CH4分子中,存在着一个σ键和三个π键。

CH4分子中,存在着一个σ键和三个π键。


相关考题:

有如下事件过程:Private Sub Form_KeyDown(KeyCode As Integer,Shift As Integer)If (Button And 3) =3 ThenPrint "OK"End IfEnd Sub程序运行后,为了在窗体上输出“OK”,应当按下的鼠标键是A.左键B.右键C.同时按下左键和右键D.按什么键都不显示

窗体上有两个按钮,则执行程序后按键盘Cance1键的输出结果是 【7】 。Private Sub Command1_Click()Print "北京";End SubPrivate Sub Command2_Click()Print "南京";End SubPrivate Sub Form_Load()Command2.Cancel=TrueCommand1.Cancel=TrueEnd Sub

编写如下事件过程:Private Sub Form_MouseDown(Button As Integer, Shift As Integer, _X As Single, Y As Single)If Shift=6 And Button=2 ThenPrint "PC"End IfEnd Sub程序运行后,为了在窗体上输出"PC",应执行的操作为( )。A.同时按下Shift键和鼠标左键B.同时按下Ctrl,Alt键和鼠标右键C.同时按下Shift键和鼠标右键D.同时按下Ctrl,Alt键和鼠标左键

编写如下两个事件过程:Private Sub Form_KeyDown(KeyCode As Integer,Shift As Integer)Print Chr(KeyCode)End SubPrivate Sub Form_KeyPress(KeyAscii As Integer)Print Chr(KeyAscii)End Sub在一般情况下(即不按住"Shift"键和锁定大写键时)运行程序,如果按“A”键,则程序输出的结果是A.AAB.AaC.AaD.aa

( 33 )有一个名称为 Form1 的窗体,上面没有控件,设有以下程序(其中方法 Pset(X,Y) 的功能是在坐标X , Y 处画一个点):Dim cmdmave As BooleanPrivate Sub Form_MouseDown(Button As Integer,Shift As Integer, X As Single,Y As Single)cmdmave = TrueEnd SubPrivate Sub Form_MouseMove(Button As Integer,Shift As Integer, X As Single, Y As Single)If cmdmave ThenForm1.Pset(X,Y)End IfEnd SubPrivate Sub Form_MouseUp(Button As Integer, Shift As Integer, X As Single,Y As Single)cmdmave = FalseEnd Sub此程序的功能是A )每按下鼠标键一次,在鼠标所指位置画一个点B )按下鼠标键,则在鼠标所指位置画一个点;放开鼠标键,则此点消失C )不按鼠标键而拖动鼠标,则沿鼠标拖动的轨迹画一条线D )按下鼠标键并拖动鼠标,则沿鼠标拖动的轨迹画一条线,放开鼠标键则结束画线

把窗体的KeyPreview属性设置为Tree,然后编写如下事件过程 Private Sub Form_KeyPress(KeyAscii As Integer) Dim ch As String ch=Chr(KeyAscii) KeyAscii=Asc(UCase(ch)) Print Chr(KeyAscii+2) End Sub 程序运行后,按键盘上的“A”键,则在窗体上显示的内容是______。A. AB.BC.CD.D

把窗体的KeyPreview属性设置为True,然后编写如下事件过程Private Sub Form_KeyPress(KeyAscii As Integer)Dim ch As Stringch = Chr(KeyAscii)KeyAscii = Asc(UCase(ch))Print Chr(KeyAscii + 2)End Sub程序运行后,按键盘上的“A”键,则在窗体上显示的内容是( )。A.AB.BC.CD.D

编写如下事件过程:Private Sub Form_KeyDown(KeyCode As Integer,Shift As Integer)Print Chr(KeyCode)End SubPrivate SubForm_KeyPress(KeyAscii As Integer)Print Chr(KeyAscii)End Sub在一般情况下(即不按住“Shift”键和锁定大写键时) 运行程序,若按“T”键,则程序输出的结果是AA.T TB.t TC.T tD.t t

编写如下两个事件过程: Private Sub Form_KeyDown(KeyCode As Integer,Shift As Integer) Print Chr(KeyCode) End Sub Private Sub Form_KeyPress(KeyAscii As Integer) Print Chr(KeyAscii) End Sub 在一般情况下(即不按住“Shift”键和锁定大写键时)运行程序,如果按“A”键,则程序输出的结果是A. A AB.a AC. A aD.a a

编写如下事件过程:Private Sub Form_keyDown(KeyCode As Integer,Shift As Integer)Print Chr(KeyCode)End SubPrivate Sub Form_Keypress(KeyAscii As Integer)Print Chr(KeyAscii)End Sub在一般情况下(即不按住Shift键和锁定大写键时) 运行程序,若按"T"键,则程序输出的结果是A.T TB.t TC.T TD.t t

下列分子中C原子形成共价键时,原子轨道采取SP3杂化的是:() A、CO₂B、CH₂=CH₂C、CH≡CHD、CH4

编写如下事件过程; Private Sub Form_ MouseDown (Button As Integer, Shift As Integer, X As Single, Y As SinglE)If Shift = 6 And Button = 1 Then Print "BBBB" End If End Sub程序运行后,为了在窗体上输出 “BBBB”,应执行的操作为______。A.同时按下Shift 键和鼠标左键B.同时Ctrl、Alt 键和鼠标左键C.同时按下Shift 键和鼠标右键D.同时按下Ctrl、Alt 键和鼠标左键

