BookStore数据库中有销售明细表OrderDetail(OrderCode,BookCode,Amount)查询销售总量前20%的图书,并按总销量降序排列。SQL语句:SELECT TOP 20 PERCENT Bookcode As书号,SUM(Amount)As总销量ROMOrderDetail GROUP BY Book code ORDER BY()A、AmountDESCB、SUM(Amount)DESCC、COUNT(Amount)DESCD、ADD(Amount)DESC
BookStore数据库中有销售明细表OrderDetail(OrderCode,BookCode,Amount)查询销售总量前20%的图书,并按总销量降序排列。SQL语句:SELECT TOP 20 PERCENT Bookcode As书号,SUM(Amount)As总销量ROMOrderDetail GROUP BY Book code ORDER BY()
- A、AmountDESC
- B、SUM(Amount)DESC
- C、COUNT(Amount)DESC
- D、ADD(Amount)DESC
相关考题:
假设每个歌手的“最后得分”的计算方法是:去掉一个最高分和一个最低分,取剩下分数的平均分。根据“评分”表求每个歌手的“最后得分”并存储于表TEMP中,表 TEMP中有两个字段:“歌手号”和“最后得分”,并且按最后得分降序排列,生成表 TEMP的SQL语句是 ______。A.SELECT歌手号,(COUNT(分数)-MAX(分数)-MIN(分数)/SUM(*)-2)最后得分; FROM评分INTO DBF TEMP GROUP BY歌手号ORDER BY最后得分DESCB.SELECT歌手号,(COUNT(分数)-MAX(分数)-MIN(分数)/(SUM(*)-2)最后得分; FROM评分INTO DBF TEMP GROUP BY评委号ORDER BY最后得分DESCC.SELECT歌手号,(SUM(分数)-MAX(分数)-MIN(分数)/COUNT(*)-2)最后得分; FROM评分INTO DBF TEMP GROUP BY评委号ORDER BY最后得分DESCD.SELECT歌手号,(SUM(分数)-MAX(分数)-MIN(分数)/COUNT(*)-2)最后得分; FROM评分INTO DBF TEMP GROUP BY歌手号ORDER BY最后得分DESC
检索选修四门以上课程的学生总成绩(不统计不及格的课程),并要求按总成绩降序排列出来,正确的SELECT语句是______。A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESCC.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVING COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESCD.DELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 ORDER BY 2 DESC CROUP BY S# HAVING COUNT(*)>=4
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deficit is the amount by which a sum of money falls short of the required or expected amount.()
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BookStore数据库中有图书表Book(BookCode,BookName,Author,PublisherCode,PublishTime查询作者名长度大于等于8的图书信息,显示书名(BookName)及作者(Author)。SQL语句:SELECTBookName,AuthorFROMBookWHERELenth(Author)=8
BookStore数据库中有图书表Book(BookCode,BookName,Author,PublisherCode,PublishTime,PublishTime是datetime类型。查询Book表中的图书类别(BookSort),要求每个类别只显示一次。SQL语句:SELECT()BookSort FROM BookA、DISTINCTB、ONLYC、ONED、PERCENT
BookStore数据库中有图书表Book(BookCode,BookName,Author,PublisherCode,PublishTime查询图书名称(BookName)含有“程序”的图书信息。SQL语句:SELECTBookCode,BookName,Author,Price,DiscountFROMBookWHEREName=“%程序%”
下列查询年龄最大的前四个学生(包括并列的情况)的语句,正确的是()。A、SELECT TOP 4 WITH TIES * FROM Student ORDER BY Sage ASCB、SELECT TOP 4 WITH TIES * FROM Student GROUP BY Sage ASCC、SELECT TOP 4 WITH TIES * FROM Student ORDER BY Sage DESCD、SELECT TOP 4 WITH TIES * FROM Student GROUP BY Sage DESC
在GZ表中选出职称为“工程师”的记录,并按年龄的降序排列,则实现的SQL语句为()A、SELECT FROM GZ for 职称=工程师 ORDER BY 年龄/DB、SELECT FROM GZ WHERE职称=工程师 ORDER BY 年龄 DESCC、SELECT * FROM GZ WHERE职称=‟工程师‟ ORDER BY 年龄 DESCD、SELECT * FROM GZ WHERE职称=‟工程师‟ ORDER ON 年龄 DESC
假设订单表orders用来存储订单信息,cid代表客户编号,money代表单次订购额,现要查询每个客户的订购次数和每个客户的订购总金额,下面()sql语句可以返回正确结果。A、select cid,count(distinct(cid)),sum(money) from orders group by cidB、select cid,count(distinct(cid)),sum(money) from orders order by cidC、select cid,count(cid),sum(money) from orders order by cidD、select cid,count(cid),sum(money) from orders group by cid
判断题BookStore数据库中有图书表Book(BookCode,BookName,Author,PublisherCode,PublishTime查询作者名长度大于等于8的图书信息,显示书名(BookName)及作者(Author)。SQL语句:SELECTBookName,AuthorFROMBookWHERELenth(Author)=8A对B错
判断题BookStore数据库中有图书表Book(BookCode,BookName,Author,PublisherCode,PublishTime查询图书名称(BookName)含有“程序”的图书信息。SQL语句:SELECTBookCode,BookName,Author,Price,DiscountFROMBookWHEREName=“%程序%”A对B错
多选题BookStore数据库中有销售明细表OrderDetail(OrderCode,BookCode,Amount)在OrderDetail表中添加一条记录:“08110801”、0701、3。SQL语句:()AINSERT INTOOrderDetail(OrderCode,Amount,BookCode)VALUES(‘08110801’,3,’0701’)BINSERT INTOOrderDetail(OrderCode,Amount,BookCode)VALUES(‘08110801’,’0701’,3)CINSERT INTOOrderDetail(OrderCode,BookCode,Amount)VALUES(‘08110801’,’0701’,3)DINSERT INTOOrderDetailVALUES(‘08110801’,’0701’,3)
单选题BookStore数据库中有图书表Book(BookCode,BookName,Author,PublisherCode,PublishTime,PublishTime是datetime类型。查询Book表中的图书类别(BookSort),要求每个类别只显示一次。SQL语句:SELECT()BookSort FROM BookADISTINCTBONLYCONEDPERCENT
单选题BookStore数据库中有销售明细表OrderDetail(OrderCode,BookCode,Amount)查询销售总量前20%的图书,并按总销量降序排列。SQL语句:SELECT TOP 20 PERCENT Bookcode As书号,SUM(Amount)As总销量ROMOrderDetail GROUP BY Book code ORDER BY()AAmountDESCBSUM(Amount)DESCCCOUNT(Amount)DESCDADD(Amount)DESC