I’m expecting a letter____Jimmy. A.forB.fromC.withD.into
I’m expecting a letter____Jimmy.
A.for
B.from
C.with
D.into
相关考题：
Project work packages are typically decomposed into smaller components called activities to provide a basis for()scheduling, executing, and monitoring and controllingthe proj ect work. A.reviewingB.estimatingC.auditingD.expecting
Project work packages are typically decomposed into smaller components called activities to provide a basis for (72) ,scheduling, executing, and monitoring and controlling the project work.A．reviewingB．estimatingC．auditingD．expecting
● Project work packages are typically decomposed into smaller components called activities to provide a basis for （72）, scheduling, executing, and monitoring and controlling the project work.（72）A. reviewingB. estimatingC. auditingD. expecting
Project work packages are typicallydecomposed into smaller components called activities to provide a basis for （ ） , scheduling, executing, andmonitoring and controlling the project work. A.reviewing B.estimating C.auditing D.expecting
写出以下程序的运行结果： int main（) { int m,s,i; for（m=2;m＜10;m++) { s=0; for（i=1;i＜m;i++) if（（m%i)==0) s=s+i; if（s==m) printf（“%d”,m); } return 0; }
22、假设整型变量n,m,i已经声明和赋值，且大于n＞2.有如下运算规则:如果n是素数，m=0；否则，m=n。如下程序中正确实现此运算的是？A．m=n; for(i=2;i＜n;i++) if(n%i==0){ m=0;break; }B．m=0; for(i=2;i＜n;i++) if(n%i==0){ m=n;break; }C．m=0; for(i=2;i＜n;i++) if(n%i==0){ m=n;continue; }D．m=n; for(i=2;i＜n;i++) if(n%i==0){ m=0;continue; }
下面（）仅输出m的大于1的最小因子。A．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); break; }B．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); continue; }C．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); }D．i=2; while (m % i != 0) i++; printf("%d is 最小因子n", i);
下面（）是正确的判断素数程序（m＞1)。A．j=0; for (i =2; i＜=m-1; i++) if (m % i != 0) j++; if(j==m-2) printf(“%d是素数n", m);B．j=0; for (i =2; i＜=m-1; i++) if (m % i == 0) j++; if(j==0) printf(“%d是素数n", m);C．flag=0; for (i =2; i＜=m-1; i++) if (m % i == 0) flag=1; if(flag==0) printf(“%d是素数n", m);D．for (i =2; i＜=m-1; i++) if (m % i == 0) i=m+2; if(i==m+3) printf(“%d是素数n", m);
假设整型变量n,m,i已经声明和赋值，且大于n＞2.有如下运算规则:如果n是素数，m=0；否则，m=n。如下程序中正确实现此运算的是？A．m=n; for(i=2;i＜n;i++) if(n%i==0){ m=0;break; }B．m=0; for(i=2;i＜n;i++) if(n%i==0){ m=n;break; }C．m=0; for(i=2;i＜n;i++) if(n%i==0){ m=n;continue; }D．m=n; for(i=2;i＜n;i++) if(n%i==0){ m=0;continue; }