subclass of the class Hypotenuse.

相关考题:

有以下程序: included using namespace std; class Base { public: Base( ) { x=0; } 有以下程序:included<iostream>using namespace std;class Base{public:Base( ){x=0;}int x;};class Derived1:virtual public Base{public:Derived1( ){x=10;}};class Derived2:virtual public Base{public:Derived2( ){x=20;}};class Derived: public Derived1,protected Derived2{ };int main( ){Derived obj;cout<<obj. x<<endl;return 0;}该程序运行后的输出结果是______。

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有如下程序: include using namespace std; class Base { public: 有如下程序: #include <iostream> using namespace std; class Base { public: Base(int x=0) { cout<<x; } } class Derived: public Base{ public: Derived(int x=0) { cout<<x; } private: Base val; }; int main() { Derived d(1); return 0; }程序的输出结果是A.0B.1C.1D.1

已知如下类定义: class Base { public Base (){ //... } public Base ( int m ){ //... } protected void fun( int n ){ //... } } public class Child extends Base{ // member methods } 如下哪句可以正确地加入子类中?() A.private void fun( int n ){ //...}B.void fun ( int n ){ //... }C.protected void fun ( int n ) { //... }D.public void fun ( int n ) { //... }

Given:Which statement is true about the class of an object that can reference the variable base? () A.It can be any class.B.No class has access to base.C.The class must belong to the geometry package.D.The class must be a subclass of the class Hypotenuse.

下面程序的运行结果是()。includeclass base{protected:int a;public:base(){cout 下面程序的运行结果是( )。 #include<iostream.h> class base{ protected: int a; public: base(){cout<<“0”;} }; Class basel:Virtual base{ public: basel(){cout<<“1”;} }; Class base2:virtual base{ public: base2(){cout<<“2”;)A.0123B.3120C.0312D.3012

有如下程序:includeusing namespace std;class Base{public:Base(int x=0){cout 有如下程序: #include<iostream> using namespace std; class Base{ public: Base(int x=0){cout<<x;} }; class Derived:public Base{ public: Derived(int x=0){cout<<x;} private: Base val; }; int main( ){ Derived d(1); return 0; } 程序的输出结果是A.0B.1C.01D.001

有以下程序:include using namespace std; class Base { public: Base() { K=0; } int 有以下程序:include<iostream>using namespace std;class Base{public:Base(){K=0;}int x;};class Derivedl:virtual public Base{public:Derivedl(){x=10;}};class Derived2:virtua1 public Base

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有以下程序 include using namespace std; class Base { int a; public: Base(int x) 有以下程序include <iostream>using namespace std;class Base{int a;public:Base(int x){ a=x; }void show(){ cout<<a; }class Derived : public Base{int b;public:Derived(int i) :Base(i+1),b(i){}void show() { cout<<b;};int main (){Base b(5),*pb;Derived d(1);pb=d;pb->show ();return 0;}运行后的打印结果是______。

下面程序的运行结果是includeclass base{protected:int a;public:base( ){cout 下面程序的运行结果是 #include<iostream.h> class base{ protected: int a; public: base( ){cout<<"0";} }; class basel:virtual base { public: base1( ){cout<<"1";} }; class base2:virtual base{ public:A.123B.3120C.312D.3012

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下列程序的输出结果是______。 include class base { int x,y; public: base(int i,i 下列程序的输出结果是______。include<iostream.h>class base{int x,y;public:base(int i,int j){x=i;y=j;}virtual int add( ){return x+y;}};class three:public base{int z;public:three(int i,int j,int k):base(i,j){z=k;)int add( ){return(base::add( )+z);}};void main( ){three*q=new three(10,20,30);cout<<q->add( )<<endl;}

package foo;  public class Outer {  public static class Inner {  }  }   Which statement is true?() A、 Compilation fails.B、 An instance of the Inner class can be constructed with “new Outer.Inner()”.C、 An instance of the Inner class cannot be constructed outside of package foo.D、 An instance of the Inner class can be constructed only from within the Outer class.E、 From within the package foo, and instance of the Inner class can be constructed with “new Inner()”.

package foo; public class Outer (  public static class Inner (  )  )   Which statement is true? () A、 An instance of the Inner class can be constructed with “new Outer.Inner ()”B、 An instance of the inner class cannot be constructed outside of package foo.C、 An instance of the inner class can only be constructed from within the outer class.D、 From within the package bar, an instance of the inner class can be constructed with “new inner()”

public class Parent {     int change() {…}     }  class Child extends Parent {     }  Which methods can be added into class Child?()    A、 public int change(){}B、 int chang(int i){}C、 private int change(){}D、 abstract int chang(){}

单选题package geometry;  public class Hypotenuse {  public InnerTriangle it = new InnerTriangle();  class InnerTriangle {  public int base;  public int height;  }  }  Which is true about the class of an object that can reference the variable base? ()A It can be any class.B No class has access to base.C The class must belong to the geometry package.D The class must be a subclass of the class Hypotenuse.

单选题package foo;  public class Outer {  public static class Inner {  }  }   Which statement is true?()A Compilation fails.B An instance of the Inner class can be constructed with “new Outer.Inner()”.C An instance of the Inner class cannot be constructed outside of package foo.D An instance of the Inner class can be constructed only from within the Outer class.E From within the package foo, and instance of the Inner class can be constructed with “new Inner()”.