SN10-10型开关生跳闸时发和跃合不上闸其原因可能是()。A、辅助开关合闸接点打开晚B、辅助开关合闸接点打开早C、辅助开关合闸接点未接通

SN10-10型开关生跳闸时发和跃合不上闸其原因可能是()。

  • A、辅助开关合闸接点打开晚
  • B、辅助开关合闸接点打开早
  • C、辅助开关合闸接点未接通

相关考题:

有以下程序:int sub(int n) { return(n/10+n%10); }void main(){ int x,y; scanf("%d",x); y=sub(sub(sub(x))); printf("%d\n",y);}若运行时输入:4321回车,程序的输出结果是。

单击命令按钮时,下列程序的执行结果为( )。 Private Sub Commandl_Click() Dimx As Integer,y As Integer x=12: y=32 CallPCS(x,y) PrintX;y End Sub PubUc Sub PCS(ByValn As Integer,ByValm As Integer) n=nMod 10 m=mMod 10 End SubA.1232B.232C.23D.123

在窗体上画两个标签和一个命令按钮,其名称分别为Labell、Label2和Command1,然后编写如下程序: Private Sub func(L As Label,ByVal a As Integer) L.Caption="1234" a=a*a End Sub Private Sub Form_Load() Label1.Caption="ABCD" Label2.Caption=10 End Sub Private Sub Command1_Click() a=Val(Label2.Caption) Call func(Labell,A)Label2.Caption=a End Sub 程序运行后,单击命令按钮,在两个标签Label1和Label2中显示的内容分别是 ______。A.ABCD和10B.1234和100C.ABCD和100D.1234和10

下列程序实现的功能是:在窗体上单击时,将在窗体上输出c:=a1.txt文件中的所有小写字母。Private Sub Form. Click()Dim Ch As String * 1Open "c:\a1.txt" For Input As 10Do While【 】Ch= Input(1, 10)If 【 】ThenPrint Ch;End IfLoop【 】End Sub

设程序中有如下数组定义和过程调用语句: Dim a(10)As Integer … Call D(a) 如下过程定义巾,正确的是( )。A.Private Sub p(a As Integer)B.Private Sub p(a( )As Integer)C.Private Sub p(a(10)As Integer)D.Private Sub p(a(n)As Integer)

在窗体上画两个标签和一个命令按钮,其名称分别为Label1、Label2和Command1,然后编写下列程序: Private Sub rune(L AS Labe1) Caption="1234" End Sub Private Sub Form. Load( ) Labe11.Caption="ABCDE" Labe12.Caption=10 End Sub Private Sub Command1Click( ) a=Va1(Label2.Caption) Call func(Label1) Label2.Caption a End Sub 程序运行后,单击命令按钮,则在两个标签中显示的内容分别为( )。A.ABCD和10B.1234和100C.ABCD和100D.1234和10

Command1_Click()事件代码如下: Private Sub Command1_Click() Dim x As Integer, Y As Integer x = 6 : Y : 8 Call ABC(X, Y) Print X; Y End Sub Private Sub ABC(ByVal X As Integer,Y As Integer) X = X + 4 Y = Y = 2 End Sub 事件发生后,X和Y的值分别为 ______。A.6, 8B.10, 10C.10, 8D.6, 10

有以下程序:int sub(int n) { return(n/10+n%10); }main(){ int x, y;scanf("% d", x);y=sub(sub(sub(x)));printf("% d\n", y);}若运行时输入:1234<回车>,程序的输出结果是【 】。

下列程序计算Sn的值。Sn=a+aa+aaa+…a,其中最后一项为n个。例如:a=5,n=4时,则Sn=5+55+555+5555。请在空白处填入适当的内容,将程序补充完整。Private Sub Command1_Click( )Dim a As Integer, n As Integer, Cout As IntegerDim Sn As Long, Tn As LongCout = 1Sn =0Tn =0a = InputBox("请输入a的值:" )【 】DoTn =Tn * 10 + aSn = Sn + TnCout = Cout + 1【 】Debug. Print a, n, SnEnd Sub

当Form1_Click事件发生时,写出在窗体上显示的第二行和第三行是( )。 Private a As Integer,c As Integer Private Sub Form_Click() Dim a As Integer,b As Integer a=10:b=10:c=10 Print a,b,c Call test1(a,B)Print a,b,c End Sub Private Sub test1(m As Integer,ByVal n As Integer) Dim c As Integer m=5:n=5:c=5 Print m,n,c End SubA.5 5 5 5 10 10B.5 5 5 5 5 10C.5 5 10 5 10 10D.5 5 5 10 10 10

在窗体上画两个标签和一个命令按钮,其名称分别为Labe11、Labe12和Command1,然后编写如下程序: Private SUb fune(L As Label,By Val a As Integer) L.Caption="1234" a=a*a End Sub Private Sub Form. Load() LabeCaptlon="ABCD" LabeCapfion=10 End Sub Private SUb Command1_Click() a=Val(Label2.Caption) Callfunc(Labell,A)LabeCaption=a End Sub 程序运行后,单击命令按钮,在两个标签Labe11和Labe12中显示的内容分别是______。A.ABCD和10B.1234和100C.ABCD和100D.1234和10

