运行下述语句后,输出的结果是( )。 Option Base 1 Dim a i=1 a = Array(1,-2,9,0,-1,9) Do k = a(i) For m = 10 To k Step -2 n=k+m Next m Print n + m i=i+1 Loop While Abs(m + n)<>27A.3 27-8B.3-8 27C.-8 27 3D.-8 3 27

运行下述语句后,输出的结果是( )。 Option Base 1 Dim a i=1 a = Array(1,-2,9,0,-1,9) Do k = a(i) For m = 10 To k Step -2 n=k+m Next m Print n + m i=i+1 Loop While Abs(m + n)<>27

A.3 27-8

B.3-8 27

C.-8 27 3

D.-8 3 27


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(20)运行下列语句后,输出的结果是 Option Base 1 Dim a i=1 A=Array(1,-2,9,0,-1,9) Do K=a(i) For m=10 To k Step -2 Next m Print n+m i=i+1 Loop While Abs(m+n)27A.3 27 -8 B.3 -8 27 C.-8 27 3 D.-8 3 27

运行下列语句后,输出的结果是( )。Option Base 1Dim ai=1a=Array(1,-2,9,0,-1,9)Dok=a(i)For m=10 To k Step-2n=k+mNext mPrint n+mi=i+1Loop While Abs(m+n)<>27A.3 27-8B.3-8 27C.-8 27 3D.-8 3 27

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运行下列语句后,输出的结果是( )。 Option Base 1 Dim a i=1 a=Array(l, -2, 9, 0, -1, 9) Do k=a(i) For m = 10 To k Step -2 n=k+m Next m Print n+m i=i+1 Loop While Abs(m+n) <> 27A.3 27-8B.3-8 27C.-8 27 3D.-8 3 27

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运行下列语句后,输出的结果是( )。 Option Base 1 Dim a i=1 a=Array(1,-2,9,0,-1,9) Do k=a(i) For m=10 To k Srep -2 n=k+m Next m Print n+m i=i+1 Loop While Abs(m+n)<>27A.3 27-8B.3-8 27C.-8 27 3D.-8 3 27

有以下程序:inClUdeusingnamespacestd;ClassBase{public: Base(intx) {a=x; } voidsh 有以下程序: #inClUde <iostream> using namespace std; Class Base { public: Base(int x) { a=x; } void show() { cout<<a; } private: int a; }; class Derived : public Base { public: Derived(int i) :Base(i+1),b(i){} void Show() { cout<<b; } private: int b; }; int main() { Base b(5),*pb; Derived d(1); pb=d; pb->show(); return 0; } 运行后的输出结果是( )。A.1B.5C.2D.0