It was the only way I could find the peace of _________ I needed to relax. A. mindB. heartC. soulD. spirit

It was the only way I could find the peace of _________ I needed to relax.

A. mind

B. heart

C. soul

D. spirit


相关考题:

I ()have been here, but I()not find the time.A. could; couldB. might; couldC. should; couldD. should; would

Come on through. I'm sorry your wife couldn't() it.A、comeB、makeC、meetD、find

阅读以下说明,回答问题1~4,将解答填入对应的解答栏内。[说明] 假设二叉树采用连接存储结构进行存储,root 指向根接点,p 所指结点为任一给定的结点,编写一个求从根结点到p所指结点之间路径的函数。void path (root, p)btree * root, * p;{Btree *stack[m0], *s;int tag[m0], top =0, i, find =0;s =root;do{while (s ! = NULL){stack [top] = s;tag[top] =0;((1))}if (top >0){((2))if (tag[top] = =1){if((3)){for (i=1; i< =top; i+ + printf ("%d" ,stack[i]- >data);find=1;}else top - -;}if((4)){p=p- >right;((5))}}} while (find || (s! = NULL top ! =0));}

有如下程序段#include "stdio.h"#include "string.h"#define N 10#define M 10char *find(char(*a)[M],int n){ char *q;int i; q=a[0]; for(i=0;in;i++) if(strcmp(a[i],q)0)q=a[i]; return q;}main(){ char s[N][M]={"tomeetme","you","and","he","china"}; char *p; int n=5; p=find(s,n); puts(p);}则执行后输出的结果为A.he B.and C.you D.tomeetme

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I__________have been there,but I__________not find the time.A.should;wouldB.should;couldC.might;couldD.could;could

非谓语动词形式填空练习: She returned home from the office,only ________ (find) the door open and something missing.