单选题有以下程序#includemain(){ charc[2][5]={6938,8254},*p[2]; inti,j,s=0; for(i=0;i2;i++)  p[i]=c[i]; for(i=0;i2;i++)  for(j=0;p[i][j]0;j+=2)   s=10*s+p[i][j]-'0'; printf(%d,s);}程序运行后的输出结果是(  )。A9284B9824C6982D6385

单选题
有以下程序 #include  main() {  char c[2][5]={6938,8254},*p[2];  int i,j,s=0;  for(i=0;i<2;i++)   p[i]=c[i];  for(i=0;i<2;i++)   for(j=0;p[i][j]>0;j+=2)    s=10*s+p[i][j]-'0';  printf(%d,s); } 程序运行后的输出结果是(  )。
A

9284

B

9824

C

6982

D

6385


参考解析

解析:
p定义了两个字符串指针,p[0]指向c[0],p[1]指向c[1]。所以,p[i][j]等价于c[i][j],s = 10*s+ p[i][j]- '0',作用是把字符串p[i]转化成10进制数,注意到内层循环中j+=2,结果取c[0]中的第0个,第2个元素,取c[1]中的第0个,第2个元素。i=0时,输出63;i=1时,输出85。答案选择D选项。

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