填空题The complex form-function relationship is not a simplified, a one-to-one().

填空题
The complex form-function relationship is not a simplified, a one-to-one().

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有如下程序:#includeusing namespace std;class Complex{double re, im;public:Complex(double r, double i):re(r), im(i){}double real() const{return re;}double image() const{return im;}Complex operator +=(Complex a){re += a.re;im += a.im;return *this;}};ostream operator(ostream s,const Complex z){return s'('}int main(){Complex x(1, -2), y(2, 3);cout(x += y)return 0;}执行这个程序的输出结果是A . (1, -2)B . (2, 3)C . (3, 5)D . (3, 1)

有以下程序include using namespace std;class Complex{public: Complex(double r=O, 有以下程序 #include<iostream> using namespace std; class Complex { public: Complex(double r=O,double i=0):re(r),im(i){} double real() const {return re;} double imag()const {return im;} Complex operator +(Complex C) const {return Complex (re+c.re,im+c.im);} private: double re,im; }; int main() { Complex a=Complex(1,1)+Complex (5); cout<<a.real()<<'+'<<a.imag()<<'i'<<endl; retum 0; } 程序执行后的输出结果是A.6+6iB.6+1iC.1+6iD.1+1i

( 13 )有如下复数类的声明,请补充完整。class complex{double real; // 实部double imag; // 虚部public:complex(double x , double y){real=x;imag=y;}perator+(complex c){// 重载加法运算符 “ + ”return complex(___________)}};

有以下程序include using namespacestd;class Complex{public:Complex (doubler=0, d 有以下程序 #include <iostream> using namespace std; class Complex { public: Complex (double r=0, double i =0 :re(r) ,im (i) {} double real() const {return re;} double imag() const { return im;} Complex operator + (Complex c} const {return Complex(re+c.re, im+c.im);} privane: double re,im; }; int main { Complex a =Complex (1,1)+Complex(5); cout<<a.real()<<'+'<<a.imag() << 'i' <<endl return 0; } 程序执行后的输出结果是A.6+6iB.6+1iC.1+6iD.1+1i

有如下程序: include using namespace std; class Complex { double re, im, public 有如下程序: #include <iostream> using namespace std; class Complex { double re, im, public: Complex(double r, double i): re(r), im(i) {} double real() const {return re;} double image() const {return im,} Complex operator +=(Complex a) { re +=a.re; im +=a.im; return *this; } }; ostream operator << (ostream s, const Complex z) { return s<<'('<<z.real()<<','<<z.image()<<')'; } int main() { Complex x(1,-2), y(2,3); cout << (x+=y) << endl; return 0; } 执行这个程序的输出结果是( )。A.(1,-2)B.(2,3)C.(3,5)D.(3,1)

下面是复数类complex的定义,其中作为友元函数重载的运算符“--”的功能是将参数对象的实部减1,然后返回对该对象的引用;请补充完整。class complex{private:int real;int imag;public:complex(int r=0,int i=0):real(r),imag(i){}void show (){cout<<real<<(imag<0?"-":"+")<<imag<<'i';}______;};complex operator -- (complex c){c.real --;return c;}

有下列程序:includeusing namespace std;class Complex{double re,im;public:Complex 有下列程序: #include<iostream> using namespace std; class Complex { double re,im; public: Complex(double r,double i):re(r),im(i){} double real()const{retum re;} double image()const{return im;} Complex operator+=(Complex A) { rA.(1,-2)B.(2,3)C.(3,5)D.(3,1)

有以下程序:includeusing namespace std;class Complex{public:Complex(dOuble r=0,d 有以下程序: #include<iostream> using namespace std; class Complex { public: Complex(dOuble r=0,dOuble i=0):re(r),im(i){} doublereal()const{return re;} doubleimag()const{return im;} Complex operator+(Complex c)const {return ComplexA.6+6iB.6+1iC.1+6iD.1+1i

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名词解释题junctional complex

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