根据i=Imsinφt可知()。A、任一时刻i总大于0B、任一时刻i总小于0C、i值在0~Im之间变化D、i值-Im~Im之间变化

根据i=Imsinφt可知()。

  • A、任一时刻i总大于0
  • B、任一时刻i总小于0
  • C、i值在0~Im之间变化
  • D、i值-Im~Im之间变化

相关考题:

下面程序段的运行结果是【 】。Option Base 1Private Sub swap(a()As InteSer)For I=1 to 10\2t=a(i)a(i)=a(10-1+1)a(10-1+1)=tNext1End SubPrivate Sub Form_Click()Dim x(10)As IntegerFor I=1 to 10x(i)=I*2Next1Swap x()For1=1 to 10Print x (i)Next IEnd Sub

有一过程如下:Sub Sub1(m As Integer,total As Long)Dim i As Integertotal=1For i=1 To mtotal=total*iNextEnd Sub调用它的事件过程如下:Private Sub Command1_Click()Dim tot As Long,a As Integera=Val(InputBox("请输入数据"))Call Sub1(a,tot)Print totEnd Sub则输入数据5,运行结果为【 】。

下面是用冒泡法将5个整数按升序排列,请将程序补充完整。Sub GASR()Dim mm=Array(10, 1, 5, 6, 7)For i=0 To 3For j= 【13】If m(i) =m(j) Then【14】m(i) =m(j)m(j) =tEnd IfNext j【15】For i=0 To 4Print m(i)Next iEnd Sub

在窗体上画一个命令按钮,然后编写如下事件过程:Sub BTC(oldCopy() As Integer, newCopy() As Integer)Dim i As IntegerFor i=LBound(oldCopy() ) To UBound(oldCopy() )newCopy(i) =oldCopy(i)Next iEnd SubPrivate Sub Command1_Click()Dim m(10) As Integer, n(10) As IntegerFor i=1 To 10m(i) =i  iNext iCall BTC(m, n)Print n(5)End Sub程序运行后,单击命令按钮输出结果为( )。A.0B.2C.10D.25

程序执行结果s的值是【 】.Private Sub Command l-Click ()I =0DoS= I +SI = I + lLoop Until I >=4End Sub

阅读程序: Sub p( b () As Integer)For i =1To 4 b(i) = 2(iNext i End Sub Private Sub Command1_Click()Dim a (1 To 4) As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 call p (a) For i=1 To 4 Print a(i) Next iEnd Sub运行上面的程序,单击命令按钮,输出结果为。

下面程序段的运行结果是【 】。Option Base 1Private Sub Swap (a() As IntegFor I=1 to 10\2t=a(I)a(I)=a(10-I+1)a(10-I+1)=tNext IEnd SubPrivate Sub Form_Click()Dim x(10) As IntegerFor I=1 to 10x(I)=I*2Next ISwap x()For I=1 to 10Print x(I)Next IEnd Sub

下面程序的输出结果是【 】。Private Sub Form_Click()i=0Do Until 0i=i+1if i>10 then Exit DoLoopPrint iEnd Sub

有如下程序: Private Sub Commandl_Click( ) Dim i As Integer For i=1 To 2 DS Next i End Sub Sub DS( ) Dim x As Integer,m As String Static y,n X=X + 1 y=y + 1 m=m "*”:n=n"#" Print x,y,m,n End Sub 程序运行后,输出的结果是A.1 1 * #B.1 1 * #C.1 1 * # 1 1 * # 1 2 * #D.1 1 * # 1 1 * ## 1 2 * ##

以下能够正确计算n!的程序是A.Private Sub Command1 Click() n=5:x=1 Do x=x * I I=I + 1 Loop While I < n Print x End SubB.Private Sub Command1_Click() n=5:X=1:I=1 Do X=X*I I=I + 1 Loop While I <n Print x End SubC.Private Sub Command1_Click() n=5:X=1:I=1 Do X=X * I I=I + 1 Loop While I<=n Print X End SubD.Private Sub Command1_Click() n=5:X=1:I=1 Do x=x * I I=I + 1 Loop While I>n Print X End Sub