在窗体上画一个名称为Text1的文本框,然后编写如下事件过程: Private Sub Text1_ KeyPress (KeyAscii As Integer) Dim ch As String ch = Chr (KeyAscii) KeyAscii = Asc (UCase(ch)) TextText = String(1, KeyAscii) End Sub程序运行后,使文本框拥有焦点,然后按键盘上的B键,则在文本框中显示的内容是 ______。A.bB.bbC.BBD.B

文本框Text1的KeyDown事件过程如下: Private Sub Text 1_KeyDown(KeyCode As Integer,Shift As Integer) … End Sub 其中参数KeyCode的值表示的是发生此事件时( )。A.是否按下了<Alt>键或<Ertl>键B.按下的是哪个数字键C.所按的键盘键的键码D.按下的是哪个鼠标键

编写了如下事件过程: Private Sub Form_MouseDown(KeyCode As Integer,Shift As Integer) If (Button And 3)=3 Then Print"AAAA" End If End Sub 程序运行后,为了在窗体上输出“AAAA”,应按下的鼠标键是A.左B.右C.同时按下左和右D.按什么键都不显示

若有以下变量和函数说明:includecharCh='*';void sub(int x,int y,char ch,double* 若有以下变量和函数说明: #include<iostream.h> charCh='*'; void sub(int x,int y,char ch,double*Z) { switch(ch) { case'+':*Z=x+y;break; case'-':*Z=x-y;break: case'*':*Z=x*y;break; case'/':*z=x/y;break: } } 以下合法的函数调用语句是( )。A.sub(10,20,Ch,y);B.sub(1.2+3,2*2,'+',Z);C.sub(sub(1,2,'+',y),sub(3,4'+',x),'-',y);D.sub(a,b,x,ch);

窗体上画一个名称为Text1的文本框,然后编写如下事件过程: Private Sub Form. Load() Show TextSetFocus End Sub Private Sub Text1_ KeyPress (KeyAscii As Integer) Dim ch As String ch = Chr (KeyAscii) KeyAscii = Asc(UCase(ch)) Pint Chr(KeyAscii + 4) End Sub程序运行后,在文本框中输入abcde,则在窗体上显示的内容是______。A.abcdeB.efghiC.EFGHID.ABCDE

编写如下事件过程: Private Sub Form_KeyDown (KeyCode As Integer,Shift As Integer) Print Chr(KeyCode) End Sub Private Sub Form_Key Press (KeyAscii As Integer) Print Chr (Key Ascii) End Sub 在一般情况下(即不按住Shift键和锁定大写键时)运行程序,若按“T”键,则程序输出的结果是A.T TB.t TC.T TD.t t

编写如下事件过程: Private Sub Form_ MouseDown (Button As Integer, Shift As Integer, X As Single, Y As Single) If Shift = 6 And Button = 2 Then Print “Hello” End If End Sub 程序运行后,为了在窗体上输出“Hello”,应在窗体上执行以下______ 操作。A.同时按下Shift键和鼠标左按钮.B.同时按下Shift键和鼠标右按钮C.同时按下Ctrl、Alt键和鼠标左按钮D.同时按下Ctrl、Alt键和鼠标右按钮

执行以下程序后输出的是。 Private Sub Commandl_Click ch$ = "ABCDEFGH": Print Mid(Right(ch$, 6), Len(Left(ch$, 4)), 2) End Sub A.CDEFGH B.ABCD C.FG D.AB

下面程序的输出结果是。 Private Sub Commandl_Click ch$=“ABCDEF” proc ch:Print ch End Sub Private Sub proc(ch As Stnng) s=“” For k=Len(ch) TO 1 Step -1 s=sMid(ch,k,1) Next k ch=s End Sub A.ABCDEF B.FEDCBA C.A D.F

有一个名称为Fom1的窗体,上面没有控件,设有以下程序(其中方法PSet(X,Y)的功能是在坐标X,Y处画一个点): Dim cmdmave As Boolean Private Sub Form_MouseDown(Button As Integer,Shift As Integer,X As Single,Y As Single) cmdmave=True End Sub Private Sub Form_MouseMove(Button AS Integer,Shift As Integer,X AS Single,Y As Single) If cmdmave Then Forml.PSet(X,Y) End lf End Sub Private Sub Form_MouseUp(Button As Integer,Shift As Integer,X As Single,Y As Single) cmdmave=False End Sub 此程序的功能是。 A.每按下鼠标键一次,在鼠标所指位置画一个点 B.按下鼠标键,则在鼠标所指位置画一个点;放开鼠标键,则此点消失 C.不按鼠标键而拖动鼠标,则沿鼠标拖动的轨迹画一条线 D.按下鼠标键并拖动鼠标,则沿鼠标拖动的轨迹画一条线,放开鼠标键则结束画线

在窗体上画了两个按钮控件Command1和Command2,有如下程序: Private Sub Command1_Click() Print "Visual"; End Sub Private Sub Command2_Click() Print "Basic"; End Sub Private Sub Form_Load() CommandCancel=True Command1.Cancel=True End Sub 执行程序后,按键盘Cancel键,在窗体上输出的结果是A.BasicB.VisualC.CancelD.True

N2分子中,存在着一个σ键和两个π键。

下列分子中,同时存在σ键和π键的是()。A、CH4B、HCIC、CI2D、N2

判断题在CH4分子中存在着σ键和π键。A对B错

单选题设有函数定义:void sub(int k,char ch){…}则以下对函数sub的调用语句中,正确的是(  )。Asub(1,97);Bsub(2,'97');Ch=sub(3,'a');Dsub(4,a);