配制I2标准溶液时,加入KI的目的是()。A、增大I2的溶解度,以降低I2的挥发性B、提高淀粉指示剂的灵敏度C、避免日光照射D、避免I2与空气的接触

配制I2标准溶液时,加入KI的目的是()。

  • A、增大I2的溶解度,以降低I2的挥发性
  • B、提高淀粉指示剂的灵敏度
  • C、避免日光照射
  • D、避免I2与空气的接触

相关考题:

有以下程序: Sub subP(b()As Integer) For i=1 To 4 b(i)=2*i Next i End Sub Private Sub Command1_Click() Dim a(1 To 4)As Integer a(i)=5 a(2)=6 a(3)=7 a(4)=8 subP a() For i=1 To 4 Print a(i) Next i End Sub 运行上面的程序,单击命令按钮,输出结果为______。A. 2 4 6 8B.5 6 7 8C.10 12 14 6D.出错

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阅读程序: Sub p( b () As Integer)For i =1To 4 b(i) = 2(iNext i End Sub Private Sub Command1_Click()Dim a (1 To 4) As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 call p (a) For i=1 To 4 Print a(i) Next iEnd Sub运行上面的程序,单击命令按钮,输出结果为。

配制I2标准溶液时,加入适量的碘化钾,目的是()A、防止I2被空气氧化B、使终点颜色变化更加敏锐C、增加I2的溶解度,减少挥发D、防止待测组分分解E、以上均非

配制I2标准溶液时,加入KI的目的是增大I2的溶解度以降低I2的挥发性和提高淀粉指示剂的灵敏度。() 此题为判断题(对,错)。

配制I2标准滴定溶液时,加入KI的目的是()。 A、增大I2的溶解度,以降低I2的挥发性B、提高淀粉指示剂的灵敏度C、避免日光照射D、避免I2与空气的接触

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下面程序段的运行结果是【 】。Option Base 1Private Sub Swap (a() As IntegFor I=1 to 10\2t=a(I)a(I)=a(10-I+1)a(10-I+1)=tNext IEnd SubPrivate Sub Form_Click()Dim x(10) As IntegerFor I=1 to 10x(I)=I*2Next ISwap x()For I=1 to 10Print x(I)Next IEnd Sub

以下程序的运行结果是( ) #define MAX 10 int a[MAX],i; main() { printf("\n");sub1();sub3(A) ,sub2(),sub3(A) ; } sub2() { int a[MAX],i,max; max=5; for(i=0;i<max;i++)a[i]=i; } sub1() {for(i=0;i<MAX;i++)a[i]=i+i; } sub3(int a[]) { int i; for(i=0;i<MAX,i++)printf("%d",a[i]); printf("\n"); }A.0 2 4 6 8 10 12 14 16 18 0 1 2 3 4B.0 1 2 3 4 0 2 4 6 8 10 12 14 16 18C.0 1 2 3 4 5 6 7 8 9 0 1 2 3 4D.0 2 4 6 8 10 12 14 16 18 0 2 4 6 8 10 12 14 16 18

设有如下程序: Private Sub search(a()As Variant,ByVal key As Variant,index%) Dim I% For I = Lbound(a)To Ubound(A)If key=a(I)Then index=I Exit Sub End If Next I index=-1 End Sub Private Sub Form_Load() Show Dim b()As Variant Dim n As Integer b=Array(21,64,92,15,72,38,45,72) Call search(b, 45, n) Print n End Sub 程序运行后,输出的结果是A.2B.6C.10D.12

下列程序的输出结果是【 】。Private Sub Command l Click()Dim a(1 TO 20)Dim iFor i=1 TO 20a(i)=iNext iFor Each i In a()a(i)=20Next iPrint a(2) End Sub

下列程序的输出结果是【 】。Private Sub Command1_Click()Dim a(1 To 20)Dim iFor i=1 To 20a(i)=iNext iFor Each i In a()a(i)=20Next iPrint a(2)End Sub

请阅读程序: Sub subP(b( )As Integer) For i=1 To4 b(i)=2*i Next i End Sub Private Sub Commandl Click( ) Dim a(1 To 4)As Integer a(1)=5:a(2)=6:a(3)=7:a(4)=8 subP a( ) For i=1 To 4 Print a(i) Next i End Sub 运行上面的程序,单击命令按钮,则输出结果是( )。A.2 4 6 8B.5 6 7 8C.10 12 14 16D.出错

在窗体上画一个名称为CoilTlilandl的命令按钮,然后编写如下事件过程: Private Sub command1 Click() Dim m As Integer, i As Integer, x(3)As Integer For i=0 To 3:x(i)=i:Next i For i = 1 To 2: Call sub1(x,i):Next i For i = 0 To 3: Print x(i);: Next i End Sub Private Sub sub1(a()As Integer,k As Integer) Dim i As Integer Do a(k)=a(k)+a(k+1) j = j + 1 Loop While j < 2 End Sub 程序运行后,单击命令按钮,则窗体上显示的内容是A.0 3 7 5B.0 1 2 3C.3 2 4 5D.0 5 8 3

配制I2标准溶液时,加入KI的目的是( )和( )。用间接碘量法测铜时,加入过量KI的作用是( ),( ),( )。

编写如下事件过程: Private sub sub1 (ByVal x1 As String, y1 As String) Dim xt As String Dim i As Integer i = Len(x1) Do While i>= 1 xt = xt + Mid(x1, i, 1) i=i-1 Loop y1 = xt End Sub Private Sub Form. Click() Dim s1 As String, s2 As String s1= "teacher" sub1 s1, s2 Print s2 End Sub 程序运行后,单击窗体,则窗体上显示的内容是A.rehcaetB.tahreeeC.themeeD.eerthea

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class Super {  public int i = 0;  public Super(String text) {  i = 1; }  }  public class Sub extends Super {  public Sub(String text) {  i = 2;  }   public static void main(String args[]) {  Sub sub = new Sub(“Hello”);  System.out.println(sub.i);  }  }  What is the result?()  A、 0B、 1C、 2D、 Compilation fails.

配制I2溶液时要滴加KI。

配制I2标准溶液时,加入KI的目的是增大I2溶解度以降低I2的挥发性和提高淀粉指示剂的灵敏度。

配制I2溶液时,加入固体KI,目的是为了(),增大I2的溶解度。A、增加盐效应B、利用同离子效应 C、降低水分子极性D、生成I3-离子

如何配制和保存I2溶液?配制I2溶液时为什么要滴加KI?

配制碘液加入KI的目的是()。

单选题class Super {  public int i = 0;  public Super(String text) {  i = 1; }  }  public class Sub extends Super {  public Sub(String text) {  i = 2;  }   public static void main(String args[]) {  Sub sub = new Sub(“Hello”);  System.out.println(sub.i);  }  }  What is the result?()A 0B 1C 2D Compilation fails.

单选题class super (   public int I = 0;   public super (string text) (   I = 1   )   )     public class sub extends super (   public sub (string text) (   i= 2   )   public static void main (straing args) (  sub sub = new sub (“Hello”);   system.out. PrintIn(sub.i);  )   )   What is the result?()A Compilation will fail.B Compilation will succeed and the program will print “0”C Compilation will succeed and the program will print “1”D Compilation will succeed and the program will print “2”