以下程序的运行结果是( ) #define MAX 10 int a[MAX],i; main() { printf("\n");sub1();sub3(A) ,sub2(),sub3(A) ; } sub2() { int a[MAX],i,max; max=5; for(i=0;i<max;i++)a[i]=i; } sub1() {for(i=0;i<MAX;i++)a[i]=i+i; } sub3(int a[]) { int i; for(i=0;i<MAX,i++)printf("%d",a[i]); printf("\n"); }A.0 2 4 6 8 10 12 14 16 18 0 1 2 3 4B.0 1 2 3 4 0 2 4 6 8 10 12 14 16 18C.0 1 2 3 4 5 6 7 8 9 0 1 2 3 4D.0 2 4 6 8 10 12 14 16 18 0 2 4 6 8 10 12 14 16 18

有如下事件过程:Private Sub Form. Active ( )Dim Score (1 to 3) As IntegerDim i As IntegerDim t As VariantFori=3 To 1 step-1Score (i) = 2 * iNextFor Each t In ScorePrint tNextEnd Sub程序运行后窗体上显示的值为【 】。

下面程序的输出结果是( )。 #include"stdio.h" int sub(int m) { static a=4; a+=m; return a; } void main() { int i=2,j=1,k; k=sub(i); k=sub(j); printf("%d",k); }A.6B.7C.8D.9

在窗体上画一个名称为Command1的命令按钮,然后编写如下事件过程: Private Sub Command1 Click() a = 2 For i=1 To 3 Call funl(i,A)Next i x = i + 2 Print x;a End Sub Private Sub fun1(n,m) m=m + n * 2 n = n + m End Sub 程序运行后,单击命令按钮,则窗体上显示的内容是A.1 5B.4 5C.8 4D.3 4

下面程序段,运行后的结果是 Private Sub Commandl_Click( ) Dim b%(1 To 4),i%,t# For i=1 To 4 b(i)=i Next i t=Tof(b( ) ) Print"t=";t, End Sub Function Tof(a() As Integer) Dim t#,i% t=1 For i=2 To UBound(A)t=t * a(i) Next i Tof=t End FunctionA.t=18B.t=24C.t=30D.t=32

下面程序段,运行后的结果是 Private Sub Command1_Click() Dim b%(1 To 4),i%,t# For i=1 To 4 b(i) =i Next t=Tof(b() ) Print"t=";t, End Sub Function Tof(a() As Integer) Dim t#,i% t=1 For i=2 To UBound(a) t=t*a(i) Next Tof=t End FunctionA.t=18B.t=24C.t=30D.t=32

在窗体上画一个名称为CoilTlilandl的命令按钮,然后编写如下事件过程: Private Sub command1 Click() Dim m As Integer, i As Integer, x(3)As Integer For i=0 To 3:x(i)=i:Next i For i = 1 To 2: Call sub1(x,i):Next i For i = 0 To 3: Print x(i);: Next i End Sub Private Sub sub1(a()As Integer,k As Integer) Dim i As Integer Do a(k)=a(k)+a(k+1) j = j + 1 Loop While j < 2 End Sub 程序运行后,单击命令按钮,则窗体上显示的内容是A.0 3 7 5B.0 1 2 3C.3 2 4 5D.0 5 8 3

有过程如下:Sub fact (m As Integer, total As Long) Dim i As Integer total = 1 for i = 1 To m total = total*i Next iEnd Sub调用它的事件过程如下:Private Sub Command1_ Click () Dim tot As Long Dim a As Integer a = Val InputBox (“请输入数据”)) Call fact (a, tot) Print totEnd Sub则输入数据5,运行结果为 ______。A.100B.120C.200D.50

以下能够正确计算1+2+3+…+10的程序是A.Private Sub Command1_Click() Sum=0 ForI=1 To 10 Sum=Sum+I Next I Print Sum End SubB.Private Sub Command1_Click() Sum=0,I=1 Do While I<=10 Sum=Sum+I I=I+1 Print Sum End SubC.Private Sub Command1_Click() Sum=0: I=1 Do Sum=Sum+I I=I+1 Loop While I<10 Print Sum End SubD.Private Sub Command1_Click() Sum=0: I=1 Do Sum=Sum+I I=I+1 Loop Until I<10 Print Sum End Sub

