图示电路中,I1=10A,I2=4A,R1=R2=2Ω,R3=1Ω,电流源I2的电压是( )。 A. 8V B. 12V C. 16V D. 20V
图示电路中,I1=10A,I2=4A,R1=R2=2Ω,R3=1Ω,电流源I2的电压是( )。
A. 8V
B. 12V
C. 16V
D. 20V
B. 12V
C. 16V
D. 20V
参考解析
解析:设流过电阻R2上的电流为I3。根据基尔霍夫电流定律(KCL),I3=I1-I2=10-4=6A。根据基尔霍夫电压定律(KVL),I2R3+U=I3R2,即4×l+U=6×2,解得:U=8V。
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