名词解释题机遇结点（chance point）
名词解释题
机遇结点（chance point）
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（ 29 ）有如下程序：#includeusing namespace std;class point {public:static int number;public:point （） {number++;～ point （） {number-;}};imt point::number=0;void main （） {point*ptr;printA,B;{point*ptr_point=new point{3};ptr=ptr_point;}pointC;coutPOINT::NUMBERENDL;delete[]ptr;}运行时输出的结果是A ） 3B ） 4C ） 6D ） 7
有如下程序:includeusing namespace std;class Point{public: static int number; 有如下程序：#include＜iostream＞using namespace std；class Point{public： static int number；public： Point(){number++；} ～Point(){number--；}}；int Point::number=0；void main(){ Point*ptr； Point A，B； { Point*ptr_point=new Point[3]； ptr=pb_point； } Point C cout＜＜Point::number＜＜endl； delete[]ptr； }运行时输出的结果是A．3B．4C．6D．7
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