下面是求最大公约数的函数的首部Function gcd(ByVal x As Integer,ByVal y As Integer)As Integer若要输出8、12、16这3个数的最大公约数,下面正确的语句是A.Print ged(8,12),gcd(12,16),gcd(16,8)B.Print ged(8,12,16)C.Print gcd(8),gcd(12),gcd(16)D.Print gcd(8,gcd(12,16))

下面是求最大公约数的函数的首部Function gcd(ByVal x As Integer,ByVal y As Integer)As Integer若要输出8、12、16这3个数的最大公约数,下面正确的语句是

A.Print ged(8,12),gcd(12,16),gcd(16,8)

B.Print ged(8,12,16)

C.Print gcd(8),gcd(12),gcd(16)

D.Print gcd(8,gcd(12,16))


相关考题:

( 22 )下面是求最大公约数的函数的首部Function gcd ( ByVal x As Integer, ByVal y As Integer ) As Integer若要输出 8 、 12 、 16 这 3 个数的最大公约数,下面正确的语句是A ) Print gcd ( 8,12 ) , gcd ( 12,16 ) , gcd ( 16,8 )B ) Print gcd ( 8 , 12 , 16 )C ) Print gcd ( 8 ) , gcd ( 12 ) , gcd ( 16 )D ) Print gcd ( 8 , gcd ( 12,16 ))

以下所列的各函数首部中,正确的是A.void play(var :Integer,var b:Integer)B.void play(int a,b)C.void play(int a,int b)D.Sub play(a as integer,b as integer)

以下所列的各函数首部中,正确的是______。A.void play(var a:Integer,var b:Integer)B.void play(int a,b)C.void play(int a,int b)D.Sub play(a as integer,b as integer)

以下所列的各函数首部中,正确的是______。A.void play(var:Integer,var b:Integer)B.void play(int a,b)C.void play(int a,int b)D.Sub play(a as integer,b as integer)

求两数的最大公约数function gcd(a,b:integer):integer;

下面是求最大公约数的函数的首部: Function gcd(ByVal X As Integer,ByVal y As Integer)As Integer 若要输出8、12、16这3个数的最大公约数,下面正确的语句是( )。A.Print gcd(8,12),gcd(12,16),gcd(16,8)B.Print gcd(8,12,16)C.Print gcd(8),gcd(12),gcd(16)D.Print gcd(8,gcd(12,16))

下列各函数首部中,正确的是()。A.void play(var :Integer, var b:Integer)B.void play(int a, b)C.void play(int a, int b)D.Sub play(a as integer, b as integer)

下面是求最大公约数的函数的首部 Function gcd(ByVal x As Integer, ByVal y As Integer) As Integer 若要输出8、12、16这3个数的最大公约数,下面正确的语句是__________。A.Print gcd(8,12),gcd(12,16),gcd(16,8)B.Print gcd(8,12,16)C.Print gcd(8),gcd(12),gcd(16)D.Print gcd(8,gcd(12,16))

11、下面哪些定义是类型正确的?A.f :: (Integer, Integer) - Float f (x,y) = x / yB.f :: (Integer, Integer) - Float f (x,y) = (fromInteger x) / (fromInteger y)C.f :: (Integer, Integer) - Float f (x,y) = 3*x + yD.f :: (Integer, Integer) - Integer f (x, y) = 3*x + y