Often,after I had told Walt or Larry what to do in a particular situation, I'd have_________ getting back to sleep. A. troubleB. pleasureC. hindranceD. time

Often,after I had told Walt or Larry what to do in a particular situation, I'd have_________ getting back to sleep.

A. trouble

B. pleasure

C. hindrance

D. time


相关考题:

I ________ her to marry me and she agreed. A. askB. askedC. told

Ted: I'm sorry. I damaged your mp3 player.Larry: __________A、Well,it's OK.B、No,it's all right.C、Oh,I'm sorry.D、What!

以下能正确计算1×2×3×4...×10的程序段是A.i=1; s=1; do { s=s*i; i++; } while(i<=10);B.do { i=1; s=1; s=s*i; i++; } while(i<=10);C.do { i=1; s=0; s=s*i; i++; } while(i<=10);D.i=1; s=0; do { s=s*i; i++; } while(i<=10);

以下程序段中,循环次数不超过10的是()A.int i=10; do{ i=i+1;} while(i<0);B.int i=5; do{ i+=1;} while(i>0);C.int i=1; do{ i+=2;} while(i!=10);D.int i=6; do{ i-=2;} while(i!=1);

以下能正确计算1+2+3+…+10的程序段是 。A.i=1; s=1; do {s=s+i; i++;} while (i<10);B.do {i=1;s=0; s=s+i; i++;} while (i<=10);C.do {i=1;s=1; s=s+i; i++;} while (i<=10);D.i=1,s=0; do {s=s+i; i++;} while (i<=10);E.i=1; s=1; do {s=s+i; i++;} while (i<=10);F.i=1,s=0; do {s=s+i; i++;} while (i<10);

7、以下能正确计算1×2×3×4...×10的程序段是A.i=1; s=1; do { s=s*i; i++; } while(i<=10);B.do { i=1; s=1; s=s*i; i++; } while(i<=10);C.do { i=1; s=0; s=s*i; i++; } while(i<=10);D.i=1; s=0; do { s=s*i; i++; } while(i<=10);

15、以下能正确计算1×2×3×4...×10的程序段是A.i=1; s=1; do { s=s*i; i++; } while(i<=10);B.do { i=1; s=1; s=s*i; i++; } while(i<=10);C.do { i=1; s=0; s=s*i; i++; } while(i<=10);D.i=1; s=0; do { s=s*i; i++; } while(i<=10);

以下能正确计算1×2×3×4...×10的程序段是A.i=1; s=1; do { s=s*i; i++; } while(i=10);B.do { i=1; s=1; s=s*i; i++; } while(i=10);C.do { i=1; s=0; s=s*i; i++; } while(i=10);D.i=1; s=0; do { s=s*i; i++; } while(i=10);

以下能正确计算10!的程序段是 。A.do {i=1;s=1;; s=s*i; i++; }while(i<=10);B.do{i=1;s=0 s=s*i; i++; while(i<=10);C.i=1;s=1; do{s=s*i; i++; }while(i<=10);D.i=1;s=0; do{s=s*i; i++; }while(i<=10);

以下能正确计算1×2×3×…×10的程序段是 。A.do {i=1;s=1; s=s*i; i++; } while(i<=10);B.do {i=1;s=0; s=s*i; i++; } while(i<=10);C.i=1;s=1; do {s=s*i; i++; } while(i<=10);D.i=1;s=0; do {s=s*i; i++; } while(i<=10);