What are two rulebase types within an IPS policy on an SRX Series device?() (Choose two.) A.rulebase-ipsB.rulebase-ignoreC.rulebase-idpD.rulebase-exempt

What are two rulebase types within an IPS policy on an SRX Series device?() (Choose two.)

A.rulebase-ips

B.rulebase-ignore

C.rulebase-idp

D.rulebase-exempt


相关考题:

以下程序段的输出结果为 ( )int j=2;switch(j){case 2:System.out.print("two.");case 2+1:System.out.println("three.");breakdefault:System.out.println("value is"+j);break;}A.two.three.B.two.C.three.D.value is 2

To enable the Database Smart Flash Cache, you configure the following parameters:DB_FLASH_CACHE_FILE = ‘/dev/flash_device_1’ , ‘/dev/flash_device_2’DB_FLASH_CACHE_SIZE=64GWhat is the result when you start up the database instance?()A. It results in an error because these parameter settings are invalid.B. One 64G flash cache file will be used.C. Two 64G flash cache files will be used.D. Two 32G flash cache files will be used.

TD-LTE系统小区选择算法是()A、Srx,s>0B、Rn>RsC、Srx,sD、SRX,S>THserving,high

以下程序段的输出结果为( )。 int j=2 switch (j){ Case 2: system.out.print("two."): Case 2+1: System.out.println("three."); break: default: System.out.println (“value is”+j): Break }A.B.twoA.two.three.B.twoC.threeD.value is 2

WhichofthefollowingareassociatedwiththeapplicationlayeroftheOSImodel?(two.)() A.pingB.TelnetC.FTPD.TCPE.IP

TD-LTE系统高优先级邻区小区重选算法包括()。 A.Srx,nTHx,highB.RnRsC.Srx,sTHserving,lowD.Srx,sTHserving,highE.Srx,sTHserving,high

TD-LTE系统小区选择算法是()A.Srx,s>0B.Rn>RsC.Srx,s<THserving,lowD.Srx,s>THserving,high

老伍按以下方式生成数据: import pandas as pd dt={'one':pd.Series([3,2,1],index=['c','b','a']), 'two':pd.Series([9,8,7,6],index=['a','b','c','d'])} d=pd.DataFrame(dt) c=d.index c=d.values c=d.columns c 请问输出结果为:A.Index(['a', 'b', 'c', 'd'], dtype='object')B.array([[ 1., 9.], [ 2., 8.], [ 3., 7.], [nan, 6.]])C.Index(['one', 'two'], dtype='object')D.信你个鬼,老伍这个糟老头子坏得很,没有输出!

老伍按以下方式生成数据: import pandas as pd dt={'one':pd.Series([3,2,1],index=['c','b','a']), 'two':pd.Series([9,8,7,6],index=['a','b','c','d'])} d=pd.DataFrame(dt) c=d.columns c=d.values c=d.index c 请问输出结果为:A.Index(['a', 'b', 'c', 'd'], dtype='object')B.array([[ 1., 9.], [ 2., 8.], [ 3., 7.], [nan, 6.]])C.Index(['one', 'two'], dtype='object')D.信你个鬼,老伍这个糟老头子坏得很,没有输出!