电路中，流进节点A的电流分别为I1、I2，流出节点A的电流为I3，据（）定律，可得节点A的电流为I1+I2=I3。A、基尔霍夫第二B、基尔霍夫第一C、电流D、电压
电路中，流进节点A的电流分别为I1、I2，流出节点A的电流为I3，据（）定律，可得节点A的电流为I1+I2=I3。
- A、基尔霍夫第二
- B、基尔霍夫第一
- C、电流
- D、电压
相关考题：
下面运行程序后，单击命令按钮，输出的结果是______。Private Sub Commandl_clck()Dim a%(1 To 4)，b%(3 To 6)，i%，s1，s2Fori=1 To 4a(i)=iNextiFor i=3 To 6b(i)=iNextis1=YAS(a)S2=YAS(b)Printt"s1="；S1"S2="；s2End Sub
执行下列的程序，消息框里显示的结果是______。Pfivate Sub Form_Click()Dim Str As StringStr＝""S="Access"For i＝Len(S) To 1 Step-1Str＝StrMid(S.i,1)Next IMsgBox StrEnd Sub
下列程序的执行结果为Private Sub Command1_Click（）Dim s1 As String, s2 As Strings1= "abcd"Call Transfer（s1, s2）Print s2End SubPrivate Sub Transfer （ByVal xstr As String, ystr As String）Dim tempstr As Stringi=Len（xstr）Do While i =1tempstr=tempstr + Mid（xstr, i, 1）i=i - 1Loopystr=te mpstrEnd Sub（ ）。A．dcbaB．abdcC．abcdD．dabc
单击窗体时，下列程序的执行结果是Private Sub Invert（ByVal xstr As String, ystr As String）Dim tempstr As StringDim I As IntegerI=Len（xstr）Do While I =1tempstr=tempstr + Mid（xstr, I, 1）I=I - 1Loopystr=tempstrEnd SubPrivate Sub Form_Click（）Dim s1 As String, s2 As Strings1= "abcdef"Invert s1, s2Print s2End Sub（ ）。A．abcdefB．afbecdC．fedcbaD．defabc
（8）下列这个Sub过程的功能是统计字符串中“a”的个数，请在空白处填上合适的代码，将程序补充完整。Private Sub numCount() Dim num As Integer s$="software And hardware" Num=Len(s$) For i=1 unm b$=。 If b$="a"Then x=x+1 Next i Print"x="；xEnd Sub
在窗体中添加一个名称为Com1的命令按钮，然后编写如下程序：Private Sub s(ByVal p As Integer)p=p*2End SubPrivate Sub Com1_Click()Dim i As Integeri=3Call s(i)If i＞4 Then i=i^2End sub窗体打开运行后，单击命令按钮，则消息框的输出结果为( )。
在窗体中添加—个名称为Command1的命令按钮，然后编写如下事件代码： Private Sub Command1_Click() s="ABBACDDCBA" For I=6 To 2 Step -2 x=Mid(s,I,I) y=Left(s,I) z=Right(s,I) z=x y z Next I MSgBox z End Sub 窗体打开运行后，单击命令按钮，则消息框的输出结果是______。A．AABAABB．ABBABAC．BABBAD．BBABBA
以下能够正确计算n!的程序是A．Private Sub Command1 Click() n=5：x=1 Do x=x * I I=I + 1 Loop While I ＜ n Print x End SubB．Private Sub Command1_Click() n=5：X=1：I=1 Do X=X*I I=I + 1 Loop While I ＜n Print x End SubC．Private Sub Command1_Click() n=5：X=1：I=1 Do X=X * I I=I + 1 Loop While I＜=n Print X End SubD．Private Sub Command1_Click() n=5：X=1：I=1 Do x=x * I I=I + 1 Loop While I＞n Print X End Sub
在窗体上画一个名称为Command1的命令按钮，然后编写如下事件过程： Prirate Sub Command1_Click() s = 0 For i=1 To 13 x = i * i-1 If x Mod 3 = 0 Then s = s + 1 Next i Print s End Sub 程序运行后，单击命令按钮，则窗体中显示的内容是A．1B．5C．27D．45
在窗体中添加一个名称为Command1的命令按钮，然后编写如下程序：Private Sub s(ByVal p As Integer)p=p*2End SubPrivate Sub Command1_click()Dim i As Integeri=3Call s(i)If i＞4 Then i=i^2MsgBox iEnd Sub窗体打开运行后，单击命令按钮，则消息框的输出结果为【 】。
编写如下事件过程： Private sub sub1 (ByVal x1 As String, y1 As String) Dim xt As String Dim i As Integer i = Len(x1) Do While i＞= 1 xt = xt + Mid(x1, i, 1) i=i-1 Loop y1 = xt End Sub Private Sub Form. Click() Dim s1 As String, s2 As String s1= "teacher" sub1 s1, s2 Print s2 End Sub 程序运行后，单击窗体，则窗体上显示的内容是A．rehcaetB．tahreeeC．themeeD．eerthea
下列程序运行后的输出结果是______。Private Sub f(k,s) s = 1 for j = 1 To k s=s*j Next jEnd SubPrivate Sub Command1_ Click () Sum = 0 for i = 1 To 3 Call f(i, s) Sum = Sum + s Next i Print Sum End SubA．0B．3C．6D．9
