I2(在水中的溶解度很小,试根据下列两个半反应: I2(s)+2e-←→ 2I- φ。= 0.535V I2/(aq)+2e-←→ 2I- φ。= 0.621V计算I2饱和溶液的溶解度
I2(在水中的溶解度很小,试根据下列两个半反应: I2(s)+2e-←→ 2I- φ。= 0.535V I2/(aq)+2e-←→ 2I- φ。= 0.621V 计算I2饱和溶液的溶解度
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下列程序的输出结果是______。Private Sub Command1_Click()Dim arr(1To 10)For i=1 To 10arr(i)=iNext iFor Each i In arr()arr(i)=arr(i)*2+1Next iMsgBox arr(7)End Sub
下列程序的执行结果为Private Sub Command1_Click()Dim s1 As String, s2 As Strings1= "abcd"Call Transfer(s1, s2)Print s2End SubPrivate Sub Transfer (ByVal xstr As String, ystr As String)Dim tempstr As Stringi=Len(xstr)Do While i =1tempstr=tempstr + Mid(xstr, i, 1)i=i - 1Loopystr=te mpstrEnd Sub( )。A.dcbaB.abdcC.abcdD.dabc
有以下程序: Sub subP(b()As Integer) For i=1 To 4 b(i)=2*i Next i End Sub Private Sub Command1_Click() Dim a(1 To 4)As Integer a(i)=5 a(2)=6 a(3)=7 a(4)=8 subP a() For i=1 To 4 Print a(i) Next i End Sub 运行上面的程序,单击命令按钮,输出结果为______。A. 2 4 6 8B.5 6 7 8C.10 12 14 6D.出错
有以下程序: Sub subP(b()As Integer) For i=1 To 4 b(i)=2*i Next i End Sub Private Sub Command1_Click() Dim a(1 To 4)As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 subPa() For i=1 To 4 Print a(i) Next i End Sub 运行上面的程序,单击命令按钮,输出结果为( )A.2 4 6 8B.5 6 7 8C.10 12 14 16D.出错
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下面程序的输出结果是【 】。Private Sub Commandl_Click( )Dim a(1 To 20)Dim iFori = 1 To 20a(i) = iNext iFor Each i In a( )a(i) = 20Next iPrint a(2)End Sub
以下程序的运行结果是( ) #define MAX 10 int a[MAX],i; main() { printf("\n");sub1();sub3(A) ,sub2(),sub3(A) ; } sub2() { int a[MAX],i,max; max=5; for(i=0;i<max;i++)a[i]=i; } sub1() {for(i=0;i<MAX;i++)a[i]=i+i; } sub3(int a[]) { int i; for(i=0;i<MAX,i++)printf("%d",a[i]); printf("\n"); }A.0 2 4 6 8 10 12 14 16 18 0 1 2 3 4B.0 1 2 3 4 0 2 4 6 8 10 12 14 16 18C.0 1 2 3 4 5 6 7 8 9 0 1 2 3 4D.0 2 4 6 8 10 12 14 16 18 0 2 4 6 8 10 12 14 16 18
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下列程序的输出结果是【 】。Private Sub Command1_Click()Dim a(1 To 20)Dim iFor i=1 To 20a(i)=iNext iFor Each i In a()a(i)=20Next iPrint a(2)End Sub
在窗体上画一个名称为CoilTlilandl的命令按钮,然后编写如下事件过程: Private Sub command1 Click() Dim m As Integer, i As Integer, x(3)As Integer For i=0 To 3:x(i)=i:Next i For i = 1 To 2: Call sub1(x,i):Next i For i = 0 To 3: Print x(i);: Next i End Sub Private Sub sub1(a()As Integer,k As Integer) Dim i As Integer Do a(k)=a(k)+a(k+1) j = j + 1 Loop While j < 2 End Sub 程序运行后,单击命令按钮,则窗体上显示的内容是A.0 3 7 5B.0 1 2 3C.3 2 4 5D.0 5 8 3
编写如下事件过程: Private sub sub1 (ByVal x1 As String, y1 As String) Dim xt As String Dim i As Integer i = Len(x1) Do While i>= 1 xt = xt + Mid(x1, i, 1) i=i-1 Loop y1 = xt End Sub Private Sub Form. Click() Dim s1 As String, s2 As String s1= "teacher" sub1 s1, s2 Print s2 End Sub 程序运行后,单击窗体,则窗体上显示的内容是A.rehcaetB.tahreeeC.themeeD.eerthea
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下列程序是将数组a的元素倒序交换,即第1个变为最后一个,第2个变为倒数第2个,完成下列程序。Private Sub Backward(a())Dim i As Integer,Tmp As IntegerFori=1 To5Tmp=a(i)a(5-i)=TmpNextiEnd Sub
有程序如下: Sub subP(b() As Integer) For i=1 To 4 b(i)=2*i Next i End Sub Private Sub Command1_Click() Dim a(1 To 4) As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 subP a() For i=1 To 4 Print a(i) Next i End Sub运行上面程序,单击命令按钮,输出结果为______ 。A. 2 4 6 8B.5 2 2 2C.10 12 14 16D.出错
某个窗体己编写下列事件过程。打开窗体运行后,单击窗体,消息框的输出结果为 ______。Pfivate Sub Form_Click()a=1i=1Do Until i10a=a+2i=i+3LoopMsgBox aEnd Sub
下列程序的输出结果是______。Private Sub Command1_Click()Dim arr(1 To 10)For i=l TO 10arr(i)=iNext iFor Each i In arr()art(i)=arr(i)*2+1Next iMsgBox arr(7)End Sub
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阅读程序: Sub subP(b()As Integer) For i=1 To 4 b(i)=2*i Next i End Sub Private Sub Command1_Click() Dim a(1 To 4)As Integer a (1)=5 a (2)=6 a (3)=7 a (4)=8 subP a() For i=1 To 4 Print a(i) Next i End Sub运行以上程序,单击命令按钮,输出结果为______ 。A.2 4 6 8B.5 6 7 8C.10 12 14 16D.出错
阅读程序 SUB P(B( ) AS INTEGER) FOR I=1 TO 4 B(I) =2*I NEXT I END SUB PRIVATE SUB COMMAND1_CLICK( ) DIM A( 1 TO 4) AS INTEGER A(1)=5 A(2) =6 A(3) =7 A(4) =8 P A( ) FOR I = 1 TO 4 MSGBOX A(I) NEXT I END SUB 运行上面的程序,单击命令按钮COMMAND1后,消息框4次输出的内容分别是( )。A.出错B.10, 12, 14, 16C.5, 6, 7, 8D.2, 4, 6, 8
class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?() A、 0B、 1C、 2D、 Compilation fails.
单选题class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?()A 0B 1C 2D Compilation fails.
单选题class super ( public int I = 0; public super (string text) ( I = 1 ) ) public class sub extends super ( public sub (string text) ( i= 2 ) public static void main (straing args) ( sub sub = new sub (“Hello”); system.out. PrintIn(sub.i); ) ) What is the result?()A Compilation will fail.B Compilation will succeed and the program will print “0”C Compilation will succeed and the program will print “1”D Compilation will succeed and the program will print “2”