Li Ming ________ English books on deck every morningA.readB.readedC.readsD.reading
Li Ming ________ English books on deck every morning
A.read
B.readed
C.reads
D.reading
相关考题：
By default, how often does a router running IGRP send its complete routing table to its neighbors?() A. Every 5 minutesB. Every 90 secondsC. Every 60 secondsD. Every 30 seconds
Each life jacket light that has a non-replaceable power source must be replaced ______．A.every 6 months after initial installationB.every 12 months after initial installationC.every 24 months after initial installationD.on or before the expiration date of the power source
When a wind force causes a floating ship to heel to a static angle，the ______．A.Centers of buoyancy and gravity are in the same vertical lineB.Righting moment equals the wind-heeling momentC.Downflooding point is below waterD.Deck-edge immersion occurs
Everybody on board was worried and we were curious to find out what had happened.A: wood B:meetingC:sign D:deck
30、如下程序的输出结果是 int main（) { char books[][20]={"English","Math","Physical"}; int i,j; for（i=0;i＜3;i++) { for（j=0;books[i][j]!=0;j++){ if（books[i][0]＜books[i][j]) books[i][0]= books[i][j]; } } printf（"%c",books[0][0]); return 0; }A．EB．sC．nD．h
选项（）可以实现下面有序列表的显示： 2.Toy Story 3.Aladdin 4.Hercules 5.101 DalmationsA．＜ol type="A" ＞ ＜li＞Toy Story＜/li＞ ＜li＞Aladdin＜/li＞ ＜li＞Hercules＜/li＞ ＜li＞101 Dalmations＜/li＞ ＜/ol＞B．＜ol type="1"＞ ＜li＞Toy Story＜/li＞ ＜li＞Aladdin＜/li＞ ＜li＞Hercules＜/li＞ ＜li＞101 Dalmations＜/li＞ ＜/ol＞C．＜ol type="1" start="2"＞ ＜li＞Toy Story＜/li＞ ＜li＞Aladdin＜/li＞ ＜li＞Hercules
选项（）可以实现下面有序列表的显示： .Toy Story .Aladdin .Hercules .101 DalmationsA.＜ul type="disc" ＞ ＜li＞Toy Story＜/li＞ ＜li＞Aladdin＜/li＞ ＜li＞Hercules＜/li＞ ＜li＞101 Dalmations＜/li＞ ＜/ul＞#B.＜ul type="circle" ＞ ＜li＞Toy Story＜/li＞ ＜li＞Aladdin＜/li＞ ＜li＞Hercules＜/li＞ ＜li＞101 Dalmations＜/li＞ ＜/ul＞#C.＜ul type="square" ＞ ＜li＞Toy Story＜/li＞ ＜li＞Aladdin＜/li＞ ＜li＞Hercul
29、如下程序的输出结果是 int main（) { char books[][20]={"English","Math","Physical"}; int i,j; for（i=0;i＜3;i++) { strcat（books[i],"book"); } printf（"%s",books[i-1][3]); return 0; }A．PhysicalbookB．sicalC．PhysicalD．sicalbook