编写如下事件过程： Option Base 1 Private Sub Form Click() Dim x1()As Integer Dim i As Integer Dim s As Integer ReDim x1(3) For i = 1 To UBound(x1) x1(i)=i + 1 Next i Call sub1(x1) For i = 1 To UBound(x1) s = s + x1(i) Next i Print s End Sub Private Sub sub1(n()As Integer) Dim i As Integer ReDim Preserve n(5) For i = 3 To 5 n(i)=n(i-1)*2 Next i End Sub 程序运行后，单击窗体，则窗体上显示的内容是A．6B．12C．24D．47
单击窗体时，下列程序的执行结果是 Private Sub Invert(By Val xstr As String，ystr As String) Dim tempstr AS String Dim I AS Integer I=Len(xstr) Do While I＞=1 tempstr=tempstr + Mid(xstr，I，1) I=I - 1 Loop ystr=tempStr End Sub Private Sub Form_Click( ) Dim s1 As String，s2 As String S1="abcdef" Invert S1，S2 Print S2 End SubA．abcdefB．afbecdC．fedcbaD．defabc
下列程序的执行结果为 Private Sub Command1_C1ick( ) Dim sl As String，s2 AS String s1="abcdef" Call lnvert(s1，s2) Print s2 End Sub Private Sub lnvert(ByVal xstr As String，ystr As String) Dim tempstr As Stdng i=Len(xstr) Do While i＞=1 tempstr=tempstr+Mid(xstr，i，1) i=i-1 Loop ystr=tempstr End SubA．fedcbaB．abcdefC．afbecdD．defabc
运行下列程序：Private Sub Command1_Click( )Dim A(10) As IntegerFor i = 1 To 5A(i) = iA(i + 5) = iNext iFor i = 1 To 10s = s + A(i)Next iDebug.Print sEnd Sub单击按钮后，则在立即窗口内显示的结果是( )。A.5B.10C.30D.出错信息
单击一次命令按钮之后，在对话框中输入12，21，30，3，窗体中的输出结果为______。 Private Sub Command1_ Click() For i = 1 To 4 s = InputBox (“请输入”) Call per(i, s) Next i Print s End Sub Sub per(a, ByValB)b = 1 For i = 1 To 3 a = a * i Next i End SubA．12 21 30 3B．24 42 60 6C．3 30 21 12D．只能输入一个数
下列程序的执行结果为 Private Sub Command1_Click() Dim s1 As String，s2 As String S1；="abcdef" Call Invert(s1，s2) Print s2 End Sub Private Sub Invert (ByVal xstr As String，ystr As String) Dim tempstr As String i=Len(xstr) Do While i=1 tempstr=tempstr+Mid(xstr，i，1) i=i-1 Loop ystr=tempstr End SubA．fedcbaB．abcdefC．afbecdD．defabc
以下能够正确计算n!的程序是( )。A．Private Sub Commandl_C1ick()B．hiVate Sub Commandl_C1ick() n＝5:x＝1 n＝5:x=1:i＝1 DO DO X＝x*1 X＝X*1 i＝i＋1 i＝i＋1 Loop while i＜n Loop While＜n Print x Ptinte x End Sub End SubC．Private Sub Commandl_Click ()D．Pdvate Sub Commandl C1ick() n＝5:X＝1:i＝1 n＝5＝:x＝1:i＝1 DO DO X＝X*1 X＝X*1 i＝i＋1 i＝i＋1 Loop While i＞n Print x Print x End Sub End Sub
有如下程序： Private Sub Command1_Click( ) a$="A WORKER IS OVER THERE" x=Len(a ＄) For i=1 To x-1 b$=Mid $(a $，i，2) If b $="ER"Then s=s+1 Next i Pdnt s End Sub 程序运行后的输出结果是A．1B．2C．3D．4
下列程序运行后的输出结果是______。Private Sub f(k，s)s=1For j=1 To ks=s*jNextEnd SubPrivate Sub Command1_Click()Sum=0For i=1 To 3Call f(i，s)Sum=Sum+sNextPrint SumEnd Sub
9.程序执行结果s的值是 [9] 。Private Sub Commandl_Click()i = 0Doi = i + ls = i + sLoop Until i = 4Print sEnd Sub
class Super { public int i = 0； public Super（String text） { i = 1； } } public class Sub extends Super { public Sub（String text） { i = 2； } public static void main（String args[]） { Sub sub = new Sub（“Hello”）； System.out.println（sub.i）； } } What is the result？（） A、 0B、 1C、 2D、 Compilation fails.
单选题class Super { public int i = 0； public Super（String text） { i = 1； } } public class Sub extends Super { public Sub（String text） { i = 2； } public static void main（String args[]） { Sub sub = new Sub（“Hello”）； System.out.println（sub.i）； } } What is the result？（）A 0B 1C 2D Compilation fails.