关于以下程序代码的说明正确的是( ) (1) class HasStatic{ (2) private static int x=100: (3) public static void main (String args[]{ (4) HasStatic hs1=new Has Static(); (5) hs1.x + +; (6) Has Static hs2=new HasStatic(); (7) hs2.x + +; (8) hs1=new HasStatic(); (9) hs1.x + +: (10) System.out.println("x="+ x); (11) } (12) }A.(5)行不能通过编译,因为引用了私有静态变量B.(10)行不能通过编译,因为x是私有静态变量C.程序通过编译,输出结果为:x=103D.程序通过编译,输出结果为:x=100

关于以下程序代码的说明正确的是( ) (1) class HasStatic{ (2) private static int x=100: (3) public static void main (String args[]{ (4) HasStatic hs1=new Has Static(); (5) hs1.x + +; (6) Has Static hs2=new HasStatic(); (7) hs2.x + +; (8) hs1=new HasStatic(); (9) hs1.x + +: (10) System.out.println("x="+ x); (11) } (12) }

A.(5)行不能通过编译,因为引用了私有静态变量

B.(10)行不能通过编译,因为x是私有静态变量

C.程序通过编译,输出结果为:x=103

D.程序通过编译,输出结果为:x=100


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关于以下程序代码的说明正确的是() 1.classHasStatic{ 2.privatestaticintx=100; 3.publicstaticvoidmain(Stringargs[]){ 4.HasStatichs1=newHasStatic(); 5.hs1.x ; 6.HasStatichs2=newHasStatic(); 7.hs2.x ; 8.hs1=newHasStatic(); 9.hs1.x ; 10.HasStatic.x--; 11.System.out.println(“x=” x); 12.} 13.}A.5行不能通过编译,因为引用了私有静态变量B.10行不能通过编译,因为x是私有静态变量C.程序通过编译,输出结果为:x=103D.程序通过编译,输出结果为:x=102

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以下程序输出结果为______。 include using namespace std; class TestClass 1 { publi 以下程序输出结果为______。include<iostream>using namespace std;class TestClass 1{public:TestClass1(){}TestClass1(int i){x1=i;}void dispa(){cout<<"x1="<<x1<<",";}private:int x1;}:class TestClass2:public TestClass1{public:TestClass2(){}TestClass2(int i):TestClass1(i+10){x2=i:}void dispb(){dispa();cout<<"x2="<<x2<<end1;}private:int x2:}:int main(){TestClass2 b(2):b.dispb();return 0;}

关于以下程序代码的说明正确的是 ( )(1)class HasStatic{(2)private static int x=100;(3)public static void main(String args[]){(4)HasStatic hs1=new HasStatic();(5)hs1.x++;(6)HasStatic hs2=new HasStatic();(7)hs2.x++;(8)hs1=new HasStatic();(9)hs1.x++;(10)System.out.println("x="+x);(11)}(12)}A.(5)行不能通过编译,因为引用了私有静态变量B.(10)行不能通过编译,因为x是私有静态变量C.程序通过编译,输出结果为:x=103D.程序通过编译,输出结果为:x=100

阅读以下说明和Java程序,填写程序中的空(1)~(6),将解答写入答题纸的对应栏内。【说明】以下Java代码实现一个简单绘图工具,绘制不同形状以及不同颜色的图形。部分接口、类及其关系如图5-1所示。【Java代码】interface?DrawCircle?{? //绘制圆形 public(1) ;}class?RedCircle?implements?DrawCircle?{? ?//绘制红色圆形???????public?void?drawCircle(int?radius,intx,?int?y)??{????????????System.out.println("Drawing?Circle[red,radius:"?+?radius?+",x:"?+?x?+?",y:"?+y+?"]");???????}}class?GreenCircle?implements?DrawCircle?{????//绘制绿色圆形??????public?void?drawCircle(int?radius,?int?x,int?y)?{???????????System.out.println("Drawing?Circle[green,radius:"?+radius+",x:?"?+x+?",y:?"?+y+?"]");??????}}abstract?class?Shape?{????//形状? protected? ? (2)???;? ? public?Shape(DrawCircle?drawCircle)?{? ?this.drawCircle=?drawCircle;? ? ? public?abstract?void?draw();}class?Circle?extends?Shape?{? //圆形? ?private?int?x,y,radius;? public?Circle(int?x,int?y,intradius,DrawCircle?drawCircle)?{? ?(3)???;? this.x?=?x;? ? ? this.y?=?y;? ?this.radius?=radius;? }? ? ?public?void?draw()?{? ? drawCircle.? ?(4)? ?;? ? ? }}public?class?DrawCircleMain?{? public?static?void?main(String[]?args)?{? Shape?redCircle=new?Circle(?100,100,10,? (5) );//绘制红色圆形? Shape?greenCircle=new?Circle(200,200,10,(6) );//绘制绿色圆形? ?redCircle.draw(); greenCircle.draw();? ?}}

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2、下面代码的输出结果是‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪‪ x=12.34 print(type(x))A.<class 'int'>B.<class 'bool'>C.<class 'complex'>D.<class 'float'>

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