以下能够正确计算1+2+3+…+10的程序是A．Private Sub Command1_Click() Sum=0 ForI=1 To 10 Sum=Sum+I Next I Print Sum End SubB．Private Sub Command1_Click() Sum=0，I=1 Do While I＜=10 Sum=Sum+I I=I+1 Print Sum End SubC．Private Sub Command1_Click() Sum=0： I=1 Do Sum=Sum+I I=I+1 Loop While I＜10 Print Sum End SubD．Private Sub Command1_Click() Sum=0： I=1 Do Sum=Sum+I I=I+1 Loop Until I＜10 Print Sum End Sub
以下能够正确计算1+2+3+…+10的程序是
A．Private Sub Command1_Click() Sum=0 ForI=1 To 10 Sum=Sum+I Next I Print Sum End Sub
B．Private Sub Command1_Click() Sum=0，I=1 Do While I＜=10 Sum=Sum+I I=I+1 Print Sum End Sub
C．Private Sub Command1_Click() Sum=0： I=1 Do Sum=Sum+I I=I+1 Loop While I＜10 Print Sum End Sub
D．Private Sub Command1_Click() Sum=0： I=1 Do Sum=Sum+I I=I+1 Loop Until I＜10 Print Sum End Sub
相关考题：
以下能够正确计算1+2+3+…+10的程序是( )A.PrivateSubCommand1_Click()Sum=0ForC=1To10Sum=Sum+1NextCPrintSumEndSubB.PrivateSubCommand1_Click()Sum=0,C=1DoWhileC=10Sum=Sum+1C=C+1LoopPrintSumEndSubC.PrivateSubCommand1_Click()Sum=0;C=1DoSum=Sum+1C=C+1LoopWhileC10PrintSumEndSubD.PrivateSubCommand1_Click()Sum=0;C=1DoSum=Sum+1C=C+1LoopWhileC10PrintSumEndSub
已知程序段： sum=0For i=1 to 10 step 3sum=sum+ii=i*2Nexti当循环结束后，变量i、sum的值分别为（ ）。A.10、6B.13、6C.13、5D.10、5
以下能够正确计算1+2+3+…+10的程序是A．Private sub Command1_Click( ) sum=0 For 1=1 To 10 Sum=sum+1， Next I Print Sum End SubB．Private sub Command1_Click( ) Sum=0,I=1 Do While l＜=10 Sum=Sum+1 I=I+1 Print Sum End SubC．Private Sub command1_click( ) Sum=0：I=1 Do Sum=Sum+1 I=I+1 Loop While I＜10 Print Sum End SubD．Private Sub command1_Click( ) Sum=0：I=1 Do Sum=Sum+1 l=I+1 Loop Until I＜10 Print Sum End Sub
已知程序段：sum=0For i=1 to 10 step 3sum=sum+ii=i*2Next i当循环结束后，变量i、sum的值分别为( )。A．10、6B．13、6C．13、5D．10、5
若有以下程序段，sum和i都是整型变量，则不能与下面程序段等价的选项是（） sum=0; i=2; while（i＜=10) { sum=sum+i; i++; }A．for(i=2, sum=0; i＜=10; i++) sum+=i;B．sum=0; i=2; do{ sum=sum+i; i++; }while(i＜=10);C．sum=0; i=10; while(i＞1) { sum=sum+i; i--; }D．sum=0; i=11; do{ sum=sum+i; i--; }while(i＞1);
执行以下程序段，程序输出结果是（)。 int i=5, sum1=0; sum2=0; while（i＜=4) { sum1=sum1+i; i++; } do { sum2=sum2+i; i++; }while（i＜=4); printf（"sum1=%d, sum2=%dn",sum1, sum2);A．sum1=0, sum2=5B．sum1=0, sum2=0C．sum1=10, sum2=10D．sum1=4, sum2=0
下面程序可以正确求出1+2+3+。。。+n的和。（） #include ＜stdio.h＞ int main（) { int i = 1,sum = 0,n; scanf（“%d”,n); while （i ＜= n) sum = sum + i; ++i; printf（"sum=%d",sum); return 0; }
在下列程序段中，不能计算1到100之间奇数之和的是__________。A．Dim sum As Integer sum = 0 For i = 1 To 100 Step 2 sum = sum + i NextB．Dim sum As Integer sum = 0 For i = 1 To 100 If i Mod 2 ＜＞ 0 Then sum = sum + i NextC．Dim sum As Integer sum = 0 For i = 1 To 99 sum = sum + i NextD．Dim sum As Integer sum = 0 For i = 100 To 1 Step -1 If i Mod 2 ＜＞ 0 Then sum = sum + i Next