请阐述状态空间的一般搜索过程。OPEN表与CLOSED表的作用是什么？
请阐述状态空间的一般搜索过程。OPEN表与CLOSED表的作用是什么？
相关考题：
阅读以下说明和C++代码。【说明】传输门是传输系统中的重要装置。传输门具有Open(打开)、Closed(关闭)、Opening (正在打开)、StayOpen(保持打开)和Closing(正在关闭)五种状态。触发传输门状态转换的事件有click、complete和timeout三种。事件与其相应的状态转换如下图所示。下面的C++代码1与C++代码2分别用两种不同的设计思路对传输门进行状态模拟，请填补代码中的空缺。【C++代码1】const int CLOSED=1； const int PENING=2；const int PEN=3； const int CLOSING=4；const int STAYOPEN=5； //定义状态变量，用不同整数表示不同状态class Door {Private：int state； //传输门当前状态void setState(int state){ this-＞state=state；} //设置当前状态public：Door()：state(CLOSED){}；void getState(){ //根据当前状态输出相应的字符串switch(state){case OPENING： cout＜＜"OPENING"＜＜endl； break；case CLOSED： cout＜＜"CLOSED"＜＜endl； break；case OPEN： cout＜＜"OPEN"＜＜endl； break；case CLOSING： cout＜＜"CLOSING"＜＜endl； break；case STAYOPEN：cout＜＜"STAYOPEN"＜＜endl； break；}};void click() { //发生click事件时进行状态转换if ((1)) setState(OPENING)；else if ((2)) setState(CLOSING)；else if ((3)) setState(STAYOPEN)；}void timeout(){ //发生timeout事件时进行状态转换if (state == OPEN) setState(CLOSING)；}void complete(){ //发生complete事件时进行状态转换if (state == OPENING) setState(OPEN)；else if (state == CLOSING) setState(CLOSED)；}};int main(){Door aDoor；aDoor.getState()；aDoor.click()； aDoor.getState()；aDoor.complete()；aDoor.getState()； aDoor.click()；aDoor.getState()；aDoor.click()； aDoor.getState()； return 0；}【C++代码2】class Door {public：DoorState *CLOSED，*OPENING，*OPEN，*CLOSING，*STAYOPEN，*state；Door()；virtual～Door(){……//释放申请的内存，此处代码省略)；void setState(DoorState *state) { this-＞state = state；}void getState(){//此处代码省略，本方法输出状态字符串，//例如，当前状态为CLOSED时，输出字符串为“CLOSED”}；void click()；void timeout()；void complete()；}；Door::Door(){CLOSED = new DoorClosed(this)； OPENING = new DoorOpening(this)；PEN = new DoorOpen(this)； CLOSING = new DoorClosing(this)；STAYOPEN = new DoorStayOpen(this)；state = CLOSED；}void Door :: click() {(4)；)void Door :: timeout() {(5)；)void Door :: complete() {(6)；}class DoorState//定义一个抽象的状态，它是所有状态类的基类{protected：Door *door；public：DoorState(Door *door) {this-＞door = door；}virtual～DoorState(void)；virtual void click() {}virtual void complete(
请认真阅读以下关于某传输系统的技术说明、状态转换图及C++代码，根据要求回答问题1和问题2。【说明】传输门是传输系统中的重要装置。传输门具有Open(打开)、Closed(关闭)、Opening(正在打开)、StayOpen(保持打开)和Closing(正在关闭)5种状态。触发状态的转换事件有click、complete和timeout 3种，事件与其相应的状态转换如图6-18所示。下面的【C++代码1】与【C++代码2】分别用两种不同的设计思路对传输门进行状态模拟，请填补代码段中的空缺语句。【C++代码1】const int CLOSED = 1; const int PENING = 2;const int PEN = 3; const int CLOSING = 4;const int STAYOPEN = 5; //定义状态变量，用不同整数表示不同状态class Door {private:private:int state; //传输门当前状态void setState(int state) { this-＞state = stale; } //设置当前状态public:Door () :state (CLOSED) { };void getState() { //根据当前状态输出相应的字符串switch(state) {case OPENING: cout ＜＜"OPENING" ＜＜ endl; break;case CLOSED: cout ＜＜ "CLOSED" ＜＜ endl; break;case OPEN: cout ＜＜ "OPEN" ＜＜ endl; break;case CLOSING: cout ＜＜ "CLOSING" ＜＜ endl; break;case STAYOPEN: cout ＜＜ "STAYOPEN" ＜＜ endl; break;}}void click() { //发生click事件时进行状态转换if ( (1) ) setState(OPENING);else if ( (2) ) setState(CLOSING);else if ( (3) ) setState(STAYOPEN);}void timeout() { //发生timeout事件时进行状态转换if (state == OPEN) setState(CLOSING);}void complete() { //发生complete事件时进行状态转换if (state == OPENING) setState(OPEN);else if (state == CLOSING) setState(CLOSED);}};int main(){Door aDoor;aDoor.getState(); aDoor.click(); aDoor.getState(); aDoor.complete();aDoor.getState(); aDoor.click(); aDoor.getState(); aDoor.click();aDoor.getState(); return 0;}【C++代码2】class Door {public:DoorState *CLOSED, *OPENING, *OPEN, *CLOSING, *STAYOPEN, *state;Door();virtual ～Door() { ... //释放申请的内存，此处代码省略};void s
单选题哪一个表空间不能切换为脱机状态（）A临时表空间TEMPB用户表空间USERC索引表空间INDEXD系统表空间SYSTEM