I need ( ) cloth, for I'm going to make ( ) clothes. A、many/ manyB、many/ a lot o{C、a lot of/ manyD、much/ much
I need ( ) cloth, for I'm going to make ( ) clothes.
A、many/ many
B、many/ a lot o{
C、a lot of/ many
D、much/ much
相关考题:
---- Shall we stay at home watching TV tonight?---- No, I’d like __________ and see a movie.A. to go B. go C. went D. going
–Do you ever play tennis?–_______.I have played a few times.I'd rather _____ jogging. A.Hardly ever ⋯goingB.Hardly ever ⋯goC.Hardly never ⋯goD.Hardly never ⋯going
下面()仅输出m的大于1的最小因子。A.for (i =2; i<=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); break; }B.for (i =2; i<=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); continue; }C.for (i =2; i<=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); }D.i=2; while (m % i != 0) i++; printf("%d is 最小因子n", i);
下面()是正确的判断素数程序(m>1)。A.j=0; for (i =2; i<=m-1; i++) if (m % i != 0) j++; if(j==m-2) printf(“%d是素数n", m);B.j=0; for (i =2; i<=m-1; i++) if (m % i == 0) j++; if(j==0) printf(“%d是素数n", m);C.flag=0; for (i =2; i<=m-1; i++) if (m % i == 0) flag=1; if(flag==0) printf(“%d是素数n", m);D.for (i =2; i<=m-1; i++) if (m % i == 0) i=m+2; if(i==m+3) printf(“%d是素数n", m);