- You need to work with other colleagues to look after that. -() A、Oh, sorry to bother you.B、Thanks.I’m grateful for your suggestions.C、I’m not sure.

- You need to work with other colleagues to look after that. -()

A、Oh, sorry to bother you.

B、Thanks.I’m grateful for your suggestions.

C、I’m not sure.


相关考题:

Your little girl is becoming very rude. You ________ scold her. A.mayB.canC.ought toD.need

It was just in the room_____he was born_____he die. A、where, which.B、that, that.C、where, that.D、which, that.

May I take this book out of the reading room? No,you . You read it in here. ( )A. mightn’tB. won’tC. need’tD. mustn’t

Great changes have taken place in that school. It is no longer_ it was 20 years age_, it was so poorly equipped. A.what,whenB.that,whichC.what,whichD which, that.

Jim is one of the most popular ________ in my company. A.classmatesB. coachesC. citizensD. colleagues

I think we are friends ________colleagues. A.as well asB.as long asC.as good as

classWorkimplementsRunnable{Threadother;Work(Threadother){this.other=other;}publicvoidrun(){try{other.join();}catch(Exceptione){}System.out.print(afterjoin);}}classLaunch{publicstaticvoidmain(String[]args){newThread(newWork(Thread.currentThread())).start();System.out.print(afterstart);}}结果为:()A.afterjoinB.afterstartC.afterjoinafterstartD.afterstartafterjoin

针对下列程序段,需要( )个测试用例才可以满足语句覆盖的要求。switch(value){case 0:other=30;break;case 1:other=50;break;case 2:other=300;case 3:other=other/value;break;default:other=other*value;}A.2B.3C.4D.5

以下对于列表的相关操作中哪些项有正确的输出结果?A.>>> language = list('PHP'); >>> language[1:] = 'ython'; >>> print(language) ['P', 'y', 't', 'h', 'o', 'n']#B.>>> print(list('Life is short, you need Python.').count('is')) 1#C.>>> x = [2, 3, 0, 4, 1] >>> x.sort() >>> print(x) [0, 1, 2, 3, 4]#D.>>> words = ['Life', 'is', 'short', 'you', 'need', 'Python'] >>> words.index('you') 4

以下对于列表的相关操作中哪些项有正确的输出结果?A.>>> language = list('PHP'); >>> language[1:] = 'ython'; >>> print language ['P', 'y', 't', 'h', 'o', 'n']#B.>>> print list('Life is short, you need Python.').count('is') 1#C.>>> x = [2, 3, 0, 4, 1] >>> x.sort() >>> print x [0, 1, 2, 3, 4]#D.>>> words = ['Life', 'is', 'short', 'you', 'need', 'Python'] >>> words.index('you') 4