air－conditioner is a word derived from adding –er to air－condition.() 此题为判断题(对，错)。
air－conditioner is a word derived from adding –er to air－condition.()
此题为判断题(对，错)。
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The room is a little small; _______ it is so hot. A.in additionB.in addition toC.additionalD.adding
综合局部ER图生成总体ER图过程中，下列说法错误的是()A、不同局部ER图中出现的相同实体，在总体ER图中只能出现一次B、在总体ER图中可以添加属于不同局部ER图实体间的联系C、在总体ER图中可以添加局部ER图中不存在的联系D、在总体ER图中不可以删除任何实体间的联系。
在下列横线处应添加的语句是( )。 class Base{public:void fun(){cout＜＜"Base::fun"＜＜end1;}}; class: Derived: public Base { public: void fun() { ______//显示调用基类的fun函数 cout＜＜"Derived::fun"＜＜end1; } };A．Derived::funB．Base::fun();C．Pubic::funD．fun();
有如下程序:includeusing namespace std;class Base{public:virtual void func1(){co 有如下程序: #include＜iostream＞ using namespace std; class Base{ public: virtual void func1(){cout＜＜"Base 1";} void rune2(){cout＜＜"Base 2";} }; class Derived:public Base{ public: void func1(){cout＜＜"Derived 1";} void func2(){cout＜＜"Derived 2";} }; int main(){ Base *p=new Derived; P-＞func1(); P-＞func2(); return 0: } 运行此程序,屏幕上将显示输出______。A．Derived 1 Base 2B．Base 1 Base 2C．Derived 1 Derived 2D．Base 1 Derived 2
Passage 1From James Moriarty to Ernst Stavro Blofeld, the idea of the evil genius has been a staple ofstorytelling．But is it true Or, to put the matter less starkly, is there a connection between creativityand dishonesty in real people who are not bent on world domination, as well as in fictionalsupervillains Writing in Psychological Science, Francesca Gino of Harvard University and ScottWiltermuth of the University of Southem California suggest that there is--and that cheating actuallyincreases creativity.Dr Gino and Dr Wiltermuth tested the honesty of 153 volunteers with a task that involvedadding up numbers for a cash reward, which was presented in a way that seemed to them to allowthem to cheat undetected(though the researchers knew when they did)．This was sandwichedbetween two tests for creativity, one of which was to work out how to fix a candle to a cardboardwall with a box of drawing pins, and the other a word-association test．This combination showed notonly that creative people cheat more, but also that cheating seems to encourage creativity--for thosewho cheated in the adding-up test were even better at word association than their candle-test resultspredicted.That result was confirmed by a second set of experiments, in which some people were givenmany opportunities to cheat and others few．The crucial predictor of creativity, the researchers con-firmed, was the actual amount of cheating, not any propensity to cheat.A third experiment tested the idea that this is because both creativity and dishonesty require, asit were, a flexible attitude to rules．In this experiment volunteers were asked about their attitude tobossy signs, such as "no cycling" and "no diving" notices, after being allowed to cheat (again, in away transparent to the experimenters) on a coin-tossing test．Cheats, it turned out, were less con-strained to obey such signs.It is, it goes without saying, a long way from such acts of petty defiance to building a lair insidean extinct volcano and threatening Washington from it--or even to non-fictional acts of seriouscrime．But some sort of link exists, so this research does indeed suggest that Arthur Conan Doyleand Ian Fleming were on to something.Which of the following describes the sequence of Dr Gino and Dr Wiltermuth′ s researchA.candle test, adding-up test, word association test.B.candle test, word association test, adding-up test.C.adding-up test, candle test, word association test.D.adding-up test, word association test, candle test.
The migratory birds use the same nests year after year,（ ）new material each time.A.and will addB.to addC.which are addedD.adding
设Derived类的基类是Base类，同时还包含了Component类的对象作为数据成员，在Derived类对象的构建过程中，三个不同类的构造函数的调用次序是A．Component类，Base类，Derived类B．Base类，Derived类，Component类C．Derived类，Component类，Base类D．Base类，Component类，Derived类
如有基类Base和派生类Derived,实例化对象Base b; Derived d;叙述正确的是:A．Derived* pDev = new Base();B．Derived类中不能定义与Base类同名的成员,以免引用时引起歧义;C．Base* pb =d ; Derived* pd = b; 为正确的赋值操作;D．Base rb = d; Base bb = d; 为正确的赋值操作;