单击命令按钮后,下列程序代码的执行结果是______。Public Sub fun (a As Integer, b As Integer, c As Integer)Doa=b+ cn=n+1Loop While n > 3End SubPrivate Sub command1_ click()Dim m As Integer, n As Integer, i As IntegerFor i = 0 To 2: m = n + 1: Next iFor i = 1 To 2: Call fun (m, n, i): Next iFor i = 0 To 3Print m;Next iEnd Sub

在窗体上画一个命令按钮,然后编写如下事件过程: Sub BTC(old Copy( ) As Integer,new Copy( ) As Integer) Dim i AS Integer For i=LBound(oldCopy( ))To UBound(oldCopy( )) newCopy(i)=oldCopy(i) Next i End Sub Private Sub Command1 _ Click( ) Dimm(10) As Integer,n(10)As Integer For i=1 To 10 m(i) =i*i Next i Call BTC(m,n) Print n(5) End Sub 程序运行后,单击命令按钮输出结果为A.0B.2C.10D.25

编写如下事件过程: Option Base 1 Private Sub Form Click() Dim x1()As Integer Dim i As Integer Dim s As Integer ReDim x1(3) For i = 1 To UBound(x1) x1(i)=i + 1 Next i Call sub1(x1) For i = 1 To UBound(x1) s = s + x1(i) Next i Print s End Sub Private Sub sub1(n()As Integer) Dim i As Integer ReDim Preserve n(5) For i = 3 To 5 n(i)=n(i-1)*2 Next i End Sub 程序运行后,单击窗体,则窗体上显示的内容是A.6B.12C.24D.47

以下能够正确计算n!的程序是______。A.Private Sub Commeadl_Click() n=5: x=1 Do x=x*i i=i+1 Loop While i<n Print x End SubB.Private Sub Command1_Click() n=5: x=1: i=1 Do x=x*i i=i+1 Loop While i<n Print x End SubC.Private Sub Command1_Click() n=5: x=1: i=1 Do x=x*i i=i+1 Loop Whilei<=n Print x End SubD.Private Sub Commsndl_Click() n=5: x=1: i=1 Do x=x*i i=i+1 Loop While i>n Print x End Sub

在窗体上画一个按钮,然后编写如下的事件代码。在按钮上单击,输出为( )。 Option Base 1 Private Sub fun (a()As Integer,n As Integer) For i=1 To 2 t=a(i):a(i)=a(5-i+1):a(5-i+1)=t Next i End Sub Private Sub Command1_Click() Dim arr1(5)As Integer For i=1 To 5 arr1(i)=i Next i Call fun(arr1,5) Print arr1(1);arr1(2) End SubA.1 2B.2 1C.5 4D.4 5

以下能够正确计算n!的程序是( )。A.Private Sub Commandl_C1ick()B.hiVate Sub Commandl_C1ick() n=5:x=1 n=5:x=1:i=1 DO DO X=x*1 X=X*1 i=i+1 i=i+1 Loop while i<n Loop While<n Print x Ptinte x End Sub End SubC.Private Sub Commandl_Click ()D.Pdvate Sub Commandl C1ick() n=5:X=1:i=1 n=5=:x=1:i=1 DO DO X=X*1 X=X*1 i=i+1 i=i+1 Loop While i>n Print x Print x End Sub End Sub

class Super {  public int i = 0;  public Super(String text) {  i = 1; }  }  public class Sub extends Super {  public Sub(String text) {  i = 2;  }   public static void main(String args[]) {  Sub sub = new Sub(“Hello”);  System.out.println(sub.i);  }  }  What is the result?()  A、 0B、 1C、 2D、 Compilation fails.

单选题class Super {  public int i = 0;  public Super(String text) {  i = 1; }  }  public class Sub extends Super {  public Sub(String text) {  i = 2;  }   public static void main(String args[]) {  Sub sub = new Sub(“Hello”);  System.out.println(sub.i);  }  }  What is the result?()A 0B 1C 2D Compilation fails.

单选题class super (   public int I = 0;   public super (string text) (   I = 1   )   )     public class sub extends super (   public sub (string text) (   i= 2   )   public static void main (straing args) (  sub sub = new sub (“Hello”);   system.out. PrintIn(sub.i);  )   )   What is the result?()A Compilation will fail.B Compilation will succeed and the program will print “0”C Compilation will succeed and the program will print “1”D Compilation will succeed and the program will print “2”