有以下程序int sub(int n){ return(n%10+n/10); }main(){ int x,y; scanf("%d",x); y=sub(sub(x)); printf("%d\n",y);}若运行时输入:248回车,程序的输出结果是

单击一次命令按钮之后,窗体中的输出结果为______。 Private Sub Command1_ Click() Dim a As Single Dim b As Single a = 10 b = 20 Call Num(a,B)Print a, b End Sub Sub Num(a,B)t = a a = b / t b = t End SubA.20 10B.10 20C.2 10D.10 10

单击窗体上的命令按钮Command1,【 】Private Sub Command1_Click()a= "10"b=20c=Val(A)+bPrint cEnd Sub

设程序中有如下数组定义和过程调用语句:Dim a(10) as integer……Call p(a)如下过程定义中,正确的是A)Private Sub p(a as integer)B)Private Sub p(a() as integer)C)Private Sub p(a(10) as integer)D)Private Sub p(a(n) as integer)

假定在窗体中的通用声明段已经定义有如下的子过程: Sub fix As Single,Y As Single)t=xx=yy=xEnd Sub在窗体上添加一个命令按钮(名为Commandl),然后编写如下事件过程: Private Sub Commandl_Click( ) a=10b=20f(a,B. MsgBox a&bEnd Sub打开窗体运行后,单击命令按钮,消息框输出的值分别为( )。A.20和10B.10和20C.10和10D.20和20

假定在窗体中的通用声明段已经定义有如下的子过程: Subf(x As Single,y As Single) t=x x=y y=x End Sub 在窗体上添加一个命令按钮(名为Commandl),然后编写如下事件过程: Pfivme Sub Commandl_Click() a=10 b=20 f(a,B) MsgBox ab End Sub 打开窗体运行后,单击命令按钮,消息框输出的值分别为( )A.20和10B.10和20C.10和10D.20和20

现有如下Sub过程: Sub fun(x es single,y as single) t = x x = t/y y = t mod y End sub在窗体上添加命令按钮(cmD) ,编写如下事件过程: Private sub cmd_click( ) Dim a as single Dim b as single a = 5 b = 4 fun a, b Msgbox a chr(10) + chr(13) b End sub运行程序后,单击按钮,则在消息框中显示的内容为( )A.1和1B.1.25和1C.1.25和4D.5和4

下列关于SuperVLAN的配置,正确的是()。 A.设置VLAN 10的类型为Super VLAN:[Quidway]supervlan 10B.创建Sub VLAN 20:[Quidway]vlan 20C.配置Super VLAN 10和Sub VLAN 20间的映射关系:[Quidway-vlan10]subvlan 20D.显示Super VLAN和Sub VLAN之间的映射关系:[Quidway]display supervlan 10

在窗体上画一个名称为Commandl的命令按钮,然后编写如下事件过程: Private Sub Command1_Click() Dim x As Integer,y As Integer x = 41: y = 54 Call sub1(x,y) x = x + 1 Print x; y End Sub Private Sub sub1(n As Integer, ByVal m As Integer) n=n Mod 10 m=m\10 End Sub 程序运行后,单击命令按钮,则窗体上显示的内容是A.41 54B.2 54C.1 3D.42 3

说出SN10-ⅠⅡ型油开关行程。

10kV及以下线路故障越级跳闸,如果10kV各路出线无保护动作时,应拉开10kV各路出线,试发跳闸开关后,逐路试发10kV出线开关并将试发结果报告调度。

SN10-10型断路器配CD10型电磁操动机构合不上闸及合闸速度偏低的原因是什么?如何处理?

单选题SN10-10型开关生跳闸时发和跃合不上闸其原因可能是()。A辅助开关合闸接点打开晚B辅助开关合闸接点打开早C辅助开关合闸接点未接通

单选题下列测量结果的表示中,错误的是()。ApIsubS/sub=10.0413A,Usubrel/sub=5×10sup-5/sup,k=2 /pBpIsubS/sub=10.0413(1±5×10sup-5/sup)A,k=2 /pCpIsubS/sub=(10.0413±5×10sup-5/sup)A,k=2 /pDpIsubS/sub=10.0413A,Usub95rel/sub=5×10sup-5/sup,Vsubeff/sub=9 /p

单选题标称值为10kΩ的标准电阻在23℃时的校准值Rs为9.9999315kΩ,合成标准不确定度为52mΩ。在被测量服从正态分布的情况下,当包含概率为95%时,测量结果可表示为( )。ApRsubs/sub=9.99993kΩ,Usub95/sub=0.10Ω,ksub95/sub=1.96/pBpRsubs/sub=9.999931kΩ,Usub95/sub=0.10Ω,ksub95/sub=1.96/pCpRsubs/sub=9.99993kΩ,Usub95/sub=102mΩ,ksub95/sub=1.96/pDpRsubs/sub=9.999931kΩ,Usub95/sub=102mΩ,ksub95/sub=1.96/p

单选题根据《环境影响评价技术导则大气环境》,以下评价等级正确的是( )A pPsubmax/sub≥10%为一级评价/pB pPsubmax/sub≥80%为一级评价/pC pPsubmax/sub≤10%为三级评价/pD p 10%≤Psubmax/sub≤80%为二级评价/p