I couldn ’t tell _____ whether he had left or not. A. cheerfulB. for sureC. at easeD. in advance

I couldn ’t tell _____ whether he had left or not.

A. cheerful

B. for sure

C. at ease

D. in advance


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阅读下列C程序和程序说明,将应填入(n)处的字句写在对应栏内。【说明】下面是一个用C编写的快速排序算法。为了避免最坏情况,取基准记录pivot时,采用从left、right和mid=[(left+right)/2]中取中间值,并交换到right位置的办法。数组a存放待排序的一组记录,数据类型为T,left和right是待排序子区间的最左端点和最右端点。void quicksort (int a[], int left, int right) {int temp;if (left<right) {hat pivot = median3 (a, left, right); //三者取中子程序int i = left, j = right-1;for(;;){while (i <j a[i] < pivot) i++;while (i <j pivot < a[j]) j--;if(i<j){temp = a[i]; a[j] = a[i]; a[i] = temp;i++; j--;}else break;}if (a[i] > pivot){temp = a[i]; a[i] = a[right]; a[right] = temp;}quicksort( (1) ); //递归排序左子区间quieksort(a,i+1 ,right); //递归排序右子区间}}void median3 (int a[], int left, int right){ int mid=(2);int k = left;if(a[mid] < a[k])k = mid;if(a[high] < a[k]) k = high; //选最小记录int temp = a[k]; a[k] = a[left]; a[left] = temp; //最小者交换到 leftif(a[mid] < a[right]){temp=a[mid]; a[mid]=a[right]; a[right]=temp;}}消去第二个递归调用 quicksort (a,i+1,right)。 采用循环的办法:void quicksort (int a[], int left, int right) {int temp; int i,j;(3) {int pivot = median3(a, left, right); //三者取中子程序i = left; j = righi-1;for (;; ){while (i<j a[i] < pivot)i++;while (i<j pivot <a[j]) j--;if(i <j) {temp = a[i]; a[j]; = a[i]; a[i]=temp;i++; j--;}else break;}if(a[i]>pivot){(4);a[i]=pivot;}quicksoft ((5)); //递归排序左子区间left = i+1;}}

– Do you agree with me? -- ______________.A、No.B、I’m afraid not.C、I can’t.D、Not.