Washington’s decision to free slaves originated from his[A] moral considerations.[B] military experience.[C] financial conditions.[D] political stand.
Washington’s decision to free slaves originated from his
[A] moral considerations.
[B] military experience.
[C] financial conditions.
[D] political stand.
相关考题：
设rear是指向非空带头结点的循环单链表的尾指针，则删除起始结点的操作可表示为( )A．s=rear;B．rear=rear—＞next; rear=rear—＞next; free(rear); free(s);C．rear=rear—＞next—＞next;D．s=rear—＞next—＞next; free(rear); rear—＞next—＞next=s—＞next; free(s);
下列摩托罗拉Handover参数中,哪些是接收质量切换门限参数() A.decision_1_n5B.decision_1_p5C.decision_1_n6D.decision_1_p6E.decision_1_n7F.decision_1_p7
下列摩托罗拉Handover参数中,哪些是接收电平切换门限参数() A.decision_1_n5B.decision_1_p5C.decision_1_n6D.decision_1_p6E.decision_1_n7F.decision_1_p7
The steam machine________ industry _____ dependence on running water for the only way to transport big amount of goods.A. free; by B. helped; with C. departed; to D. liberated; from
在一单链表中，删除指针p所指的后继结点，以下语句正确的是（）。A．p-＞next=p-＞next-＞next; free(p-＞next);B．free(p-＞next);p-＞next=p-＞next-＞next;C．p=p-＞next;D．s=p-＞next;p-＞next=s-＞next;free(s);
在一单链表中，删除指针p所指的后继结点，以下语句正确的是（）A．s=p-＞next;p-＞next=s-＞next;free(s);B．p-＞next=p-＞next-＞next; free(p-＞next);C．free(p-＞next); p-＞next=p-＞next-＞next;D．p=p-＞next;
若不带头结点的链栈其栈顶指针为top，则删除栈顶元素，应进行如下（）操作。A．top=top-＞next; s=top; free(s);B．s=top; top=top-＞next; free(s);C．s=top-＞next; top-＞next=s-＞next;free(s);D．s=top; top-＞next=s-＞next;free(s);
设单循环链表中结点的结构为（data, next），且rear是指向非空的带表头结点的单循环链表的尾结点的指针。若想删除链表第一个结点，则应执行下列哪一个操作？A．s = rear；rear = rear-＞next；free（s）；B．rear = rear-＞next；free（rear）；C．rear = rear-＞next-＞next； free（rear）；D．s = rear-＞next-＞next；rear-＞next = s-＞next；free（s）；
设单循环链表中结点的结构为（data, next），且rear是指向非空的带头结点的单循环链表的尾结点的指针。若想删除链表的首元结点，则应执行的操作是（）。A．s = rear; rear = rear-＞next; free(s);B．s = rear-＞next; rear-＞next = s-＞next; free(s);C．s = rear-＞next-＞next; rear = rear-＞next-＞next; free(s);D．s = rear-＞next-＞next; rear-＞next-＞next = s-＞next; free(s);
在一个单链表中，若删除s所指结点的直接后继结点，则执行（)。A．p=s-＞next; s-＞next=p-＞next; free(p);B．p=s-＞next; free(p); s-＞next=s-＞next-＞next;C．s-＞next=s-＞next-＞next; free(s);D．s-＞next=s-＞next-＞next; p=s-＞next; free(p);